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Class 9 Chemistry Kerala Syllabus for Students
The Class 9 Chemistry syllabus for the Kerala State Board typically includes:
1. Matter in Our Surroundings
- Properties of matter
- States of matter
- Changes in states of matter
2. Is Matter Around Us Pure
- Elements and compounds
- Mixtures (homogeneous and heterogeneous)
- Separation techniques
3. Atoms and Molecules
- Concept of atoms and molecules
- Symbols and formulae
- Atomic and molecular masses
4. Structure of the Atom
- Basic structure of the atom
- Electron, proton, neutron
- Atomic models
- Types of chemical reactions
- Balancing chemical equations
- Effects of chemical reactions
- Properties of acids and bases
- Indicators
- pH scale
- Preparation and uses of salts
- Properties and uses of metals and non-metals
- Reactivity series
- Corrosion and its prevention
8. Carbon and its Compounds
- Allotropes of carbon
- Organic compounds
- Simple organic reactions
This syllabus covers fundamental concepts and provides a foundation for understanding more complex chemical principles in higher classes.
Class 9 Chemistry Kerala Syllabus Objective for Students
The polymer obtained from monomers glycine and e amino caproic Acid is:
(A) Buna-S
(B) Dextron
(C) PHBV
(D) Nylon-2-nylon-6
Explanation: This question asks which type of polymer is formed when two specific monomers—glycine and ε-aminocaproic Acid—combine through polymerization. These monomers contain both amine (–NH₂) and carboxylic Acid (–COOH) functional groups, which are capable of reacting with each other.
Polymers formed from such bifunctional monomers typically undergo condensation reactions, where small molecules like water are eliminated during bond formation. This results in the creation of amide linkages (–CONH–), which are characteristic of a particular class of Polymers. These Polymers are known for their strong intermolecular hydrogen Bonding, leading to high tensile strength and durability.
When glycine and ε-aminocaproic Acid polymerize together, they form a copolymer consisting of repeating units derived from both monomers. The structure includes alternating segments, and the amide bonds formed contribute to the rigidity and stability of the chain. Such Polymers are commonly used in fibers and engineering materials due to their resilience.
Think of this process like linking small beads (monomers) with hooks on both ends. Each bead connects to another by releasing a tiny piece (like water), forming a long, strong chain. The repeating pattern depends on the types of beads used.
In summary, the polymer formed arises from condensation between amino and carboxyl groups, resulting in a strong, amide-linked structure composed of repeating units from both starting compounds.
Option d – Nylon-2-nylon-6
Polyacrylamide gel is used in ( Class 9 Chemistry Kerala mcq )
(A) Paints
(B) Electrophoresis
(C) Raincoats
(D) Gaskets
Explanation: This question focuses on identifying the application of polyacrylamide gel, a synthetic polymer widely used in laboratory and industrial settings. Polyacrylamide is formed by the polymerization of acrylamide units, creating a cross-linked Network that can trap and separate molecules based on size and charge.
One of its most important properties is its ability to form a stable, porous gel matrix. This matrix allows molecules like proteins or nucleic Acids to move through it at different speeds when an Electric Field is applied. The separation occurs because smaller molecules pass more easily through the pores, while larger ones move more slowly.
In biochemical and Molecular Biology techniques, this property is extremely useful for analyzing mixtures of Biomolecules. The gel acts as a medium where components can be distinguished and studied individually. The precision of separation depends on the concentration of the gel and the applied conditions.
A simple analogy is filtering sand and pebbles through a mesh—smaller particles pass quickly, while larger ones are delayed. Similarly, polyacrylamide gel acts as a Molecular sieve.
To summarize, this polymer is valued for its ability to form a controlled porous structure, making it ideal for separating and analyzing biological molecules in laboratory processes.
Option b – Electrophoresis
Bakelite is obtained from Phenol by reaction with:
(A) Ethanal
(B) Methanol
(C) Methanal
(D) Acetone
Explanation: This question explores the chemical reaction responsible for producing a well-known thermosetting polymer from Phenol. Phenol is an aromatic compound with a reactive hydroxyl group, which allows it to undergo condensation reactions with certain aldehydes.
In polymer Chemistry, when Phenol reacts with an aldehyde under controlled conditions, it forms a Network polymer through repeated condensation steps. These reactions involve the formation of methylene bridges linking Phenol rings, resulting in a rigid, cross-linked structure. The elimination of small molecules like water occurs during this process, which is characteristic of condensation polymerization.
The resulting polymer is highly durable, Heat-resistant, and electrically insulating. Due to its cross-linked nature, it does not soften upon heating, making it suitable for manufacturing electrical switches, handles, and casings.
Imagine building a three-dimensional scaffold using rigid blocks connected by strong links. Once the structure is formed, it cannot be reshaped easily, which explains its stability and resistance to Heat.
In summary, the polymer forms through condensation between Phenol and a reactive aldehyde, leading to a hard, cross-linked material with significant industrial applications.
Option c – Methanal
SBR is obtained from 75 parts of butadiene and 25 parts of styrene subjected to addition polymerization by the action of ( Class 9 Chemistry Kerala mcq )
(A) Hydrogen
(B) Sulphur
(C) Lithium
(D) Sodium
Explanation: This question deals with the formation of a synthetic rubber known as SBR through addition polymerization. The process involves combining two different monomers—butadiene and styrene—in specific proportions to produce a copolymer with desirable properties.
Addition polymerization typically requires an initiator that generates reactive species, such as free radicals, to begin the chain reaction. These radicals attack the double bonds present in the monomers, causing them to open and link together into long chains. The process continues in a chain-growth manner until termination occurs.
The presence of such an initiator is essential because it provides the energy needed to break bonds and create reactive intermediates. Without it, the monomers would remain unreacted under normal conditions.
Think of it like starting a domino effect. The initiator acts as the first push, causing a chain reaction where each monomer adds to the growing polymer chain.
In summary, the polymerization of butadiene and styrene requires a reactive agent that initiates free radical formation, enabling the formation of a synthetic rubber through addition polymerization.
Option d – Sodium
Chloroprene polymerizes rapidly in the presence of:
(A) Hydrogen
(B) Oxygen
(C) Helium
(D) Neon
Explanation: This question focuses on the conditions that accelerate the polymerization of chloroprene, a monomer used to produce synthetic rubber. Chloroprene contains a double bond, making it suitable for addition polymerization reactions.
Certain environmental factors or substances can influence the rate of polymerization. In particular, the presence of reactive species or conditions that generate free radicals can significantly speed up the process. These radicals initiate the breaking of double bonds and the formation of long polymer chains.
Chloroprene is especially sensitive to such conditions, and polymerization can occur rapidly when exposed to an Environment that facilitates radical formation. This behavior is important in industrial settings, where controlled polymerization is necessary to produce materials like neoprene.
An analogy would be how a spark can quickly ignite dry leaves—once initiated, the reaction spreads rapidly. Similarly, once polymerization begins, it proceeds quickly under favorable conditions.
In summary, chloroprene polymerizes efficiently when exposed to conditions that promote the formation of reactive intermediates, leading to rapid chain growth.
Option b – Oxygen
Vulcanization of neoprene takes place in the presence of ( Class 9 Chemistry Kerala mcq )
(A) Magnesium oxide
(B) Tritium oxide
(C) Vanadium oxide
(D) Polonium oxide
Explanation: This question examines the process of vulcanization in neoprene, a synthetic rubber. Vulcanization is a chemical treatment that improves the Mechanical Properties of rubber by introducing cross-links between polymer chains.
In the case of neoprene, this process does not rely on sulfur as in natural rubber. Instead, specific metal oxides are used to create cross-linking. These substances facilitate the formation of bridges between polymer chains, enhancing strength, elasticity, and resistance to Heat and chemicals.
The cross-linked structure prevents the polymer chains from sliding past each other easily, which increases durability and resilience. This makes vulcanized neoprene suitable for applications like gaskets, hoses, and insulation materials.
Think of it like tying multiple strands of rope together at various points—this makes the overall structure stronger and less likely to deform under stress.
In summary, vulcanization of neoprene involves chemical agents that create cross-links, transforming the material into a more stable and durable form.
Option a – Magnesium oxide
The Molecular formula of cellulose is:
(A) Cell-OH
(B) Cell-OR
(C) Cell-OAr
(D) Cell-SR
Explanation: This question relates to the general representation of cellulose, a natural polymer found in plant cell walls. Cellulose is composed of repeating glucose units linked together through glycosidic bonds.
Rather than having a simple Molecular formula like small molecules, Polymers like cellulose are represented using a repeating unit notation. This notation reflects the structure of the polymer chain, showing how each unit is connected and which functional groups are involved.
The repeating unit in cellulose includes hydroxyl groups (–OH), which play a crucial role in forming hydrogen bonds between chains. These interactions contribute to the strength and rigidity of cellulose fibers.
An easy way to visualize this is to think of a long chain made of identical building blocks, each with specific attachment points that allow them to connect and interact with neighboring chains.
In summary, cellulose is represented by a repeating unit structure that highlights its polymeric nature and the presence of functional groups responsible for its physical properties.
Option a – Cell-OH
Cellulose xanthate, when mixed with dilute NaOH, gives ( Class 9 Chemistry Kerala mcq )
(A) Viscose
(B) Acetate
(C) Tartarate
(D) Carboxylate
Explanation: This question deals with a step in the production of a regenerated cellulose material. Cellulose xanthate is an intermediate formed when cellulose reacts with certain chemicals during processing.
When this intermediate is treated with dilute sodium hydroxide solution, it forms a viscous liquid. This solution can be further processed to produce fibers or films. The transformation involves changes in the solubility and structure of the cellulose derivative.
This viscous solution is crucial in industrial applications because it can be extruded through fine openings to form threads or sheets, which then solidify into useful materials.
Imagine dissolving a thick paste that can be shaped into different forms before hardening. This flexibility allows for the creation of fibers and fabrics.
In summary, the treatment of cellulose xanthate with dilute alkali produces a viscous form that can be processed into regenerated cellulose products.
Option a – Viscose
PHBV is a:
(A) Polyether polymer
(B) Polyester polymer
(C) Polyamide polymer
(D) Polyhydroxyl polymer
Explanation: This question focuses on identifying the class of polymer to which PHBV belongs. PHBV is a biodegradable polymer produced by microorganisms and is composed of hydroxy Acid monomers.
These monomers are linked together through ester bonds, which are formed by the reaction between hydroxyl and carboxyl groups. Such linkages are characteristic of a specific category of Polymers known for their biodegradability and environmental friendliness.
The presence of ester bonds makes the polymer susceptible to hydrolysis, allowing it to break down naturally over time. This property makes it useful in medical and packaging applications where biodegradability is important.
Think of it like a chain made of links that can slowly break apart under natural conditions, returning to simpler substances.
In summary, PHBV is a polymer characterized by ester linkages between its repeating units, contributing to its biodegradable nature.
Option b – Polyester polymer
Which of the following is a natural polymer? ( Class 9 Chemistry Kerala mcq )
(A) poly (Butadiene-acrylonitrile)
(B) cis-1,4-polyisoprene
(C) poly (Butadiene-styrene)
(D) polybutadiene
Explanation: This question asks to identify a polymer that occurs naturally rather than being synthesized artificially. Natural Polymers are produced by Living Organisms and include substances like proteins, nucleic Acids, and natural rubber.
These Polymers are formed through biological processes and have specific structures and functions. For example, natural rubber consists of repeating isoprene units arranged in a particular configuration, giving it elasticity.
In contrast, synthetic Polymers are man-made and produced through chemical reactions in laboratories or industries. They may mimic natural Polymers but differ in origin and sometimes in structure.
A helpful analogy is comparing naturally grown cotton fibers with synthetic fibers like polyester. Both serve similar purposes, but their origins are different.
In summary, natural polymers are those formed in nature through biological processes and are not artificially manufactured.
Option b – cis-1,4-polyisoprene
The reaction between benzaldehyde and acetophenone in the presence of dilute NaOH is known as:
(A) Cross Aldol condensation
(B) Aldol condensation
(C) Cannizzaro’s reaction
(D) Cross Cannizzaro’s reaction
Explanation: This question involves identifying a specific Organic reaction between two different carbonyl compounds in the presence of a Base. When such compounds react under basic conditions, they can form larger molecules through carbon–carbon bond formation.
If one compound has no alpha hydrogen and the other does, the reaction proceeds in a particular way, leading to the formation of a mixed product. This type of reaction is a variation of a well-known condensation process.
The Base facilitates the formation of an enolate ion, which then attacks another carbonyl compound. This results in the formation of a new bond and eventually a more complex Molecule.
Think of it like combining two different puzzle pieces to form a larger structure, guided by a catalyst that enables the connection.
In summary, the reaction involves Base-catalyzed condensation between two different carbonyl compounds, leading to the formation of a new product through carbon–carbon bond formation.
Option a – Cross Aldol condensation
The mixture which shows positive deviation from Raoult’s law is ( Class 9 Chemistry Kerala mcq )
(A) Chloroethane + Bromoethane
(B) Ethanol + Acetone
(C) Benzene + Toluene
(D) Acetone + Chloroform
Explanation: This question deals with the concept of deviations from Raoult’s law in liquid mixtures. Raoult’s law assumes ideal behavior, where intermolecular forces between unlike molecules are similar to those between like molecules.
Positive deviation occurs when the आकर्षive forces between different components are weaker than those in the pure substances. As a result, molecules escape more easily into the vapor phase, increasing the vapor pressure above the expected value.
This typically happens when two liquids do not interact strongly, leading to less stable mixtures. The components tend to separate more easily compared to ideal solutions.
An analogy would be mixing oil and Alcohol—if they do not interact well, they tend to separate, indicating weaker intermolecular attraction.
In summary, positive deviation arises when intermolecular forces between different components are weaker, causing higher vapor pressure than predicted by ideal behavior.
Option b – Ethanol + Acetone
Which of the following sets of molecules will have zero dipole moment?
(A) Boron trifluoride, beryllium difluoride, carbon dioxide, 1,4-dichlorobenzene
(B) Ammonia, beryllium difluoride, water, 1,4 dichlorobenzene
(C) Boron trifluoride, hydrogen fluoride, carbon dioxide, 1,3-dichlorobenzene
(D) Nitrogen trifluoride, beryllium difluoride, water, 1,3-dichlorobenzene
Explanation: This question examines which group of molecules collectively exhibits zero dipole moment, meaning each Molecule has no NET polarity. A Molecule’s dipole moment depends on both bond polarity and Molecular geometry.
Even if bonds are polar, the overall dipole moment can be zero if the Molecule is symmetrical, allowing individual bond dipoles to cancel each other. Linear, trigonal planar, or highly symmetrical structures often show this behavior. In contrast, bent or pyramidal shapes usually result in a NET dipole due to uneven charge distribution.
To determine such molecules, one must analyze their geometry and check whether the Vector sum of bond dipoles equals zero. Molecules with identical surrounding atoms arranged symmetrically are more likely to meet this condition.
Imagine a tug-of-war where equal forces pull in opposite directions, resulting in no movement. Similarly, balanced dipoles cancel out.
In summary, zero dipole moment arises when Molecular symmetry ensures that individual bond polarities cancel, leading to a nonpolar overall structure.
Option a – Boron trifluoride, beryllium difluoride, carbon dioxide, 1,4-dichlorobenzene
Paper chromatography is an example of ( Class 9 Chemistry Kerala mcq )
(A) Column chromatography
(B) Adsorption chromatography
(C) Partition chromatography
(D) Thin-layer chromatography
Explanation: This question focuses on identifying the principle behind paper chromatography, a technique used to separate components of a mixture. Chromatography methods rely on differences in how substances distribute between two phases.
In this technique, a stationary phase (paper) and a mobile phase (solvent) are involved. The substances in the mixture travel along the paper at different rates depending on their solubility in the solvent and their interaction with the paper fibers.
The separation occurs because each component prefers one phase over the other to a different extent. Substances more soluble in the solvent move farther, while those interacting strongly with the paper remain closer to the starting point.
A simple analogy is how ink spreads on a wet tissue—different colors move at different speeds, separating from each other.
In summary, paper chromatography separates components based on their distribution between stationary and mobile phases, leading to effective separation of mixtures.
Option c – Partition chromatography
Chemically treated natural polymers are:
(A) Synthetic polymer
(B) Semi-synthetic polymer
(C) Fibres
(D) Thermosetting polymer
Explanation: This question asks about polymers that originate from natural sources but are chemically modified to improve their properties. Natural polymers like cellulose or rubber often undergo treatment to enhance durability, flexibility, or usability.
Such modifications involve chemical reactions that alter the structure without completely changing the मूल backbone of the polymer. The resulting material retains some characteristics of the original natural polymer while gaining improved features like increased strength or resistance.
These polymers are distinct from fully synthetic ones because their मूल source remains biological, even though they have been processed. They also differ from untreated natural polymers due to their enhanced performance.
An analogy would be polishing raw wood to make it stronger and more durable while still being wood at its core.
In summary, these polymers are derived from natural materials but chemically altered to improve properties, combining features of both natural and synthetic materials.
Option b – Semi-synthetic polymer
Polymers obtained in the laboratory by polymerization of simple chemicals are ( Class 9 Chemistry Kerala mcq )
(A) Elimination polymer
(B) Natural polymer
(C) Synthetic polymer
(D) Semisynthetic polymer
Explanation: This question deals with polymers that are created artificially through chemical processes in laboratories or industries. These polymers are formed by joining simple monomer units through reactions like addition or condensation polymerization.
Unlike natural polymers, which are produced by Living Organisms, these are designed and synthesized to meet specific needs. Their properties can be controlled by selecting appropriate monomers and reaction conditions.
Such polymers are widely used in everyday products, including plastics, fibers, and coatings. Their versatility and ease of production make them highly valuable in modern industries.
Think of it like assembling a custom-built structure using standard building blocks, where the design can be tailored according to requirements.
In summary, these polymers are man-made materials produced by chemically linking simple molecules to form large, useful structures.
Option c – Synthetic polymer
Thermosetting polymers are:
(A) Animal polymer
(B) Linear polymer
(C) Network polymer
(D) Branched polymer
Explanation: This question explores the nature of thermosetting polymers, which are a specific class of synthetic materials. These polymers form rigid, three-dimensional networks due to extensive cross-linking between chains.
Once formed, these materials cannot be softened or reshaped by heating. The strong covalent bonds between chains lock the structure in place, making them resistant to Heat and mechanical stress.
This property makes them suitable for applications requiring durability and thermal stability, such as electrical insulators and adhesives. However, their inability to be remolded limits recyclability.
An analogy is baking a cake—once it is baked and SET, it cannot return to its original batter form.
In summary, thermosetting polymers are highly cross-linked materials that become permanently rigid after formation and do not soften upon reheating.
Option c – Network polymer
The polymerization process complete with the formation of a dimer, trimer, etc. by condensation is ( Class 9 Chemistry Kerala mcq )
(A) Condensation polymers
(B) Addition polymers
(C) Chain growth polymerization
(D) Step growth polymerization
Explanation: This question refers to a polymerization mechanism where small units like dimers and trimers are formed step by step through condensation reactions. In this process, monomers combine with the elimination of small molecules such as water or Alcohol.
Unlike chain-growth polymerization, this method proceeds gradually, with molecules of similar size reacting with each other. The Molecular weight increases slowly as more units join together.
The formation of intermediates like dimers and trimers indicates that the reaction progresses in stages rather than through a continuous chain reaction. This type of polymerization is common in producing polyesters and polyamides.
Think of it like assembling a chain link by link, where small segments combine to form larger ones over time.
In summary, this process involves gradual growth through condensation, forming increasingly larger molecules from smaller units.
Option d – Step growth polymerization
The polymers which have two or more types of repeating units are called:
(A) Copolymer
(B) Homopolymer
(C) Addition polymers
(D) Condensation polymers
Explanation: This question focuses on polymers composed of more than one type of repeating unit. Such polymers are formed when two or more different monomers participate in the polymerization process.
The presence of multiple repeating units allows these polymers to exhibit a combination of properties from each monomer. This can lead to improved strength, flexibility, or chemical resistance compared to polymers made from a single monomer.
The arrangement of different units can vary—alternating, random, or block patterns—affecting the final properties of the material.
An analogy would be a chain made of different colored beads, where each color contributes unique characteristics to the overall design.
In summary, these polymers consist of multiple types of repeating units, resulting in materials with tailored and often enhanced properties.
Option a – Copolymer
The synthetic polymers that are not affected by microbes are called ( Class 9 Chemistry Kerala mcq )
(A) Biodegradable polymers
(B) Non-biodegradable polymers
(C) PHBV
(D) Nylon-2-nylon-6
Explanation: This question addresses polymers that resist degradation by microorganisms. Many synthetic polymers are designed to be stable and long-lasting, which makes them resistant to biological breakdown.
Microorganisms typically degrade materials by breaking chemical bonds using enzymes. However, certain polymers have structures that are not easily attacked by these enzymes, making them persistent in the Environment.
While this durability is useful for long-term applications, it also raises environmental concerns due to accumulation and Pollution.
A simple analogy is comparing biodegradable paper with plastic—paper decomposes easily, while plastic remains intact for long periods.
In summary, these polymers are resistant to microbial action due to their stable chemical structure, making them long-lasting but less environmentally friendly.
Option b – Non-biodegradable polymers
Select the initiator that generates free radicals:
(A) Acetyl peroxide
(B) Methyl Alcohol
(C) Isopropyl chloride
(D) Isopropyl amine
Explanation: This question involves identifying a substance that can initiate free radical polymerization. Initiators are compounds that decompose under certain conditions to produce highly reactive species known as free radicals.
These radicals start the polymerization process by attacking double bonds in monomers, creating a chain reaction. The effectiveness of an initiator depends on its ability to break into radicals easily under controlled conditions.
Such compounds often contain weak bonds that can be cleaved by Heat or Light, leading to the formation of radicals. These radicals then propagate the reaction by adding more monomer units.
Think of it like lighting a match to start a fire—the initiator provides the initial spark needed for the reaction to proceed.
In summary, an initiator is a compound that produces free radicals, triggering the chain reaction required for polymer formation.
Option a – Acetyl peroxide
The intermediate formed during chain growth polymerization is ( Class 9 Chemistry Kerala MCQ )
(A) Carbanion
(B) Carbocation
(C) Free radical
(D) Either ‘A’ or ‘B’
Explanation: This question focuses on the type of reactive species formed during chain growth polymerization. In such processes, the polymer chain grows rapidly through successive addition of monomers.
The key step involves the formation of a reactive intermediate that continues to add monomers. This intermediate can take different forms depending on the mechanism, such as free radicals, cations, or anions.
The nature of this intermediate determines the pathway and conditions required for polymerization. It is highly reactive and short-lived, continuously reacting until termination occurs.
An analogy is a relay runner passing a baton—the active site keeps transferring as the chain grows longer.
In summary, chain growth polymerization involves reactive intermediates that drive rapid addition of monomers, leading to the formation of long polymer chains.
Option c – Free radical
The functionality of polymer depends upon:
(A) Type of polymer
(B) Mass of polymer
(C) Size of polymer
(D) No. of Bonding sites in polymer
Explanation: This question explores what determines the functionality of a polymer, a term used to describe how many bonds a monomer can form during polymerization. Functionality is crucial because it influences the structure and properties of the resulting polymer.
In polymer chemistry, functionality refers to the number of reactive sites present in a monomer Molecule. These sites allow the monomer to connect with others, forming chains or networks. Monomers with two functional groups typically form linear polymers, while those with more than two can form branched or cross-linked structures.
The number of Bonding sites directly impacts properties such as strength, flexibility, and melting point. Higher functionality often leads to more complex, rigid structures due to increased cross-linking.
Think of it like connectors on building blocks—more connectors allow for more complex structures to be formed.
In summary, the functionality of a polymer is governed by the number of reactive Bonding sites in its monomer units, influencing the final structure and properties.
Option a – Type of polymer
Incorrect statement about branched chain polymers is ( Class 9 Chemistry Kerala MCQ )
(A) They have low density and melting point.
(B) They contain continuous chains.
(C) Their molecules are irregularly packed.
(D) They have branched side chains of different lengths.
Explanation: This question requires identifying an incorrect statement about branched chain polymers by understanding their structural characteristics. Branched polymers consist of a main chain with side chains attached at various points.
These side branches prevent the molecules from packing closely together, resulting in lower density and melting points compared to linear polymers. The irregular arrangement also reduces intermolecular forces, affecting mechanical strength.
However, branched polymers do not form continuous straight chains like linear polymers. Their structure is more irregular due to the presence of side chains of varying lengths.
An analogy would be comparing a straight rope to a tree with branches—the latter is more spread out and less compact.
In summary, branched polymers have irregular structures with side chains, leading to lower density and different physical properties compared to linear polymers.
Option b – They contain continuous chains
The polymer chains form fibers by:
(A) Cooling
(B) Chemical treatment
(C) Stretched by external force
(D) Hydrogen Bonding
Explanation: This question focuses on how polymer chains are converted into fibers. Fibers are formed when polymer chains are aligned in a specific direction, enhancing strength and flexibility.
The alignment is achieved by applying an external force that stretches the polymer material. This stretching causes the chains to orient parallel to each other, increasing intermolecular interactions such as hydrogen Bonding or van der Waals forces.
As a result, the material gains high tensile strength and becomes suitable for applications like textiles and ropes. Without this alignment, the polymer would remain weak and less organized.
A simple analogy is combing tangled hair into straight strands—alignment improves strength and uniformity.
In summary, fiber formation involves stretching polymer chains to align them, enhancing their Mechanical Properties and usability.
Option c – Stretched by external force
Polymers having intermolecular attractive forces between elastomers and fibers are ( Class 9 Chemistry Kerala MCQ )
(A) Synthetic polymers
(B) Plant polymers
(C) Thermoplastic polymers
(D) Thermosetting polymers
Explanation: This question deals with classifying polymers based on the strength of intermolecular forces. Polymers can be categorized into elastomers, fibers, and others depending on how strongly their chains interact.
Elastomers have weak intermolecular forces, making them flexible, while fibers have very strong forces, giving them high strength. Between these extremes are polymers with moderate intermolecular forces.
These intermediate polymers can soften on heating and be reshaped, showing properties between rigid fibers and elastic materials. Their structure allows some mobility while still maintaining reasonable strength.
An analogy would be comparing rubber bands (very flexible) and steel wires (very strong), with plastics falling somewhere in between.
In summary, such polymers have intermediate intermolecular forces, giving them balanced properties of flexibility and strength.
Option c – Thermoplastic polymers
The polymers which do not become soft on heating and cannot be remolded or recycled are:
(A) Fibers
(B) Elastomers
(C) Thermoplastic polymers
(D) Thermosetting polymers
Explanation: This question examines a class of polymers that remain rigid even when heated. These materials form strong cross-linked networks during their formation.
Once these cross-links are established, the structure becomes fixed and cannot be undone by reheating. As a result, these polymers do not melt or soften like others and cannot be reshaped or recycled easily.
Their rigidity and thermal stability make them useful in applications requiring durability and resistance to high temperatures, such as electrical components.
An analogy is a boiled egg—it cannot return to its liquid state once SET.
In summary, these polymers are highly cross-linked and permanently rigid, making them resistant to Heat and unsuitable for remolding.
Option d – Thermosetting polymers
Polymers having a Network or cross-linked chain polymers through strong covalent bonds are ( Class 9 Chemistry Kerala MCQ )
(A) Polypropylene
(B) Teflon
(C) Melamine
(D) Terylene
Explanation: This question focuses on identifying polymers with a three-dimensional Network structure formed by strong covalent bonds. Such polymers are created when monomers with multiple functional groups form extensive cross-links.
These cross-links connect different polymer chains, forming a rigid and stable Network. The resulting material has high mechanical strength, thermal resistance, and chemical stability.
Due to their structure, these polymers do not dissolve or melt easily. They are commonly used in applications requiring durability and resistance to deformation.
Imagine a fishing NET where each knot is tightly connected—this interconnected structure makes it strong and difficult to break.
In summary, these polymers consist of cross-linked networks formed by strong covalent bonds, resulting in highly stable and rigid materials.
Option c – Melamine
The Molecular Mass of an addition polymer is:
(A) Very low
(B) Equal to monomer
(C) Double the Mass of the monomer
(D) Equal to an integral multiple of monomer
Explanation: This question explores how the Molecular Mass of an addition polymer relates to its monomer units. In addition polymerization, monomers join together without the loss of any small molecules.
Each monomer adds directly to the growing chain, so the total Molecular Mass is the sum of all the repeating units. As the number of units increases, the molecular Mass becomes very large.
This process leads to polymers with high molecular weights, depending on the degree of polymerization. The relationship between monomer and polymer Mass is therefore directly proportional.
An analogy is stacking identical blocks—each block adds its full weight to the total.
In summary, the molecular Mass of an addition polymer is determined by the total number of monomer units linked together in the chain.
Option d – Equal to an integral multiple of monomer
Linear polymers have not ( Class 9 Chemistry Kerala MCQ )
(A) Low melting point
(B) High density
(C) High tensile strength
(D) Close-packed molecules
Explanation: This question requires identifying a property that linear polymers do not possess. Linear polymers consist of long, straight chains without branching.
Due to their structure, they can pack closely together, resulting in higher density and stronger intermolecular forces. This leads to higher tensile strength and relatively higher melting points.
Their ordered arrangement allows them to exhibit good Mechanical Properties. However, certain characteristics associated with loosely packed or branched structures are not present in linear polymers.
An analogy would be stacking straight rods neatly—they fit closely and form a compact structure.
In summary, linear polymers are closely packed and strong, lacking properties associated with loosely arranged or irregular structures.
Option a – Low melting point
The process in which monomeric units are added successively to form a polymer is called:
(A) Addition-elimination polymer
(B) Condensation polymerization
(C) Chain growth polymerization
(D) Step growth polymerization
Explanation: This question focuses on a polymerization process where monomers are added one by one to a growing chain. This type of mechanism is characteristic of chain-growth polymerization.
In this process, an active center is created, and monomers continuously add to this site, leading to rapid chain growth. The reaction proceeds through initiation, propagation, and termination steps.
Unlike step-growth polymerization, where molecules combine gradually, this process results in high molecular weight polymers early in the reaction.
Think of it like adding beads to a string one at a time, rapidly increasing the length.
In summary, this process involves successive addition of monomers to an ակտիվ chain, resulting in rapid formation of long polymer chains.
Option c – Chain growth polymerization
Polymers that have only one type of repeating unit are called ( Class 9 Chemistry Kerala MCQ )
(A) Heteropolymer
(B) Homopolymer
(C) Addition polymers
(D) Condensation polymer
Explanation: This question asks about polymers composed of a single type of repeating unit. These polymers are formed from only one kind of monomer.
Since all repeating units are identical, the structure is uniform throughout the chain. This uniformity often results in consistent physical and chemical properties.
Such polymers are simpler compared to those made from multiple monomers and are widely used in various applications due to their predictable behavior.
An analogy is a chain made entirely of identical links, giving it a regular and uniform appearance.
In summary, these polymers consist of only one type of repeating unit, resulting in a uniform and consistent structure.
Option b – Homopolymer
Polymers obtained by using different monomers are called:
(A) Animal polymers
(B) Plant polymers
(C) Heteropolymers
(D) Homopolymers
Explanation: This question focuses on polymers formed from more than one type of monomer. When different monomers combine during polymerization, the resulting polymer contains varied repeating units, giving it unique structural and functional properties.
Such polymers are designed to combine the advantages of different monomers, such as flexibility, strength, or chemical resistance. The arrangement of these units can be random, alternating, or in blocks, which further influences the final characteristics.
Because of this diversity, these polymers are widely used in applications where a balance of properties is required, such as synthetic rubbers and plastics.
Think of it like mixing different ingredients in a recipe to achieve a desired taste and texture.
In summary, these polymers are formed from multiple monomers, resulting in materials with combined and enhanced properties.
Option c – Heteropolymers
Biodegradable polymers ( Class 9 Chemistry Kerala MCQ )
(A) Have only ester linkage
(B) Addition polymers
(C) Co-polymers
(D) Ether linkage
Explanation: This question deals with polymers that can break down naturally in the Environment. Biodegradable polymers are designed to decompose through the action of microorganisms like bacteria and fungi.
Their structure typically includes bonds that can be hydrolyzed or enzymatically broken, such as ester linkages. This allows them to degrade into harmless substances like water and carbon dioxide over time.
These polymers are increasingly important in reducing environmental Pollution, especially in packaging and medical applications.
An analogy is Food waste decomposing naturally in soil, unlike plastic which persists for years.
In summary, biodegradable polymers are environmentally friendly materials that can be broken down naturally due to their chemical structure.
Option c – Co-polymers
Gutta Percha is:
(A) cis-1,4-polyisoprene
(B) trans-1,4-polyisoprene
(C) trans-1,2-polyisoprene
(D) cis-1,2-polyisoprene
Explanation: This question relates to identifying the structural form of a natural polymer derived from plant sources. Gutta percha is chemically similar to natural rubber but differs in the spatial arrangement of its repeating units.
The configuration of the polymer chains determines its physical properties. While one arrangement leads to elasticity, another results in a more rigid and less flexible material.
This difference arises from how the repeating units are oriented along the polymer chain, affecting how closely the chains can pack together.
An analogy is arranging identical sticks either aligned or staggered—different arrangements lead to different structural behaviors.
In summary, gutta percha is a naturally occurring polymer whose properties depend on the geometric arrangement of its repeating units.
Option b – trans-1,4-polyisoprene
Nylon-6,6 has a high molecular Mass range of ( Class 9 Chemistry Kerala MCQ )
(A) 12,000 u to 40,000 u
(B) 10,000 u to 50,000 u
(C) 12,000 u to 50,000 u
(D) 10,000 u to 48,000 u
Explanation: This question focuses on the typical molecular Mass range of a widely used synthetic polymer. Nylon-6,6 is formed through condensation polymerization involving diamine and dicarboxylic Acid monomers.
The molecular mass of such polymers depends on the number of repeating units in the chain. During polymerization, chains grow progressively longer, leading to high molecular weight materials.
Higher molecular mass contributes to improved Mechanical Properties such as strength, toughness, and resistance to wear. This is why such polymers are used in fibers and engineering plastics.
Think of it like linking many small units into a long chain—the longer the chain, the stronger and more durable it becomes.
In summary, nylon-6,6 consists of long chains formed through repeated condensation, resulting in a high molecular mass range.
Option c – 12,000 u to 50,000 u
In the chain propagation step of free radical polymerization:
(A) Polymer is formed
(B) Decarboxylation of fatty Acid
(C) Phenyl free radical is formed
(D) Larger free radical is formed
Explanation: This question examines what happens during the propagation stage of free radical polymerization. After initiation, a reactive free radical adds to a monomer, creating a new radical site.
This new radical continues to react with additional monomers, causing the chain to grow rapidly. Each step transfers the reactive site to the end of the growing chain, allowing continuous addition.
The process continues until termination occurs, either by combination or disproportionation of radicals.
An analogy is a relay race where the baton keeps moving forward, allowing the race to continue.
In summary, propagation involves the continuous growth of the polymer chain through repeated addition of monomers to an active radical site.
Option d – Larger free radical is formed
The molecular mass of natural rubber falls within the range of:
(A) 1,30,000 u to 3,40,000 u
(B) 1,35,000 u to 3,00,000 u
(C) 504 u to 100 u
(D) 50,000 u to 1,50,000 u
Explanation: This question addresses the molecular mass range of natural rubber, a polymer made from repeating isoprene units. The size of polymer molecules can vary widely depending on the number of repeating units.
Natural rubber typically has very long chains, resulting in high molecular mass. This contributes to its elasticity and mechanical strength, as long chains can stretch and return to their original shape.
The variability in chain length leads to a range of molecular masses rather than a single fixed value.
An analogy is comparing short and long rubber bands—the longer ones stretch more and have greater elasticity.
In summary, natural rubber consists of long polymer chains with a wide range of molecular masses, contributing to its elastic properties.
Option a – 1,30,000 u to 3,40,000 u
Artificial wool and blankets are obtained from:
(A) Acrilan
(B) PAN
(C) Orlon
(D) Either A, B, C
Explanation: This question focuses on synthetic fibers used as substitutes for natural wool. These materials are produced by polymerizing specific monomers to create fibers with properties similar to wool.
Such fibers are lightweight, warm, and resistant to moisture and chemicals. They are widely used in textiles due to their durability and ease of maintenance.
The polymer structure is designed to mimic the insulating properties of wool while offering additional advantages like resistance to moths and shrinkage.
Think of it like creating a synthetic version of a natural material that performs similarly but is more durable.
In summary, artificial wool is made from synthetic polymers engineered to replicate the properties of natural wool.
Option d – Either A, B, C
Vulcanized rubber contains cross-linking chains of:
(A) Styrene
(B) trans-1,4-polypropene
(C) cis-1,4-polyisopropene
(D) trans-1,4-polyisopropene
Explanation: This question deals with the structure of vulcanized rubber, which is formed by introducing cross-links between polymer chains. Natural rubber consists of long chains that can slide past each other.
During vulcanization, cross-links are formed between these chains, restricting their movement and improving strength and elasticity. The nature of the repeating units in the polymer remains important in determining the final properties.
These cross-links create a Network structure that enhances durability and resistance to deformation.
An analogy is tying knots between strands of thread to make the structure stronger and less flexible.
In summary, vulcanized rubber consists of cross-linked polymer chains, resulting in improved Mechanical Properties and stability.
Option c – cis-1,4-polyisopropene
LDP is a poor conductor of Electricity with a melting point of:
(A) 112°C
(B) 111°C
(C) 110°C
(D) 210°C
Explanation: This question examines a property of low-density polymer materials. Such polymers have branched structures, which prevent close packing of chains.
As a result, intermolecular forces are weaker, leading to lower melting points compared to more densely packed polymers. Their structure also limits the movement of electrons, making them poor conductors of Electricity.
These properties make them useful as insulating materials in electrical applications.
An analogy is loosely packed cotton, which is soft and melts or deforms easily compared to tightly packed materials.
In summary, low-density polymers have branched structures that result in lower melting points and poor electrical conductivity.
Option c – 110°C
The catalyst used in the preparation of HDP is:
(A) Ziegler-Natta
(B) Grignard’s reagent
(C) Reimer-Tieman
(D) Stephen
Explanation: This question focuses on the catalyst used in producing high-density polymer materials. The structure of such polymers depends heavily on the conditions and catalysts used during polymerization.
Specific catalysts allow the formation of linear chains with minimal branching. This leads to closely packed structures with higher density, strength, and melting points.
These catalysts control the orientation and growth of polymer chains, ensuring the desired properties in the final product.
An analogy is using a mold to shape a material precisely, ensuring uniformity and strength.
In summary, the preparation of high-density polymers involves catalysts that promote linear chain formation and controlled polymer growth.
Option a – Ziegler-Natta
Polymers used in non-stick cookware and gaskets are:
(A) Orlon
(B) Teflon
(C) Nylon-6
(D) Bakelite
Explanation: This question focuses on identifying polymers suitable for applications like non-stick cookware and gaskets. Such uses require materials that are chemically inert, Heat-resistant, and have very low friction.
These polymers possess strong bonds that are difficult to break, making them resistant to chemicals, Acids, and Bases. Their surface is non-reactive, preventing substances from sticking, which is why they are used in cookware coatings.
Additionally, their thermal stability allows them to withstand high temperatures without degrading. This combination of properties makes them ideal for both kitchen and industrial applications.
An analogy is a smooth, polished surface where nothing sticks easily, like water on a waxed surface.
In summary, these polymers are characterized by high chemical resistance, thermal stability, and non-stick properties, making them suitable for specialized applications.
Option b – Teflon
Acrylonitrile on polymerization gives:
(A) Orlon
(B) Terylene
(C) Teflon
(D) Neoprene
Explanation: This question deals with the product formed when acrylonitrile undergoes polymerization. Acrylonitrile contains a reactive double bond, allowing it to participate in addition polymerization.
During this process, monomer units link together to form long chains, resulting in a synthetic polymer. The presence of nitrile groups in the structure contributes to strength, chemical resistance, and thermal stability.
Such polymers are commonly used in making fibers and textiles due to their durability and resistance to wear.
Think of it like linking many identical units into a strong thread that can be woven into fabric.
In summary, polymerization of acrylonitrile produces a durable synthetic polymer widely used in fiber production.
Option a – Orlon
Natural rubber is which type of polymer?
(A) Addition
(B) Coordination
(C) Condensation
(D) Substitution
Explanation: This question asks about the classification of natural rubber based on its method of formation. Natural rubber is made from repeating isoprene units that join together through a specific polymerization mechanism.
In this process, monomers add directly to a growing chain without the elimination of small molecules. This results in long chains with repeating units, giving the material its elastic properties.
The structure and Bonding in natural rubber allow it to stretch and return to its original shape, making it highly useful in various applications.
An analogy is connecting identical links in a chain, where each link adds directly to the structure.
In summary, natural rubber is formed through a process where monomers add successively, creating long, flexible chains.
Option a – Addition
Balloons, tires, Surgeon’s gloves, and garden hoses are examples of:
(A) Bakelite
(B) Urea-formaldehyde
(C) Rubber
(D) Urea-melamine polymer
Explanation: This question focuses on identifying the type of material used in everyday elastic products. These items require materials that can stretch and return to their original shape.
Such materials have weak intermolecular forces and lightly cross-linked structures, allowing flexibility and elasticity. The polymer chains can move and rearrange under stress but return to their original positions once the stress is removed.
These properties make them ideal for applications requiring flexibility, durability, and resilience.
An analogy is a spring that stretches when pulled and returns to its original shape when released.
In summary, these products are made from flexible polymer materials that exhibit high elasticity and resilience.
Option c – Rubber
Latex obtained from rubber trees is in the form of:
(A) Aerosol
(B) Coarse suspension
(C) True solution
(D) Colloidal suspension
Explanation: This question deals with the physical nature of latex collected from rubber trees. Latex is not a true solution but consists of tiny polymer particles dispersed in water.
These particles are large enough to scatter Light but small enough to remain suspended without settling quickly. This type of mixture has properties intermediate between true solutions and suspensions.
The stability of latex is due to the presence of protective layers around the particles, preventing them from clumping together.
An analogy is milk, where fat droplets are dispersed in water, forming a stable mixture.
In summary, latex is a dispersed system with polymer particles suspended in a liquid medium, exhibiting characteristics of a colloidal system.
Option d – Colloidal suspension
Heating rubber with sulfur powder in the presence of zinc butyl xanthate at 150°C is called:
(A) Oxidation
(B) Galvanization
(C) Sulphonation
(D) Vulcanization
Explanation: This question examines a chemical process used to improve the properties of rubber. Heating rubber with sulfur leads to the formation of cross-links between polymer chains.
These cross-links restrict the movement of chains, increasing strength, elasticity, and resistance to wear and Heat. The presence of accelerators helps speed up the process and ensure uniform cross-linking.
This treatment transforms raw rubber into a more durable and useful material for industrial applications.
An analogy is tying knots between threads to make a fabric stronger and more stable.
In summary, this process involves heating rubber with additives to create cross-linked structures, enhancing its Mechanical Properties.
Option d – Vulcanization
The amount of hydrocarbon present in the Havea tree is:
(A) Very high (35%)
(B) Very low (0.5%)
(C) 5.5%
(D) 12.5%
Explanation: This question relates to the composition of latex obtained from rubber trees. Latex contains a mixture of water, proteins, and hydrocarbon polymers.
The hydrocarbon component mainly consists of polymer chains that give rubber its characteristic properties. However, latex is not composed entirely of Hydrocarbons; water makes up a significant portion.
Understanding this composition is important for processing and extracting usable rubber from the latex.
An analogy is fruit juice, which contains both water and dissolved substances, not just one component.
In summary, latex from rubber trees contains a moderate proportion of hydrocarbon polymer along with other components like water and proteins.
Option a – Very high (35%)
Which of the following is obtained by the polymerization of ethylene under high pressure (1000-2000 atm) and temperature (350-570 K) in the presence of peroxide?
(A) Low-density polythene
(B) High-density polythene
(C) PAN
(D) Bura-N
Explanation: This question focuses on the conditions required to produce a specific type of polymer from ethylene. Under high pressure and temperature, and in the presence of peroxide initiators, ethylene undergoes addition polymerization.
These conditions favor the formation of branched polymer chains, resulting in a material with lower density and different physical properties compared to linear forms.
The branching reduces packing efficiency, leading to lower melting point and increased flexibility.
An analogy is loosely stacking items, which creates more space and reduces overall density.
In summary, specific reaction conditions lead to the formation of a branched polymer with lower density and distinct properties.
Option a – Low-density polythene
The raw material used in the preparation of LDP is:
(A) Ethylene
(B) Ethyl chloride
(C) Ethylamine
(D) Ethanol
Explanation: This question asks about the starting material used to produce a low-density polymer. Such polymers are typically formed from simple hydrocarbon monomers containing double bonds.
These monomers undergo addition polymerization, linking together to form long chains. The structure of the monomer determines the properties of the resulting polymer.
The simplicity and availability of the monomer make it widely used in industrial polymer production.
An analogy is using identical building blocks to construct a larger structure.
In summary, the polymer is produced from a simple unsaturated hydrocarbon monomer through addition polymerization.
Option a – Ethylene
Which of the following bonds is very difficult to break and remains unaffected by corrosive alkali, Organic solvents?
(A) C-F
(B) Na – Cl
(C) K – Br
(D) K – OH
Explanation: This question examines the strength and stability of different chemical bonds. Some bonds are highly stable due to strong overlap between atoms and significant bond energy.
Such bonds are resistant to chemical attack by alkalis, Acids, and solvents. Their stability is due to the strong attraction between atoms and the difficulty in breaking the bond.
These properties are important in materials used in harsh chemical environments.
An analogy is a tightly locked chain that cannot be easily broken even under stress.
In summary, certain chemical bonds are extremely strong and resistant to chemical attack, making them highly stable in various conditions.
Option a – C-F
A cyclic ester formed by the intramolecular reaction of -OH group and -COOH group is called:
(A) Lactone
(B) Lactam
(C) Acetal
(D) Ketol
Explanation: This question focuses on a compound formed when a single Molecule containing both hydroxyl (–OH) and carboxylic Acid (–COOH) groups reacts within itself. Such intramolecular reactions lead to the formation of a ring structure.
When the –OH group reacts with the –COOH group of the same Molecule, a condensation reaction occurs with the elimination of water. This results in the formation of a cyclic compound containing an ester linkage.
These cyclic esters are commonly found in Organic Chemistry and are important intermediates in polymer and biochemical reactions. Their stability depends on ring size and strain.
An analogy is bending a flexible strip and joining its ends to form a loop.
In summary, this process involves intramolecular condensation forming a ring structure with an ester linkage.
Option a – Lactone
The polymer used for making tyre cords, fabrics, and ropes is:
(A) Nylon 6
(B) Melamine
(C) Bakelite
(D) Teflon
Explanation: This question examines the type of polymer suitable for making strong fibers like tyre cords and ropes. Such applications require materials with high tensile strength, durability, and resistance to wear.
These polymers typically have strong intermolecular forces, often due to hydrogen Bonding or closely packed chains. This alignment and interaction between chains give them high strength and stiffness.
They are processed into fibers by stretching, which aligns the chains and enhances their Mechanical Properties further.
An analogy is tightly twisting multiple threads to make a strong rope.
In summary, such polymers are characterized by strong intermolecular forces and aligned structures, making them ideal for high-strength fiber applications.
Option a – Nylon 6
Polyethylene terephthalate (PET) is a polymer of:
(A) Polyamide
(B) Polyester
(C) Polyether
(D) Polyhalide
Explanation: This question focuses on identifying the type of polymer based on its chemical structure. PET is formed through a condensation reaction between two different types of monomers, leading to the formation of ester linkages.
These ester bonds are created when a carboxylic Acid group reacts with an Alcohol group, eliminating a small Molecule during the process. The repeating units are connected through these ester linkages, forming a long chain.
Such polymers are widely used in packaging, especially in bottles and synthetic fibers, due to their strength and chemical resistance.
An analogy is linking units together with connectors that form stable bridges between them.
In summary, this polymer is formed through condensation reactions that create repeating ester linkages in the chain.
Option b – Polyester
Telephone instrument is obtained from:
(A) Animal polymer
(B) Plant polymer
(C) Bakelite
(D) Elastomers
Explanation: This question deals with the material used in making traditional telephone instruments. Such materials need to be durable, Heat-resistant, and good electrical insulators.
These properties are typically found in certain rigid, cross-linked polymers that do not soften upon heating. Their structure provides stability and resistance to electrical conduction, making them suitable for electrical applications.
They are commonly used in switches, plugs, and casings due to their insulating nature.
An analogy is a hard plastic shell that protects internal components and resists Heat.
In summary, such instruments are made from rigid, heat-resistant polymers with excellent insulating properties.
Option c – Bakelite
The raw material used in the preparation of nylon-6,6 is:
(A) Adipic Acid and ethanol
(B) Adipic acid and ethane1,2-diol
(C) Adipic acid and hexamethylene diamine
(D) Hexamethylene diamine and vinyl cyanide
Explanation: This question focuses on the starting materials required to produce a specific synthetic polymer. Nylon-6,6 is formed through condensation polymerization involving two different monomers.
These monomers must contain functional groups capable of reacting with each other to form strong linkages. Typically, one monomer contains amine groups while the other contains carboxylic acid groups.
During polymerization, these groups react to form amide linkages, releasing small molecules like water. This results in long, strong polymer chains.
An analogy is joining two different types of connectors that fit together perfectly to form a long chain.
In summary, nylon-6,6 is formed from two complementary monomers that react through condensation to create strong, repeating linkages.
Option c – Adipic acid and hexamethylene diamine
Nylon is an example of:
(A) Polyamide
(B) Polysaccharide
(C) Polythene
(D) Polyester
Explanation: This question asks about the classification of nylon based on its chemical structure. Nylon is formed through condensation polymerization involving monomers with specific functional groups.
The resulting polymer contains repeating units connected by amide linkages. These linkages contribute to strong intermolecular forces, particularly hydrogen Bonding, which enhances strength and durability.
Due to these properties, nylon is widely used in fibers, textiles, and engineering materials.
An analogy is a chain with strong links that hold tightly together, making the overall structure robust.
In summary, nylon is a polymer characterized by repeating units linked through strong functional group connections that provide high strength.
Option a – Polyamide
Biodegradable polymers are used in:
(A) drug release materials
(B) Implants
(C) Orthopedic devices
(D) All of the above (A, B, and C)
Explanation: This question explores the applications of biodegradable polymers. These materials are designed to break down naturally in the body or Environment.
Their ability to degrade safely makes them suitable for medical applications such as drug delivery systems, implants, and temporary devices. They gradually decompose into non-toxic substances after serving their purpose.
This reduces the need for surgical removal and minimizes environmental impact.
An analogy is dissolvable stitches that disappear after healing is complete.
In summary, biodegradable polymers are used in applications where controlled degradation and minimal long-term impact are required.
Option d – All of the above (A, B, and C)
Buna-N polymer is obtained by reacting But-1,3 diene and:
(A) Vinyl cyanide
(B) Vinyl chloride
(C) Vinyl Alcohol
(D) Vinyl bromide
Explanation: This question focuses on the formation of a synthetic rubber through copolymerization. But-1,3-diene reacts with another monomer to produce a polymer with improved resistance to oils and chemicals.
The second monomer introduces specific functional groups into the polymer chain, enhancing its properties. The combination results in a material suitable for industrial applications like seals and hoses.
The polymerization occurs through addition reactions, linking monomers into long chains.
An analogy is mixing two ingredients to create a product with better performance than either alone.
In summary, this polymer is formed by combining two different monomers to produce a material with enhanced properties.
Option a – Vinyl cyanide
A three-dimensional cross-linked Network Solid having links at two ortho and one para position is called:
(A) Bakelite
(B) Orlon
(C) PVC
(D) PAN
Explanation: This question examines a polymer with a highly cross-linked three-dimensional structure. Such structures are formed when monomers react at multiple positions, creating a नेटवर्क of interconnected chains.
The presence of links at specific positions on aromatic rings leads to a rigid and stable structure. These polymers are known for their hardness, heat resistance, and electrical insulating properties.
Once formed, they cannot be reshaped due to their मजबूत covalent Bonding Network.
An analogy is a tightly woven NET where each point is strongly connected to several others.
In summary, this type of polymer forms a rigid, cross-linked network due to multiple bonding sites, resulting in high stability and strength.
Option a – Bakelite
The reaction of Melamine + Methanal to form Melamine formaldehyde resin is an example of:
(A) Addition-elimination polymerization
(B) Condensation polymerization
(C) Elimination polymerization
(D) Rearrangement polymerization
Explanation: This question focuses on the type of polymerization reaction involved in forming a specific resin. When melamine reacts with methanal, a network polymer is formed through repeated condensation steps.
During this process, small molecules are eliminated as the monomers link together. The resulting structure is highly cross-linked, giving it strength and resistance to heat.
Such polymers are widely used in laminates, adhesives, and coatings due to their durability.
An analogy is joining multiple pieces with glue that hardens permanently, creating a Solid structure.
In summary, this reaction involves stepwise linking of monomers with elimination of small molecules, forming a मजबूत cross-linked polymer network.
Option b – Condensation polymerization
Buna-S is a polymer of:
(A) Styrene and methanal
(B) Styrene and but-1,2-diene
(C) Styrene and but-1,3-diene
(D) But-1,3-diene and vinyl cyanide
Explanation: This question focuses on identifying the monomers involved in forming a widely used synthetic rubber. Such polymers are typically formed through copolymerization, where two different monomers combine to produce a material with enhanced properties.
One of the monomers provides elasticity due to its unsaturated hydrocarbon structure, while the other contributes strength and resistance to wear. The combination results in a balanced material suitable for applications like tyres and footwear.
The polymerization occurs through an addition mechanism, where double bonds open and link to form long chains. The resulting structure reflects contributions from both monomers.
An analogy is blending two materials to get the advantages of both, like mixing rubber and plastic.
In summary, this polymer is formed by combining two different monomers through addition polymerization to achieve improved Mechanical Properties.
Option c – Styrene and but-1,3-diene
Cellulose pulp wood is treated with conc. NaOH to give:
(A) Alkali cellulose
(B) Cellulose xanthate
(C) Viscose rayon
(D) Acetate rayon
Explanation: This question examines an intermediate step in the processing of cellulose. When cellulose pulp is treated with concentrated sodium hydroxide, its structure is modified.
The treatment causes swelling and partial breakdown of hydrogen bonding between chains, making the material more reactive. This step prepares cellulose for further chemical reactions in industrial processes.
The modified product has different properties compared to raw cellulose and serves as an important intermediate in producing fibers and films.
An analogy is soaking dry grains in water to make them softer and easier to process.
In summary, treating cellulose with strong alkali alters its structure, producing a reactive intermediate used in further processing.
Option a – Alkali cellulose
Which of the following is a natural polymer?
(A) Poly(butadiene-acrylonitrile)
(B) cis-1,4-polyisoprene
(C) Poly(butadiene-styrene)
(D) Polybutadiene
Explanation: This question asks to identify a polymer that occurs naturally in Living Organisms. Natural polymers are formed through biological processes and are essential for life.
Examples include proteins, nucleic Acids, and certain plant-derived materials. These polymers have specific structures and functions, often determined by their repeating units and arrangement.
Unlike synthetic polymers, they are biodegradable and environmentally friendly.
An analogy is comparing naturally grown cotton with synthetic fabric—both are useful, but one is produced by nature.
In summary, natural polymers are those produced biologically and characterized by their occurrence in nature and biodegradability.
Option b – cis-1,4-polyisoprene
The biodegradable polymer is:
(A) Nylon-2-nylon-6
(B) Nylon-6
(C) Buna-S
(D) Nylon-6,6
Explanation: This question focuses on identifying a polymer that can decompose naturally. Biodegradable polymers contain chemical bonds that can be broken down by microorganisms.
These polymers are designed to reduce environmental impact, as they degrade into harmless substances over time. Their structure often includes linkages that are susceptible to hydrolysis or enzymatic action.
Such materials are increasingly used in packaging and medical applications.
An analogy is Organic waste decomposing in soil, unlike plastic which persists.
In summary, biodegradable polymers are those that can break down naturally due to their chemical structure.
Option a – Nylon-2-nylon-6
Regarding cross-linked or network polymers, which of the following statements is incorrect?
(A) Examples are bakelite and melamine
(B) They are formed from bi-and tri-functional monomers.
(C) They contain covalent bonds between various linear polymer chains.
(D) They contain strong covalent bonds in their polymer chains.
Explanation: This question requires analyzing statements about cross-linked polymers and identifying the incorrect one. These polymers have a three-dimensional network structure formed by covalent bonds between chains.
They are typically formed from monomers with multiple functional groups, allowing extensive cross-linking. This structure gives them high strength, rigidity, and resistance to heat.
However, understanding their properties requires careful evaluation, as incorrect assumptions about their formation or structure may arise.
An analogy is a tightly connected web where each strand is linked to several others, making it strong and stable.
In summary, cross-linked polymers are highly interconnected structures, and identifying incorrect statements requires understanding their formation and properties.
Option d – They contain strong covalent bonds in their polymer chains
Polycarbonate is a polymer of:
(A) Ethylene glycol + phthalic acid
(B) Butadiene + acrylonitrile
(C) Urea + methanal
(D) Bisphenol + Phosgene
Explanation: This question deals with identifying the monomers used to form a specific polymer. Polycarbonates are formed through condensation reactions involving compounds that can create carbonate linkages.
These polymers are known for their transparency, strength, and impact resistance. The repeating units are connected through carbonate groups, contributing to their unique properties.
They are widely used in applications like optical discs, lenses, and protective equipment.
An analogy is connecting units with strong but flexible joints that allow durability without brittleness.
In summary, polycarbonates are formed through condensation reactions that create carbonate linkages between repeating units.
Option d – Bisphenol + Phosgene
Nylon is an example of:
(A) Polyester
(B) Polysaccharide
(C) Polyamide
(D) Polythene
Explanation: This question again focuses on classifying nylon based on its structure. Nylon is formed through condensation polymerization involving monomers with amine and carboxylic acid groups.
The resulting polymer contains repeating amide linkages, which contribute to strong intermolecular forces. These forces enhance mechanical strength and durability.
Such polymers are widely used in fibers, ropes, and engineering materials.
An analogy is a chain with strong links that hold tightly together under stress.
In summary, nylon is characterized by repeating units connected through strong functional linkages, resulting in a durable polymer.
Option c – Polyamide
Which one of the following is not a condensation polymer?
(A) Melamine
(B) Glyptal
(C) Dacron
(D) Neoprene
Explanation: This question asks to identify a polymer that is not formed through condensation polymerization. In condensation polymerization, small molecules like water are eliminated during the formation of the polymer.
Some polymers, however, are formed through addition polymerization, where monomers join without loss of any small molecules. These polymers have different structural characteristics.
Understanding the difference between these mechanisms helps in identifying the correct category.
An analogy is comparing building with glue (where something is lost) versus snapping pieces together (where nothing is lost).
In summary, identifying such polymers requires understanding whether small molecules are eliminated during their formation.
Option d – Neoprene
Which of the following statements is false?
(A) Artificial silk is derived from cellulose.
(B) Nylon-66 is an example of an elastomer.
(C) The repeat unit in natural rubber is isoprene.
(D) Both starch and cellulose are polymers of glucose.
Explanation: This question requires evaluating multiple statements about polymers and identifying the incorrect one. It involves knowledge of different polymer types, their structures, and properties.
Some statements may describe natural polymers, while others refer to synthetic ones. Understanding the composition and characteristics of each is essential to determine accuracy.
Careful comparison of known facts helps in identifying inconsistencies.
An analogy is checking multiple claims against known facts to find the incorrect one.
In summary, determining the false statement involves analyzing each option based on established polymer concepts and properties.
Option b – Nylon-66 is an example of an elastomer
Biodegradable polymer that can be produced from glycine and aminocaproic acid is:
(A) Nylon-2-nylon-6
(B) PHBV
(C) Buna-N
(D) Nylon-6,6
Explanation: This question focuses on identifying a biodegradable polymer formed from specific monomers. Glycine and aminocaproic acid both contain functional groups capable of forming amide linkages.
Through condensation polymerization, these monomers combine to form a polymer that can degrade naturally. The presence of such linkages allows the polymer to break down under biological conditions.
This makes it suitable for environmentally friendly and biomedical applications.
An analogy is creating a chain that can eventually break down into its original components.
In summary, such polymers are formed through condensation of amino-containing monomers and are designed to degrade naturally.
Option a – Nylon-2-nylon-6
Caprolactam is used for the manufacture of:
(A) Nylon-6
(B) Teflon
(C) Terylene
(D) Nylon-6,6
Explanation: This question focuses on identifying the polymer produced from caprolactam. Caprolactam is a cyclic compound that can undergo ring-opening polymerization under suitable conditions.
During this process, the ring structure opens up and links with other similar units to form a long-chain polymer. The resulting material contains repeating amide linkages, contributing to strength and durability.
This polymer is widely used in fibers, textiles, and engineering plastics due to its excellent Mechanical Properties and resistance to wear.
An analogy is opening circular rings and joining them end-to-end to form a long chain.
In summary, caprolactam undergoes ring-opening polymerization to produce a strong, fiber-forming polymer with repeating structural units.
Option a – Nylon-6
Natural rubber has:
(A) All trans-configuration
(B) Alternate cis-and trans-configuration
(C) Random cis- and trans-configuration
(D) All cis-configuration
Explanation: This question examines the structural configuration of natural rubber. Natural rubber is made up of repeating isoprene units arranged in a specific geometric form.
The spatial arrangement of these units determines the flexibility and elasticity of the material. In one configuration, the chains can coil and stretch easily, giving rubber its elastic nature.
This arrangement prevents tight packing of chains, allowing movement under stress and recovery afterward. Other configurations would lead to more rigid and less elastic materials.
An analogy is a loosely coiled spring that can stretch and return to its original shape.
In summary, the elasticity of natural rubber arises from the specific geometric arrangement of its repeating units, allowing flexibility and recovery after deformation.
Option d – All cis-configuration
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