Chapter Wise Test Series for NEET

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Chapter Wise test Series for NEET. We covered all the Chapter Wise test Series for NEET Students in this post for free so that you can practice well for the exam.

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mcq on Biomolecules for NEET Students

Assertion: Propan-1-ol dissolves less readily in water compared to methanol

Reason: As the alkyl chain length increases in Alcohols, their solubility in water decreases

a) Both the Assertion and the Reason are correct, and the Reason explains the Assertion

b) Both the Assertion and the Reason are correct, but the Reason does not explain the Assertion

c) The Assertion is correct, but the Reason is incorrect

d) The Assertion is incorrect, but the Reason is correct

Option a – Both the Assertion and the Reason are correct, and the Reason explains the Assertion

Which properties differ between the enantiomers (+)-2-butanol and (–)-2-butanol?

a) Solubility in water, specific rotation, reactivity with sodium

b) Specific rotation, 3D arrangement around chiral center

c) Spatial orientation, bond angles near the chiral center, refractive index

d) Solubility, spatial orientation, bond angles near the chiral center

Option b – Specific rotation, 3D arrangement around chiral center

The common name of 1-bromo-2-methylpropane is:

a) tert-butyl bromide

b) sec-butyl bromide

c) isobutyl bromide

d) n-butyl bromide

Option c – isobutyl bromide

Which of the following transformations can be achieved using the Swarts reaction?

a) Chloroethane → Fluoroethane

b) Chloroethane → Iodoethane

c) Ethanol → Chloroethane

d) Ethanol → Bromoethane

Option a – Chloroethane → Fluoroethane

Heating phenyl methyl Ether with hydrogen iodide produces:

a) Iodobenzene and iodomethane

b) Phenol and iodomethane

c) Benzene and methanol

d) Phenol and methanol

Option b – Phenol and iodomethane

Which compound cannot serve as a precursor in the iodoform reaction using iodine and sodium hydroxide?

a) Ethyl methyl ketone

b) Isopropanol

c) Acetaldehyde

d) Isobutyl Alcohol

Option d – Isobutyl Alcohol

Fusing sodium benzene sulphonate with sodium hydroxide, followed by acidification, yields:

a) Benzene sulphonic Acid

b) Benzoic Acid

c) Phenol

d) Pyrogallol

Option c – Phenol

Identify the correct statement(s):

I. The carbon-halogen bond in chloromethane is longer than in bromomethane
II. The C–X bond is longer in bromobenzene than in bromomethane
III. The bond length of C–X in chloromethane is longer than in chlorobenzene

a) Only I

b) Only III

c) I and II

d) II and III

Option b – Only III

Treatment of propyne with aqueous sulfuric Acid in the presence of mercuric sulfate yields:

a) CH₃CH₂CHO

b) CH₃CH₂COCH₃

c) CH₃COCH₃

d) CH₃CH₂CH₂OH

Option c – CH₃COCH₃

One mole of compound ‘X’ undergoes catalytic hydrogenation to produce two moles of a primary Alcohol ‘Y’. Identify ‘X’.

a) Propanone

b) Ethyl propanoate

c) Propanal

d) Propyl propanoate

Option d – Propyl propanoate

Aldehydes or ketones react with phenylhydrazine to form:

a) Semicarbazone

b) Phenylhydrazone

c) Hydrazone

d) Oxime

Option b – Phenylhydrazone

Which reagent can convert CH₃CH₂CH=CH₂ into CH₃CH₂CH₂CH₂OH?

a) Conc. H₂SO₄ followed by heating with water

b) BH₃/THF followed by H₂O₂, NaOH

c) Alcoholic NaOH

d) Moist Ag₂O

Option b – BH₃/THF followed by H₂O₂, NaOH

Assertion: p-Aminophenol is less acidic than Phenol

Reason: Electron-donating groups reduce the tendency of Phenols to release a proton

a) Both Assertion and Reason are correct, and the Reason explains the Assertion

b) Both Assertion and Reason are correct, but the Reason does not explain the Assertion

c) Assertion is correct, Reason is incorrect

d) Assertion is incorrect, Reason is correct

Option a – Both Assertion and Reason are correct, and the Reason explains the Assertion

Phenol treated with a nitrating mixture forms compound X. Which of the following groups is not present in X?

I. –CHO
II. –NO₂
III. –COOH
IV. –NH₂
V. –OH

a) I and II

b) I and IV

c) II, III, and IV

d) I, III, and IV

Option d – I, III, and IV

Compound X undergoes SN1 hydrolysis under alkaline conditions to give products Y and Z in equal amounts. Y and Z are enantiomers, and the final product is racemic. Identify X.

a) 2-Bromo-2-methylpropane

b) 1-Bromo-1-phenylethane

c) 2-Bromopropane

d) 1-Bromo-2-phenylpropane

Option b – 1-Bromo-1-phenylethane

Which of the following compounds is classified as an allylic Alcohol?

a) 2-Phenylpropan-2-ol

b) 2-Methylpropan-2-ol

c) Prop-1-en-1-ol

d) 2-Methylbut-3-en-2-ol

Option d – 2-Methylbut-3-en-2-ol

In which of the following molecules are all carbon atoms sp² hybridized?

a) Acetaldehyde

b) Acrolein

c) Glyceraldehyde

d) Crotonaldehyde

Option b – Acrolein

An Organic compound X reacts with CO and HCl under high pressure using a catalyst mixture of anhydrous AlCl₃ and Cu₂Cl₂ to give compound Y. Oxidizing Y with alkaline KMnO₄ yields benzoic Acid. Y reacts positively with Schiff’s reagent and negatively with Fehling’s solution. Identify X and Y.

a) X = Benzene; Y = Benzophenone

b) X = Toluene; Y = Benzaldehyde

c) X = Benzene; Y = Benzaldehyde

d) X = Benzene; Y = Acetophenone

Option c – X = Benzene; Y = Benzaldehyde

We covered all the Biomolecules NEET mcq above in this post for free so that you can practice well for the exam.

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