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Inter First Year Physics 2 Marks Questions. We covered all the Inter First Year Physics 2 Marks Questions in this post for free so that you can practice well for the exam.
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Inter First Year Physics 2 Marks Mock test for Students
In Young’s double-slit experiment, the separation between the slits is 0.28 mm and the screen is placed 48 cm away. The entire arrangement is immersed in oil having a refractive index of 4/3. If the slits are illuminated with Light of wavelength 0.7 μm (in air), what will be the position of the second bright fringe from the central maximum?
a) 900 μm
b) 90 μm
c) 1800 μm
d) 180 μm
Option c – 1800 μm
In Young’s experiment, the distance between the screen and the slits is kept fixed. If the separation between the two slits is reduced to half of its original value, how will the fringe width change?
a) It becomes double
b) It becomes half
c) It remains unchanged
d) It becomes four times
Option a – It becomes double
The spacing between two consecutive dark fringes in an interference pattern is known as:
a) Amplitude
b) Mean free path
c) Wavelength
d) Fringe width
Option d – Fringe width
In the phenomenon of Light interference, the fringe width depends on:
a) The wavelength of Light
b) The distance between the slits and the screen
c) The separation between the slits
d) All of these factors
Option d – All of these factors
In Young’s double-slit experiment, interference fringes are obtained using monochromatic Light for a certain slit separation. If the distance between the slits is increased, the fringes will become:
a) Narrower
b) Wider
c) Circular
d) Unchanged in width
Option a – Narrower
In Young’s experiment, the separation between the slits is 0.13 mm and the wavelength of Light used is 6500 Å. The fringe pattern is observed on a screen placed at a suitable distance. By how much should the screen be shifted so that the fringe width increases by 2 mm?
a) 30 cm
b) 40 cm
c) 60 cm
d) 50 cm
Option b – 40 cm
In Young’s double-slit experiment, Light of wavelength 5000 Å is used. The slit separation is 0.2 mm and the screen is placed 2 m away. If the central maximum is at x = 0, where will the fourth bright fringe be located?
a) 1.5 cm
b) 2 mm
c) 2 cm
d) 0.2 mm
Option c – 2 cm
In Young’s experiment, yellow Light from a sodium lamp is replaced by monochromatic blue Light of the same intensity. What change will be observed in the fringe width?
a) The fringe width increases
b) The fringe width decreases
c) The fringe width remains unchanged
d) The fringes become less intense
Option b – The fringe width decreases
In Young’s double-slit experiment, Light of wavelength 632 nm is used. The first minimum in the interference pattern occurs at a path difference of:
a) 1264 nm
b) 632 nm
c) 316 nm
d) 158 nm
Option c – 316 nm
In two separate Young’s double-slit experiments, fringes of equal width are observed using Light of wavelengths in the ratio 1 : 2. If the slit separations in the two cases are in the ratio 2 : 1, what is the ratio of distances between the slits and the screen in the two setups?
a) 1 : 1
b) 1 : 2
c) 4 : 1
d) 1 : 4
Option c – 4 : 1
In Young’s experiment, the slits are separated by 0.5 mm and the screen is placed 1 m away. The ninth bright fringe is found to be 9 mm away from the second dark fringe measured from the center. What is the wavelength of the light used?
a) 5000 Å
b) 6000 Å
c) 5500 Å
d) 7000 Å
Option b – 6000 Å
In Young’s double-slit experiment, 12 fringes are observed within a fixed length on the screen when light of wavelength 6000 Å is used. If the wavelength is reduced by 2000 Å, how many fringes will be seen in the same region?
a) 18
b) 12
c) 16
d) 24
Option a – 18
We covered all the Inter first year Physics 2 marks Questions above in this post for free so that you can practice well for the exam.
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Also, check out:
- Nootan ISC Physics Class 11 Solutions
- ISC Nootan Physics Class 11 Solutions
- Class 11 Physics Objective Questions in Hindi
