Balaji Publications Chemistry for NEET. We covered all the Balaji Publications Chemistry for NEET in this post for free so that you can practice well for the exam.
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Balaji Publications Objective Chemistry for NEET Students
When potassium iodide (KI) is heated with concentrated H₂SO₄, the main product formed is:
a) HI
b) I₂
c) HIO₃
d) KIO₃
Explanation: Analyze the reaction of potassium iodide with concentrated sulfuric Acid to determine the primary product formed.
Heating KI with concentrated H₂SO₄ involves a redox reaction where iodide ions can be oxidized. Sulfuric Acid functions both as a dehydrating agent and a strong oxidant, and the reaction produces different iodine species depending on temperature and concentration.
Iodide ions first form hydrogen iodide (HI) upon protonation. Strong oxidizing conditions can further oxidize HI to iodine (I2) or other iodine oxides. Reaction conditions like Heat and Acid concentration determine which product predominates.
For analogy, this is similar to how NaCl produces HCl with H₂SO₄, but iodide is more easily oxidized.
The reaction illustrates halide Chemistry, oxidation states, and the dual role of concentrated Acids in redox processes.
Option b – I₂
Which of the following reactions is not suitable for producing a halogen Acid?
a) 2KBr + H₂SO₄ → K₂SO₄ + 2HBr
b) NaHSO₄ + NaCl → Na₂SO₄ + HCl
c) NaCl + H₂SO₄ → NaHSO₄ + HCl
d) CaF₂ + H₂SO₄ → CaSO₄ + 2HF
Explanation: Determine which reaction cannot generate a hydrogen halide from a halide Salt and strong Acid.
Halogen Acids like HCl, HBr, and HI are typically produced by treating their Salts with strong Acids. Success depends on halide reactivity and the Acid’s oxidizing power. Some reactions fail due to insolubility or insufficient redox potential, such as fluoride Salts with H₂SO₄.
Analyzing the reactivity of halide Salts and Acid compatibility identifies the unsuitable reaction. Factors like Thermodynamics, solubility, and redox potential are key to predicting success.
Analogously, only halides capable of displacing a proton from the Acid will release the corresponding halogen Acid, much like Metals react with Acids to release hydrogen gas.
This demonstrates the interplay of halide Chemistry, solubility, and redox considerations in laboratory Acid preparation.
Option a – 2KBr + H₂SO₄ → K₂SO₄ + 2HBr
Fluorine reacts with water to produce:
a) HF and O₂
b) HF and OF₂
c) HF and O₃
d) HF, O₂, and O₃
Explanation: Understand the reaction between fluorine and water to determine the products formed.
Fluorine is a highly electronegative and reactive halogen. When it reacts with water, it can oxidize water molecules, producing a mixture of fluoride compounds and oxygen-containing species. The reaction is exothermic and involves simultaneous reduction and oxidation.
The products depend on fluorine’s strong oxidizing ability, which allows it to generate HF along with oxygen or oxygen fluorides. Reaction stoichiometry and conditions such as temperature influence which oxygen species are produced.
For example, fluorine’s reaction is much more vigorous than chlorine’s reaction with water, reflecting its high reactivity.
This reaction highlights the unique oxidizing power of fluorine and its role in producing halogen Acids and oxygen species from water.
Option d – HF, O₂, and O₃
A deficiency of iodine in the diet can lead to:
a) Night blindness
b) Rickets
c) Goitre
d) Beri-beri
Explanation: Identify the physiological disorder caused by insufficient iodine intake.
Iodine is an essential trace element required for the synthesis of thyroid hormones, which regulate metabolism, growth, and development. A deficiency impairs hormone production, leading to enlargement of the thyroid gland and other metabolic disturbances.
The deficiency manifests as goitre, with potential complications including developmental delays in children and decreased metabolic efficiency in adults. The condition is preventable through dietary intake of iodine-rich foods or iodized Salt.
This illustrates the connection between micronutrients, endocrine function, and public Health measures to prevent deficiency disorders.
It emphasizes how a single element’s deficiency can affect systemic physiological processes.
Option c – Goitre
Nitric acid converts iodine into:
a) Iodic acid (HIO₃)
b) Hydroiodic acid (HI)
c) Iodic nitrite
d) Iodine pentoxide (I₂O₅)
Explanation: Determine the product formed when iodine reacts with nitric acid.
Nitric acid acts as an oxidizing agent. Iodine can be oxidized from I2 to higher oxidation states when treated with HNO₃. The reaction leads to formation of iodine compounds like iodic acid or iodine oxides depending on conditions.
Reaction stoichiometry, acid concentration, and temperature control the extent of oxidation. This process illustrates redox behavior and the reactivity of halogens with strong oxidizers.
For analogy, it’s similar to how chlorine can be oxidized to chlorates using strong Acids or oxidizing agents.
The reaction exemplifies halogen Chemistry, oxidation states, and the use of strong Acids in producing higher oxides or Acids.
Option a – Iodic acid (HIO₃)
The lattice energy of lithium halides follows the order:
a) LiF > LiCl > LiBr > LiI
b) LiCl > LiF > LiBr > LiI
c) LiBr > LiCl > LiF > LiI
d) LiI > LiBr > LiCl > LiF
Explanation: Analyze the trend in lattice energies among lithium halides.
Lattice energy depends on the ionic charges and sizes. Smaller anions and cations result in stronger electrostatic attraction and higher lattice energy. As the halide ion size increases from F− to I−, lattice energy decreases due to increasing ionic radii.
This trend is predicted using Coulomb’s law, considering the distance between ions and magnitude of charges. Smaller ions like LiF have stronger interactions than larger ions like LiI.
Analogously, it’s like magnets: smaller, closer charges attract more strongly than larger, farther ones.
This concept highlights how ionic size influences lattice stability in SolidSalts.
Option a – LiF > LiCl > LiBr > LiI
On heating a mixture of NaCl, K₂Cr₂O₇, and concentrated H₂SO₄, the gas evolved is:
a) O₂
b) Cl₂
c) CrOCl₂
d) CrO₂Cl₂
Explanation: Identify the gaseous product formed from heating this mixture of Salts and acid.
K₂Cr₂O₇ is a strong oxidizing agent. Concentrated H₂SO₄ acts as a dehydrating and oxidizing acid. When mixed with NaCl, oxidative chlorination occurs, producing a halogen-based gas. Reaction conditions such as Heat and concentration are key.
Reaction mechanisms involve protonation, oxidation of chloride ions, and liberation of a diatomic halogen gas. Understanding oxidizing behavior of dichromates with halide Salts helps predict the gas formed.
This demonstrates the role of redox Chemistry and strong oxidizing agents in halogen gas preparation.
Option d – CrO₂Cl₂
For which property of halogens does the trend F > Cl > Br > I hold?
a) Electron affinity
b) Electronegativity
c) Atomic radius
d) Boiling point
Explanation: Determine which halogen property decreases or increases in the order F > Cl > Br > I.
Halogens show periodic trends for properties like electronegativity, electron affinity, atomic radius, and boiling point. Electronegativity is highest for fluorine and decreases down the group due to increasing atomic size and electron shielding.
Understanding trends requires consideration of nuclear charge, shielding effect, and distance of valence electrons from the nucleus. This explains why F > Cl > Br > I applies specifically to electronegativity.
Analogously, smaller, highly charged atoms hold electrons more tightly, similar to a stronger magnet attracting metal objects.
Periodic trends highlight systematic variations of chemical properties in a group.
Option b – Electronegativity
The correct order of increasing electron affinity for Cl, Br, and I is:
a) Cl, Br, I
b) I, Br, Cl
c) Br, Cl, I
d) I, Cl, Br
Explanation: Identify the order of increasing electron affinity among selected halogens.
Electron affinity measures energy change when an Atom gains an electron. Smaller atoms with less shielding (like Cl) generally release more energy upon electron gain. Larger atoms (Br, I) have more diffuse orbitals, reducing attraction for additional electrons.
Thus, the order reflects increasing ease of electron addition, affected by atomic size and nuclear charge. Understanding this trend requires knowledge of Periodic behavior of halogens.
For analogy, it’s like magnets of different strengths attracting metal particles; smaller, stronger magnets attract more strongly.
Electron affinity trends explain reactivity and Bonding tendencies of halogens.
Option b – I, Br, Cl
When iodine (I₂) is dissolved in carbon tetrachloride (CCl₄), the resulting color is:
a) Brown
b) Violet
c) Colorless
d) Bluish green
Explanation: Determine the color change when iodine is dissolved in a nonpolar solvent like CCl₄.
Iodine is more soluble in nonpolar solvents. Dissolving I2 in CCl₄ does not involve dissociation into ions, resulting in a characteristic violet color due to Molecular absorption of visible Light.
Color depends on the solvent’s polarity; polar solvents may give brown solutions due to partial ionization. Nonpolar solvents like CCl₄ maintain Molecular I2 in solution, producing the violet hue.
Analogously, the solubility and color shift is like dye in water versus oil, depending on polarity.
This demonstrates halogen solubility effects and Molecular spectroscopy principles.
Option b – Violet
We covered all the balaji publications Chemistry for NEET above in this post for free so that you can practice well for the exam.
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