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Chemistry Lesson Plan in Hindi. We covered all the Chemistry Lesson Plan in Hindi in this post for free so that you can practice well for the exam.
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Chemistry Lesson Plan Objective in Hindi for Students
A non-ideal solution is formed by mixing 30 mL of chloroform with 50 mL of acetone. What will be the total volume of the resulting mixture?
a) Greater than 80 mL
b) Less than 80 mL
c) Exactly 80 mL
d) Greater than or equal to 80 mL
Option b - Less than 80 mL
The vapour pressure will be the lowest for which of the following?
a) Pure water
b) 0.1 m aqueous urea solution
c) 0.2 m aqueous urea solution
d) 0.3 m aqueous urea solution
Option d - 0.3 m aqueous urea solution
When 18 g of glucose is dissolved in 178.28 g of water, what is the vapour pressure of water at 100 °C for this solution?
a) 759 torr
b) 7.60 torr
c) 76 torr
d) 752.40 torr
Option d - 752.40 torr
The relative lowering of vapour pressure caused by dissolving 71.5 g of a substance in 100 g of water is 0.00713. What is the molar Mass of the solute?
a) 18
b) 342
c) 60
d) 180
Option d - 180
Colligative properties are commonly used to determine the
a) Molar Mass
b) Equivalent Mass
c) Melting and boiling points
d) Molecular structure
Option a - Molar Mass
A solution contains 2 moles of a solute dissolved in 2 moles of water. If the vapour pressure of pure water is 24 mm Hg, what is the vapour pressure of the solution?
a) 24 mm Hg
b) 32 mm Hg
c) 48 mm Hg
d) 12 mm Hg
Option d - 12 mm Hg
An aqueous glucose solution is prepared by dissolving 18 g of glucose in 90 g of water. What is the relative lowering in vapour pressure?
a) 0.02
b) 1.1
c) 20
d) 1.96
Option a - 0.02
Which of the following is a colligative property of a solution?
a) Vapour pressure
b) Boiling point
c) Osmotic pressure
d) Freezing point
Option c - Osmotic pressure
A non-volatile solute weighing 18 g is dissolved in 900 g of water, producing a relative lowering in vapour pressure of 0.002. What is the molar Mass of the solute?
a) 60
b) 342
c) 18
d) 180
Option d - 180
The vapour pressure of pure water at 30 °C is 31.8 mm Hg. What will be the vapour pressure of a solution containing 90 g of glucose dissolved in 900 g of water at the same temperature?
a) 30.24 mm Hg
b) 31.482 mm Hg
c) 32.46 mm Hg
d) 30.74 mm Hg
Option b - 31.482 mm Hg
Benzene and toluene form an almost ideal solution. At 25 °C, the vapour pressures of pure benzene and toluene are 75 torr and 22 torr respectively. What is the partial vapour pressure of benzene in a solution containing 78 g of benzene and 46 g of toluene?
a) 50 torr
b) 25 torr
c) 37.5 torr
d) 53.5 torr
Option a - 50 torr
The lowering of vapour pressure caused by adding 100 g of sucrose to 1000 g of water is calculated when the vapour pressure of pure water at 25 °C is 28.8 mm Hg. What is the vapour pressure lowering?
a) 1.25 mm Hg
b) 0.125 mm Hg
c) 1.15 mm Hg
d) 0.12 mm Hg
Option b - 0.125 mm Hg
When a liquid is heated, its vapour pressure
a) Increases
b) Decreases
c) Increases and becomes constant at its boiling point
d) Cannot be predicted
Option c - Increases and becomes constant at its boiling point
We covered all the Chemistry lesson plan in Hindi above in this post for free so that you can practice well for the exam.
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