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Class 12 Physics wave Optics qna for Students
An interference pattern formed by monochromatic Light consists of
a) Alternating bright and dark fringes
b) Only bright fringes
c) Only dark fringes
d) Coloured fringes
Explanation: The question asks about the visual outcome when a single wavelength of Light overlaps to form a pattern. Interference occurs when two or more coherent Light waves meet, producing regions of constructive and destructive interference. Constructive interference happens where waves reinforce each other, while destructive interference occurs where waves cancel out. In monochromatic Light, the repeated overlap creates a series of alternating bright and dark bands or fringes on a screen. These fringes are equally spaced if the sources are coherent and the medium is uniform. A simple analogy is throwing two stones in water simultaneously, creating overlapping circular waves that form alternating high and low points. This phenomenon is a hallmark of wave behavior, demonstrating the principle of superposition where wave amplitudes add algebraically at each point. Understanding the interference pattern is crucial in experiments such as the Young’s double-slit experiment, which visually confirms wave nature of Light. The alternating bright and dark regions arise purely due to phase differences between the overlapping waves, not because of color variations or amplitude differences. The bright areas correspond to maximum intensity, while dark regions correspond to points of cancellation.
Option a – Alternating bright and dark fringes
Which of the following conditions stated for producing steady and observable interference of Light is incorrect?
a) The two sources must emit waves continuously with the same wavelength
b) The two sources should be coherent
c) The sources should be very narrow and placed close to each other
d) The amplitudes of waves from the two sources must be unequal
Explanation: This question examines the essential criteria for generating stable interference patterns with Light. Interference requires coherent sources, meaning they emit waves of the same wavelength and maintain a constant phase difference. The sources should ideally be narrow and close to each other to ensure overlapping of waves and formation of visible fringes. The amplitudes of the waves also play a role in determining intensity variations, but interference can still occur even if amplitudes are unequal; unequal amplitudes affect fringe visibility, not the possibility of interference. Understanding these conditions allows one to identify which statement contradicts the fundamental requirements. An analogy is two synchronized metronomes on a common Base: they must tick at the same rate and maintain relative phase to create a consistent pattern. Any deviation from coherence or source proximity can disrupt the steady pattern. Observing the interference requires continuous emission and stable wavelength from both sources. The key is that interference relies on wave coherence and proper alignment rather than exact equality of amplitudes.
Option d – The amplitudes of waves from the two sources must be unequal
Two Light waves of equal amplitude a, travelling through a medium, reach a point with a phase difference of π. The resultant amplitude at that point is
a) Zero
b) 2a
c) 3a
d) 4a
Explanation: The question asks what happens when two Light waves of equal strength meet out of phase by π radians. When waves combine, their amplitudes add algebraically according to their phase difference. A phase difference of π corresponds to the waves being exactly out of phase, meaning the crest of one wave aligns with the trough of the other. In such cases, the positive displacement of one wave cancels the negative displacement of the other, leading to destructive interference. This results in complete cancellation at that point, producing zero NET amplitude. A common analogy is two equal ropes being shaken in opposite directions: the upward motion of one cancels the downward motion of the other at each instant. This principle demonstrates how interference depends not just on amplitude but also on relative phase. The overall intensity at such points is minimal due to this cancellation, emphasizing the wave nature of Light. Destructive interference is responsible for the dark fringes observed in interference experiments like the double-slit experiment.
Option a – Zero
If the intensities of two superposing light sources are I and 4I, the maximum and minimum intensities in the interference pattern will be
a) 9I and 3I
b) 5I and 3I
c) 9I and I
d) 2I and I
Explanation: This question deals with combining light waves of different intensities and understanding the resulting interference pattern. Light intensity is proportional to the square of amplitude. When two waves superpose, the maximum intensity occurs when the waves interfere constructively (phases aligned), while the minimum occurs during destructive interference (phases opposite). By converting intensities to amplitudes, one can determine how the amplitudes combine algebraically: maximum intensity comes from the sum of amplitudes squared, and minimum intensity comes from their difference squared. A practical example is overlapping water waves of unequal heights; the tallest peaks form where waves align, while troughs can be shallower depending on the difference in heights. This principle is fundamental in understanding fringe contrast in optical interference experiments and highlights that unequal wave strengths modify the range of intensities without eliminating the interference pattern. The observed pattern shows bright regions more intense and dark regions less intense, consistent with the relative amplitudes.
Option c – 9I and I
When petrol droplets spread over rainwater on a road produce colourful patterns, the phenomenon responsible is
a) Dispersion of light
b) Absorption of light
c) Scattering of light
d) Interference of light
Explanation: This question explores the reason for observing rainbow-like colours on a thin petrol film on water. The colours arise due to interference of light reflecting from the top and bottom surfaces of the thin layer. Light waves reflect partially from the air–petrol interface and the petrol–water interface. Differences in path length cause constructive and destructive interference for different wavelengths, producing the observed Spectrum. This is similar to how soap bubbles display shimmering colours. Thin-film interference depends on film thickness, wavelength, and angle of incidence, resulting in different colours appearing at different points. The effect is purely optical and does not involve absorption or scattering of light in the medium. A simple analogy is layered glass reflecting sunlight, producing iridescent patterns. Understanding thin-film interference helps explain everyday visual phenomena like oil spills or bubble colours.
Option d – Interference of light
If the ratio of maximum to minimum intensity in an interference pattern is infinite, the ratio of the amplitudes of the two sources is
a) Unity
b) Infinite
c) Two
d) Cannot be determined
Explanation: The question involves linking intensity ratios with wave amplitudes in interference. Intensity in an interference pattern depends on the amplitudes of the superposing waves. The maximum intensity occurs when waves reinforce each other constructively, and the minimum intensity occurs during destructive interference. An infinite maximum-to-minimum intensity ratio implies the minimum intensity is zero, which can only happen when the waves have equal amplitudes, so they completely cancel each other during destructive interference. This demonstrates a key principle: equal-amplitude waves produce the highest contrast fringes. An analogy is two people pushing a swing in opposite directions with equal force; the swing remains stationary due to complete cancellation. This concept is widely used in Optics experiments to optimize fringe visibility in double-slit setups. The ratio highlights how amplitude equality directly affects interference contrast and pattern clarity.
Option d – Cannot be determined
Two light waves of equal amplitude a travelling through a medium reach a point in the same phase. The resultant intensity at that point is
a)
b)
c)
d)
Explanation: This question considers the case where two equal waves meet perfectly in phase. When waves are in phase, constructive interference occurs, meaning their displacements add algebraically at every point. Since intensity is proportional to the square of the resultant amplitude, the combined amplitude is double the individual amplitude, leading to four times the intensity of a single wave. An analogy is two synchronized speakers emitting the same sound wave in phase: the loudness perceived is significantly higher than that of one speaker alone. This principle underlines why bright fringes in interference experiments are much more intense than individual wave contributions. Constructive interference enhances the observed light intensity, forming bright regions in interference patterns, demonstrating the superposition principle in Optics. The phase relationship is crucial in determining whether the interference is constructive or destructive at a given point.
Option a – a square
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