Degree 4th Sem Physics Important Questions. We covered all the Degree 4th Sem Physics Important Questions in this post for free so that you can practice well for the exam.
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Explanation: This question asks what type of force must act on an object so that it continuously follows a curved, circular trajectory instead of moving in a straight line. In Physics, motion in a circle requires a constant change in direction, even if speed remains unchanged. According to Newton’s laws, any change in velocity (including direction) requires a force. For circular motion, this force must always act toward the center of the circle. Without such a force, the object would continue in a straight-line path due to inertia. This inward-directed force is responsible for maintaining the curved motion and preventing the object from flying off tangentially. Think of a stone tied to a string and whirled in a circle—the tension in the string continuously pulls it inward, keeping it in circular motion. In summary, circular motion cannot occur naturally without a specific inward force acting at every instant to change the direction of motion.
Option c – Centripetal force
The escape velocity from the Earth is v. What is the escape velocity from a planet whose Mass and radius are twice those of Earth?
a. v
b. 2v
c. 4v
d. 16v
Explanation: This question examines how escape velocity depends on a planet’s physical properties like Mass and radius. Escape velocity is the minimum speed required for an object to break free from a planet’s gravitational field without further propulsion. It is determined using the relation v = √(2GM/R), where G is the gravitational constant, M is the planet’s Mass, and R is its radius. If both Mass and radius change, their effects must be carefully compared. Increasing Mass strengthens gravitational pull, making escape harder, while increasing radius spreads that Mass over a larger distance, slightly reducing the gravitational effect at the surface. When both Mass and radius are doubled, the ratio inside the square root changes in a balanced way. Imagine climbing out of a deeper but wider well—the depth increases difficulty, but the wider opening slightly offsets it. Thus, analyzing proportional changes helps determine how escape velocity scales overall.
Option a – v
The eccentricity of Mars is:
a. 0.093
b. 0.006
c. 0.02
d. 0.001
Explanation: This question focuses on understanding how the shape of a planet’s orbit is described using a quantity called eccentricity. In celestial mechanics, planets revolve around the Sun in elliptical paths rather than perfect circles. Eccentricity is a numerical measure that indicates how much an orbit deviates from being circular. A value close to zero represents a nearly circular orbit, while higher values indicate more elongated ellipses. For planets, eccentricity values are generally small, meaning their orbits are only slightly stretched. Mars, however, has a more noticeable deviation compared to Earth, which affects variations in its distance from the Sun during its orbit. This leads to differences in Solarenergy received at different points in its path. As an analogy, imagine comparing a perfect circle drawn with a compass to a slightly stretched oval—eccentricity quantifies that stretching. In summary, eccentricity provides a precise way to describe how circular or elongated a planet’s orbit is.
Explanation: This question deals with the orbital shape of Earth and how closely it resembles a perfect circle. Earth revolves around the Sun in an elliptical path, and the degree of this deviation from a circle is measured using eccentricity. For Earth, this value is very small, indicating that its orbit is almost circular. Because of this near-circular path, the variation in Earth’s distance from the Sun throughout the year is relatively minor, which helps maintain a stable Climate compared to planets with more elongated orbits. Eccentricity plays an important role in understanding seasonal changes, though Earth’s seasons are mainly due to axial tilt rather than orbital shape. To visualize this, think of drawing a circle and then slightly stretching it—the difference is barely noticeable, which reflects Earth’s orbit. In summary, Earth’s orbit is nearly circular, and its eccentricity value confirms this minimal deviation.
Option b – 0.016
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