Engineering Physics by Amal Chakraborty. We covered all the Engineering Physics by Amal Chakraborty in this post for free so that you can practice well for the exam.
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For which of the following bodies is the rotational kinetic energy equal to the translational kinetic energy?
a) Ring
b) Disc
c) Sphere
d) All of these
Explanation: Rotational motion and translational motion are two forms of mechanical energy that can coexist in rolling bodies. This question deals with rigid bodies like a ring, disc, and sphere, which have different Mass distributions and therefore different moments of inertia. When a body rolls without slipping, its motion can be split into two parts: rotation about its own axis and translation of its Centre of Mass. The kinetic energy is shared between these two forms depending on how Mass is distributed. Bodies with different geometries convert rotational motion into translational motion differently because their resistance to rotation varies. The relationship between angular velocity and linear velocity in rolling motion links both energies. The condition for equality depends on how inertia and Mass distribution balance rotational and translational contributions during pure rolling motion.
Option a – Ring
A flywheel has a moment of inertia of 4 kg·m² and possesses 200 J of kinetic energy. If an opposing couple of 5 N·m acts on it, how many revolutions will it complete before coming to rest?
a) 12.8 rev
b) 24 rev
c) 6.4 rev
d) 16 rev
Explanation: This question is based on Rotational Dynamics where a rotating flywheel slows down under a constant opposing torque. The flywheel initially has stored rotational energy due to its angular motion, which depends on its moment of inertia and angular velocity. When a constant opposing couple acts, it produces uniform angular deceleration, continuously reducing the rotational speed. The work done by this torque is equal to the loss in rotational kinetic energy. As the system slows down, the torque removes energy steadily until the wheel comes to rest. The angular displacement during this deceleration is directly linked to the energy dissipated by the resisting torque. Since the torque is constant, the total stopping motion depends on how far the wheel rotates before all its initial energy is consumed by the opposing couple.
Option c – 6.4 rev
A flywheel with a moment of inertia of 0.32 kg·m² rotates uniformly at 120 rad/s using a 50 W motor. What is the kinetic energy stored in the flywheel?
a) 4608 J
b) 1152 J
c) 2304 J
d) 6952 J
Explanation: This question deals with rotational kinetic energy in a steadily rotating system driven by a motor. A flywheel stores energy due to its angular motion, which depends on both its moment of inertia and angular speed. When the flywheel rotates uniformly, its speed remains constant, meaning the motor only compensates for losses while maintaining motion. The stored energy is associated with how difficult it is to change the rotational state of the system. A higher moment of inertia means greater resistance to changes in angular motion, leading to greater energy storage at the same angular speed. Angular velocity plays a crucial role because kinetic energy increases rapidly with increasing rotational speed. In such systems, power input is related to maintaining motion rather than changing it, and the stored energy represents the rotational state of the flywheel at that instant.
Option c – 2304 J
A body having a moment of inertia of 3 kg·m² rotates with an angular speed of 2 rad/s. It has the same kinetic energy as a particle of Mass 12 kg moving with what linear speed?
a) 1 m/s
b) 2 m/s
c) 4 m/s
d) 8 m/s
Explanation: This problem compares rotational kinetic energy with translational kinetic energy. A rigid body rotating about an axis stores energy based on its moment of inertia and angular velocity, while a particle in linear motion stores energy based on Mass and velocity. The equivalence between these two forms of energy allows comparison between rotational and linear motion. The idea is to match the energy stored in rotation with that of a moving particle, even though the nature of motion differs. Moment of inertia plays a role similar to Mass in rotation, while angular speed corresponds to linear speed. This analogy helps connect Rotational Dynamics with basic translational motion. The comparison highlights how energy expressions can be equated across different types of motion when they represent the same physical quantity.
Option a – 1 m/s
A thin uniform ring of Mass 10 kg and radius 0.5 m rotates about an axis through its centre, perpendicular to its plane, at 600 rpm. What is its rotational kinetic energy?
a) 9860 J
b) 4930 J
c) 493 J
d) 9.86 J
Explanation: This question involves calculating rotational kinetic energy of a rigid body with known geometry and angular speed. A ring has its entire Mass distributed at a fixed radius from the axis of rotation, which gives it a specific moment of inertia dependent on Mass and radius. Rotational kinetic energy depends on both this inertia and the square of angular velocity. Since the rotation rate is given in revolutions per minute, it must be conceptually converted into angular velocity in radians per second to apply energy relations. The energy increases significantly with angular speed because of its squared dependence. The problem highlights how geometry strongly influences rotational energy through mass distribution and how faster rotation leads to rapidly increasing energy storage in rotating systems.
Option b – 4930 J
A body with a moment of inertia of 1.2 kg·m² is initially at rest. An angular acceleration of 25 rad/s² is applied until the body gains 1500 J of kinetic energy. For how long is the acceleration applied?
a) 4 s
b) 2 s
c) 8 s
d) 10 s
Explanation: This problem deals with rotational motion under constant angular acceleration starting from rest. As the body accelerates, its angular velocity increases steadily over time, leading to an increase in rotational kinetic energy. The energy stored depends on both moment of inertia and angular velocity, while angular velocity itself grows linearly with time under constant acceleration. The applied torque is related to angular acceleration and moment of inertia, creating a direct connection between force-like rotational effect and resulting motion. As time progresses, energy increases because angular speed increases, and the process continues until a specified energy value is reached. The relationship between energy and time is indirect, involving angular acceleration as the bridge between force and motion in rotational systems.
Option b – 2 s
A particle moving in a circular path has its linear momentum directed along which direction?
a) Tangential
b) Radial
c) Centripetal
d) At 45° to the tangent
Explanation: This question focuses on the direction of linear momentum in circular motion. A particle moving along a circular path continuously changes direction, even if its speed remains constant. Linear momentum is defined as the product of mass and velocity, and therefore its direction always follows the instantaneous velocity of the particle. In circular motion, the velocity Vector is always tangent to the path at any given point. This tangential direction is perpendicular to the radius drawn from the center of the circle. Even though there is centripetal acceleration acting toward the center, momentum itself does not point inward; it follows motion direction. This distinction between acceleration and momentum direction is important in understanding rotational and circular dynamics.
Option a – Tangential
The moment of inertia of a rotating wheel about its axis is 3 (SI units). If its rotational kinetic energy is 600 J, what is the time period of rotation?
a) 0.05 s
b) 0.314 s
c) 3.18 s
d) 20 s
Explanation: This problem connects rotational kinetic energy with Periodic motion of a rotating wheel. The kinetic energy of a rotating system depends on its moment of inertia and angular velocity. Once angular velocity is determined from energy and inertia, it can be related to time period, since angular velocity describes how fast the object completes one rotation. The time period is the time required for one full revolution and is inversely related to angular velocity. This relationship links energy stored in rotation to how quickly the system completes cycles of motion. A higher angular speed means shorter time period and greater kinetic energy for the same inertia. The problem highlights how energy, inertia, and Periodic motion are interconnected in Rotational Dynamics.
Option b – 0.314 s
A Solid spherical ball of mass 1 kg and radius 3 cm rotates about an axis through its centre with an angular velocity of 50 rad/s. What is its rotational kinetic energy?
a) 4500 J
b) 90 J
c) 9/8 J
d) 9/20 J
Explanation: This question involves rotational kinetic energy of a Solid sphere, which depends on how its mass is distributed relative to the axis of rotation. For a Solid sphere, the moment of inertia is determined by both mass and radius, reflecting that most of the mass is concentrated at varying distances from the axis. Rotational kinetic energy is then calculated using this inertia and the square of angular velocity. Since angular velocity is quite high, even a small object can store significant rotational energy. The radius plays a crucial role because inertia depends on the square of distance from the axis. This problem shows how geometry and rotation speed combine to determine energy stored in spinning rigid bodies.
Option d – 9/20 J
A sphere rotating about its diameter has rotational kinetic energy equal to 360 J. If its angular speed is 30 rad/s, what is its moment of inertia?
a) 0.4 kg·m²
b) 0.6 kg·m²
c) 0.8 kg·m²
d) 1.2 kg·m²
Explanation: This problem works backward from rotational kinetic energy to determine moment of inertia. Rotational kinetic energy depends directly on inertia and the square of angular velocity. When energy and angular speed are known, inertia can be found by rearranging the energy relationship. The sphere rotates about its diameter, meaning the axis passes through its center, and mass distribution around this axis determines its resistance to rotational change. A higher moment of inertia means the object stores more energy for the same angular speed. This concept is useful in understanding how different rigid bodies respond to rotation depending on their shape and mass distribution. The relationship between energy and angular velocity is fundamental in rotational mechanics.
Option c – 0.8 kg·m²
A flywheel is a uniform circular disc of radius 1 m and mass 2 kg. What approximate work must be done to increase its rotational frequency from 5 rev/s to 10 rev/s?
a) 1.5 × 10² J
b) 3.0 × 10² J
c) 1.5 × 10³ J
d) 3.0 × 10³ J
Explanation: This problem is based on the work–energy principle in rotational motion. When the rotational frequency of a flywheel increases, its angular velocity increases, leading to an increase in rotational kinetic energy. The work done on the system is equal to the change in its stored rotational energy. A uniform disc has its mass distributed evenly, giving a specific form of moment of inertia based on its mass and radius. As frequency doubles, angular speed also doubles, and since kinetic energy depends on the square of angular velocity, the energy increases significantly. This increase represents the extra work required to spin the disc faster against its inertia. The concept highlights how energy requirements grow rapidly with rotational speed in mechanical systems.
Option c – 1.5 × 10³ J
A wheel of mass 2 kg has almost all its mass concentrated at the rim of a circle of radius 20 cm. If it rotates with an angular speed of 100 rad/s, what is its rotational kinetic energy?
a) 4 J
b) 70 J
c) 400 J
d) 800 J
Explanation: This question deals with a rim-type rotating body, where most of the mass is concentrated at the outer edge. Such a system has a large moment of inertia because all mass is located far from the axis of rotation. Rotational kinetic energy depends on this inertia and the square of angular speed. Since angular speed is high, the energy stored in the system increases significantly. The distribution of mass plays a key role here because placing mass at the rim increases resistance to rotational change. This makes rim-type wheels effective for storing rotational energy, as seen in flywheels. The problem highlights the strong influence of mass distribution and angular velocity on rotational energy.
Option c – 400 J
We covered all the engineering Physics by amal chakraborty above in this post for free so that you can practice well for the exam.
My name is Vamshi Krishna and I am from Kamareddy, a district in Telangana. I am a graduate and by profession, I am an android app developer and also interested in blogging.