Which of the following expresses the equation for Gibbs free energy?
a) dQ = dV + dW
b) dH = TdS + VdP
c) dU = TdS – PdV
d) dH = TdS + VdP
Explanation: This question asks about the mathematical relationship used to define Gibbs free energy in Thermodynamics. Gibbs free energy is a very important concept because it helps scientists predict whether a physical or chemical process can occur naturally under constant temperature and pressure conditions. It combines the effects of Heat, entropy, and internal energy into a single useful quantity.
In Thermodynamics, different equations describe how energy changes inside a system. Some equations represent internal energy, some represent enthalpy, and others describe Heat transfer or work done. Gibbs free energy is specially designed to explain the maximum useful work obtainable from a process when temperature and pressure remain constant. To identify the correct relation, one must carefully examine which thermodynamic variables are involved and how entropy and pressure-volume terms appear together.
For example, when ice melts into water or when a chemical reaction proceeds on its own, Gibbs free energy helps determine whether the process is favorable. It acts like an energy balance that decides the direction of natural change.
Overall, the question checks understanding of thermodynamic equations and the role of Gibbs free energy in determining spontaneity and useful energy transformations in physical systems.
Option d – dH = TdS + VdP
A blackbody is placed in a vacuum at 27°C. What is the ratio of the radiation rate when its temperature rises to 527°C compared to when it is at 127°C?
a) 21 : 23
b) 23 : 1
c) 23 : 14
d) 4 : 221
Explanation: This question focuses on thermal radiation emitted by a blackbody and how the radiation rate changes with temperature. A blackbody is an ideal object that absorbs all incoming radiation and emits energy perfectly according to its temperature. The amount of energy radiated depends strongly on temperature, making this an important concept in Heat transfer and modern Physics.
The governing principle here is the Stefan–Boltzmann law, which states that the radiation emitted per unit area is proportional to the fourth power of the absolute temperature. Because of this fourth-power dependence, even a moderate increase in temperature can produce a very large increase in emitted radiation. To solve such problems correctly, temperatures must first be converted from Celsius to Kelvin before comparing the radiation rates.
A common analogy is comparing a dim red-hot metal rod with a bright white-hot filament. As temperature increases, the emitted energy rises dramatically rather than gradually. This is why furnaces, stars, and heated objects become intensely radiant at high temperatures.
In summary, the question examines the relationship between temperature and radiation intensity using blackbody radiation laws and emphasizes the importance of absolute temperature scales in Thermodynamics.
Option b – 23 : 1
Which thermodynamic quantity indicates the portion of Heat that can be converted into useful work?
a) Helmholtz free energy
b) Gibbs free energy
c) H + G
d) F + G
Explanation: This question examines which thermodynamic quantity represents the usable part of Heat energy that can be transformed into mechanical or useful work. In Thermodynamics, not all supplied Heat can be completely converted into work because some energy is always unavailable due to entropy and system limitations. Scientists therefore use special energy functions to measure the practically usable portion.
Different thermodynamic quantities describe energy in different forms. Internal energy represents total microscopic energy, enthalpy includes pressure-volume effects, while free energy functions describe the energy available for useful work. The required quantity is especially important in chemical reactions, industrial engines, biological systems, and electrochemical cells operating at constant temperature and pressure conditions.
A useful analogy is a rechargeable battery. Although the battery stores total energy, only a certain fraction can be effectively delivered to operate devices. Similarly, thermodynamic systems contain total Heat energy, but only part of it becomes practically available for productive work.
Overall, the question checks understanding of energy availability in Thermodynamics and the distinction between total heat content and the fraction that can actually perform useful external work in real physical processes.
Option b – Gibbs free energy
Which option reflects the part of internal energy that is available to perform work?
a) Enthalpy
b) Gibbs free energy
c) Total energy
d) Helmholtz free energy
Explanation: This question focuses on identifying the thermodynamic quantity that measures the usable fraction of a system’s internal energy. In physical systems, total internal energy contains both usable and unusable components. Because entropy reduces the amount of energy that can be fully transformed into work, Thermodynamics introduces special functions to describe the practically available energy.
When a system operates under controlled conditions, such as constant temperature or constant pressure, scientists use different free energy functions to determine how much work can be extracted. These functions are widely used in Chemistry, engineering, and Physics to predict whether processes like reactions, melting, evaporation, or electrical energy production can occur efficiently.
Consider a water reservoir behind a dam. Although the reservoir stores a huge quantity of water, only the water flowing through turbines can generate Electricity. Similarly, not every part of internal energy can perform useful work because some remains unavailable due to thermodynamic restrictions.
In summary, the question evaluates understanding of the relationship between internal energy and useful work, highlighting how thermodynamic free energy concepts help determine the practical energy obtainable from a system.
Option d – Helmholtz free energy
At what temperature does Gibbs free energy become zero?
a) T = H/S
b) T = S/H
c) T = SH
d) T = S + H
Explanation: This question explores the condition under which Gibbs free energy becomes zero. Gibbs free energy is a thermodynamic function that predicts whether a process or reaction will occur naturally. Its value depends mainly on enthalpy, entropy, and temperature. When the free energy becomes zero, the system reaches a special balance condition where opposing tendencies are equal.
The mathematical relationship for Gibbs free energy contains temperature multiplied by entropy, along with enthalpy terms. Setting the free energy equal to zero creates an equilibrium condition from which the required temperature relationship can be determined. Such conditions are important in phase changes, chemical equilibrium, and reversible reactions where no NET spontaneous change occurs.
An everyday analogy is a tug-of-war match where both teams pull with equal force. Since neither side dominates, the rope remains stationary. Similarly, when energetic and entropic effects balance perfectly, the free energy becomes zero and the system reaches equilibrium.
Overall, the question checks conceptual understanding of equilibrium conditions in Thermodynamics and how temperature influences the balance between enthalpy and entropy contributions in Gibbs free energy equations.
Option a – T = H/S
What happens to the boiling point of a liquid when the external pressure increases?
a) It rises
b) It remains unchanged
c) It falls
d) None of the above
Explanation: This question examines how external pressure affects the boiling point of a liquid. Boiling occurs when the vapor pressure of a liquid becomes equal to the surrounding external pressure. Since boiling depends on this pressure balance, changing the outside pressure directly changes the temperature at which boiling begins.
When external pressure becomes larger, liquid molecules require more energy to escape into the vapor phase. As a result, the liquid must be heated to a higher temperature before its vapor pressure matches the increased external pressure. This principle explains why cooking conditions vary at different altitudes and in pressure cookers.
For instance, water boils at a lower temperature on mountains because atmospheric pressure is smaller there. In contrast, inside a pressure cooker the pressure is higher, so water reaches a higher boiling temperature and Food cooks faster. The boiling point therefore depends strongly on surrounding pressure conditions rather than being a fixed value.
In summary, the question tests understanding of vapor pressure and phase transitions, emphasizing how external pressure controls the temperature required for a liquid to change into vapor.
Option a – It rises
Identify the correct formula that represents enthalpy:
a) H = PV
b) H = U
c) H = U + PV
d) H = QUT
Explanation: This question asks about the thermodynamic expression used to define enthalpy. Enthalpy is an important state function that represents the total heat content of a system under constant pressure conditions. It combines internal energy with the energy associated with pressure and volume, making it especially useful in Chemistry and engineering calculations.
Internal energy alone describes microscopic kinetic and potential energies within a system. However, when a system expands or contracts against external pressure, additional energy related to pressure-volume work must also be considered. Enthalpy therefore includes both the internal energy and the contribution arising from pressure and volume together.
A simple example is steam inside a boiler. The energy of steam is not only due to Molecularmotion but also due to the work required to occupy space against surrounding pressure. Enthalpy accounts for both effects simultaneously, which is why it is widely used in heat transfer and chemical reaction studies.
Overall, the question evaluates understanding of thermodynamic state functions and the relationship between internal energy, pressure, and volume in defining the total heat content of a system.
Option c – H = U + PV
We covered all the heat and thermodynamics mcqs above in this post for free so that you can practice well for the exam.
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