Explanation: X-rays are high-energy electromagnetic waves with extremely small wavelengths, so their measurement requires methods based on wave behaviour rather than direct detection. In Physics, wavelength determination for such radiation is commonly achieved using Diffraction techniques, where the wave interacts with a regularly spaced Atomic Structure. Crystals act as natural Diffraction gratings because their atomic planes are arranged in a Periodic pattern. When X-rays strike these planes, they are reflected at specific angles that depend on the spacing between the planes and the wavelength of the radiation. By analysing these angles of constructive interference, the wavelength can be calculated using a fundamental relationship between angle, spacing, and wavelength. This approach is widely used in spectroscopy and crystallography to study atomic structures and radiation properties. The focus is on wave interference patterns rather than particle detection or acceleration mechanisms.
Option c – Bragg spectrometer
A photon of X-ray has energy of 1 keV. A photon of visible radiation has energy of 3 eV. In this context, which one of the following statement(s) is/are not correct?
(a) The wavelength of X-ray photon is less than the wavelength of visible radiation photon.
(b) Both the photons have different energies.
(c) The speeds of both the photons in vacuum are different.
(d) The frequency of X-ray photon is higher than the frequency of visible radiation photon.
Explanation: Photons are discrete packets of electromagnetic energy, and their energy is directly related to frequency and inversely related to wavelength. Radiation across the electromagnetic Spectrum differs in energy levels, which leads to differences in wavelength and frequency characteristics. Higher energy radiation corresponds to shorter wavelengths and higher frequencies, while lower energy radiation has longer wavelengths and lower frequencies. Despite these differences, all electromagnetic waves travel at the same speed in vacuum, independent of their energy or frequency. This constant speed is a fundamental property of Light in free space. The relationships between energy, frequency, and wavelength form the basis of quantum theory and help explain how different regions of the electromagnetic Spectrum behave differently while still obeying the same propagation rules.
Option c – The speeds of both the photons in vacuum are different
Infrared, visible, and ultraviolet radiations/lights have different properties. Which one of the following statements related to these radiations/lights is not correct?
(a) The wavelength of infrared is more than that of ultraviolet radiation.
(b) The wavelength of ultraviolet is smaller than that of visible Light.
(c) The photon energy of visible Light is more than that of infrared Light.
(d) The photon energy of ultraviolet is less than that of visible Light.
Explanation: Electromagnetic radiation spans a wide Spectrum, and different regions such as infrared, visible, and ultraviolet differ mainly in wavelength, frequency, and energy. As we move from infrared to visible to ultraviolet, the wavelength decreases while frequency and energy increase. Infrared radiation has longer wavelengths and lower energy compared to visible Light, while ultraviolet radiation has shorter wavelengths and higher energy than visible Light. These relationships are governed by the fundamental wave equation connecting speed, frequency, and wavelength. All electromagnetic waves travel at the same speed in vacuum, but their energy content varies depending on frequency. These differences explain why infrared is associated with Heat effects, visible Light with vision, and ultraviolet with higher-energy interactions such as fluorescence and potential biological effects. The key idea is understanding how position in the Spectrum determines physical properties consistently.
Option d – The photon energy of ultraviolet is less than that of visible Light
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