Explanation: A nucleotide is a fundamental building block of nucleic Acids such as DNA and RNA. It is composed of three essential components that work together to store and transmit genetic information in Living Organisms. These components include a nitrogenous Base, a five-carbon sugar, and a phosphate group. The sugar forms the central backbone, while the Base carries genetic coding information, and the phosphate group links nucleotides together to form long chains.
In MolecularBiology, understanding how these units assemble is crucial because nucleotides polymerize through phosphodiester bonds, creating the structural framework of DNA and RNA. The arrangement and type of Base determine genetic coding, while the sugar-phosphate backbone provides stability and directionality to the nucleic Acid strand. These interactions are highly specific and essential for replication, transcription, and translation processes.
Structurally, each component contributes uniquely: the sugar connects to both the Base and phosphate, the phosphate forms bonds with adjacent sugars, and the Base participates in complementary pairing. This coordinated structure ensures accurate genetic storage and expression in biological systems.
Overall, a nucleotide represents a tri-component Molecular unit that serves as the foundation of genetic material and plays a central role in Heredity and protein synthesis.
How do D-glucose and D-fructose differ in their open-chain forms?
a) They differ in the position of the hydroxyl group on carbon 5
b) Glucose is an aldose, while fructose is a ketose
c) Glucose contains more hydrogen and less oxygen compared to fructose
d) Glucose has five –OH groups, while fructose has only four
Explanation: Monosaccharides such as D-glucose and D-fructose are simple sugars that differ in their structural arrangement, even though they share the same Molecular formula. Their open-chain forms vary primarily in the position and type of functional group present, which influences their chemical behavior and classification in carbohydrate Chemistry.
In carbohydrate structure, D-glucose belongs to the aldose group because it contains an aldehyde functional group at one end of its carbon chain. In contrast, D-fructose belongs to the ketose group because it contains a ketone functional group, typically located at the second carbon Atom. This difference affects how each sugar reacts in oxidation, reduction, and ring formation processes.
These structural variations also influence their behavior in biochemical reactions and metabolic pathways. For example, enzymes in living systems recognize these subtle differences, allowing specific pathways for energy production and storage. Although both can exist in cyclic forms in aqueous solution, their open-chain configurations determine their classification and reactivity.
Thus, the key distinction lies in the nature and position of the carbonyl group within their structures, which leads to different chemical properties despite their similar Molecular composition.
Option b – Glucose is an aldose, while fructose is a ketose
Which vitamin dissolves in water?
a) Vitamin A
b) Vitamin E
c) Vitamin B
d) Vitamin D
Explanation: Vitamins are Organic compounds required in small amounts for normal metabolic functions in the body. They are broadly classified based on their solubility in either fat or water, which also determines how they are absorbed, stored, and excreted in the human body. Water-soluble vitamins generally include those that dissolve easily in aqueous environments and are not stored in large quantities, requiring regular dietary intake.
These vitamins typically travel freely in body fluids and participate in key biochemical reactions, especially those related to energy metabolism and enzyme function. Because they are not stored extensively, excess amounts are usually excreted through urine, reducing the risk of toxicity compared to fat-soluble vitamins.
Water solubility also influences their physiological role, as they often act as coenzymes or coenzyme precursors in metabolic pathways. Their daily replenishment is essential for maintaining proper cellular functions and overall Health.
Thus, the concept of solubility plays a major role in understanding vitamin classification and biological availability.
Option c – Vitamin B
Which amino Acid has an oxygen Atom in its R group?
a) Serine
b) Isoleucine
c) Methionine
d) Cysteine
Explanation: Amino Acids are Organic molecules that serve as the building blocks of proteins. Each amino Acid contains a central carbon Atom bonded to an amino group, a carboxyl group, a hydrogen Atom, and a variable side chain known as the R group. The chemical nature of the R group determines the properties of each amino Acid, including polarity, reactivity, and ability to form hydrogen bonds.
Some amino Acids contain heteroatoms such as oxygen, sulfur, or nitrogen in their side chains, which significantly influences their chemical behavior. The presence of oxygen in the R group generally increases polarity and allows participation in hydrogen Bonding, making the amino Acid more reactive in biological systems.
Such structural features are important in protein folding, enzyme activity, and Molecular interactions. The side chain composition ultimately determines whether an amino Acid is hydrophilic or hydrophobic and how it contributes to protein structure.
Thus, the identification of oxygen-containing side chains is based on recognizing functional groups present in the R group.
Option a – Serine
Which compound contains the element cobalt?
a) Hemoglobin
b) Chlorophyll
c) Vitamin B12
d) Vitamin C
Explanation: Certain biological molecules require metal ions as part of their structure to perform essential physiological functions. These molecules are known as metallobiomolecules, where a metal ion is centrally coordinated within an Organic framework. The metal often plays a crucial role in catalytic activity, electron transfer, or structural stability.
Cobalt is a trace element that is biologically significant because it forms part of a vital vitamin structure required for red blood cell formation and neurological function. In such compounds, cobalt is chemically bonded within a complex Organic ring system, enabling it to participate in enzymatic reactions and metabolic pathways.
The presence of cobalt in biological molecules highlights the importance of trace elements in Nutrition and metabolism. Even in very small quantities, these elements are essential for maintaining normal physiological processes.
Explanation: Glucose is a monosaccharide that can exist in open-chain and cyclic forms. In its open-chain form, it contains an aldehyde group that is chemically reactive and can undergo addition reactions with reagents such as hydroxylamine. However, when glucose is fully converted into derivatives like pentaacetate, its reactive groups may be protected or involved in stable cyclic structures.
Hydroxylamine typically reacts with free carbonyl groups to form oximes, which is a characteristic test for aldehydes and ketones. If a glucose derivative does not respond to this reaction, it indicates that the carbonyl group is not available in a free form.
This lack of reactivity suggests that the Molecule exists predominantly in a cyclic structure where the aldehyde group is no longer free but involved in ring formation as a hemiacetal. Such structural changes significantly reduce its chemical reactivity compared to the open-chain form.
Therefore, the behavior in this reaction provides insight into the structural state of glucose derivatives in solution.
Option b – It lacks a free aldehyde group
How many among sucrose, maltose, lactose, glucose, and cellobiose are non-reducing sugars?
a) One
b) Two
c) Three
d) Four
Explanation: Carbohydrates can be classified based on their ability to act as reducing agents, which depends on the presence of a free aldehyde or ketone group. Reducing sugars have a free anomeric carbon that can open into an aldehyde or ketone form, allowing them to participate in oxidation-reduction reactions.
Non-reducing sugars, on the other hand, do not possess a free anomeric carbon because it is involved in glycosidic Bonding. This prevents them from opening into a reactive carbonyl form, making them chemically less reactive in standard tests like Benedict’s or Fehling’s solution.
The classification of sugars in a mixture depends on identifying which molecules have their anomeric carbon blocked in bond formation and which retain a free reactive group.
Thus, understanding glycosidic linkage structure is essential for determining reducing and non-reducing behavior.
Option a – One
Which pair consists of aldose sugars?
a) Erythrulose and ribulose
b) Glucose and ribulose
c) Fructose and ribose
d) Galactose and ribose
Explanation: Monosaccharides are classified based on the type of carbonyl group they contain. Aldoses are sugars that contain an aldehyde group, typically at the terminal carbon, while ketoses contain a ketone group, usually at an internal carbon position. This structural difference plays a key role in their chemical behavior and classification.
The identification of aldose sugars depends on recognizing the presence of the aldehyde functional group in their open-chain form. This group makes them capable of undergoing oxidation reactions and forming characteristic cyclic structures in solution.
The position of the carbonyl group also influences the number of chiral centers and the overall stereochemistry of the Molecule. These structural differences are important in biochemical pathways where enzymes specifically recognize aldose or ketose forms.
Thus, classification relies on functional group identification within the carbohydrate structure.
Option d – Galactose and ribose
Assertion: Our body cannot store Vitamin K. Reason: Vitamin K is a fat-soluble vitamin.
a) Both Assertion and Reason are true, and Reason explains the Assertion
b) Both Assertion and Reason are true, but Reason doesn’t explain the Assertion
c) Assertion is true, Reason is false
d) Assertion is false, Reason is true
Explanation: Vitamins are classified based on their solubility, which affects how they are absorbed, transported, and stored in the human body. Fat-soluble vitamins are typically stored in liver and adipose tissues, while water-soluble vitamins are generally not stored and require frequent intake.
The storage capacity of vitamins depends on their chemical solubility and metabolic handling. Fat-soluble vitamins tend to accumulate in body tissues, whereas water-soluble ones are excreted more easily.
Understanding this distinction is important for evaluating nutritional requirements and potential deficiencies. The relationship between solubility and storage helps explain how the body regulates vitamin levels over time.
Explanation:Biomolecules such as proteins perform a wide range of structural and functional roles in Living Organisms. Proteins are long chains of amino Acids linked by peptide bonds and can be classified based on their structure and function. Some proteins serve enzymatic roles, while others provide structural support.
Structural proteins are responsible for maintaining the shape and strength of tissues. They are typically fibrous in nature, forming long, insoluble fibers that provide mechanical stability. These proteins are found in connective tissues, skin, tendons, and bones.
Their composition and arrangement of amino Acids give them high tensile strength and resistance to stretching, making them essential for structural integrity in Organisms.
Thus, protein classification depends on their biological role and structural characteristics.
Option b – Protein
Which statement correctly describes adenine and guanine?
d) Both contain two double bonds between carbon atoms
Explanation: Nitrogenous Bases are essential components of nucleic Acids such as DNA and RNA. They are broadly categorized into two types based on their chemical structure: purines and pyrimidines. Purines are characterized by a double-ring structure, while pyrimidines contain a single-ring structure. These structural differences influence how Bases pair and stabilize genetic material.
Adenine and guanine belong to the purine class of nitrogenous Bases. Their fused ring system allows them to participate in specific hydrogen Bonding interactions with complementary Bases in DNA and RNA. This pairing is highly specific and forms the basis of genetic coding and replication accuracy.
The arrangement of atoms in purine Bases also contributes to Molecular stability and recognition by enzymes involved in transcription and replication. These interactions ensure that genetic information is faithfully transmitted during cell division.
Thus, classification of nitrogenous Bases is based on their ring structure and role in nucleic Acid pairing mechanisms.
Option a – They are heterocyclic Bases with purine rings
Which carbohydrate plays a structural role in plant tissues?
a) Starch
b) Cellulose
c) Glucose
d) Glycogen
Explanation: Carbohydrates are Biomolecules that serve both energy storage and structural functions in Living Organisms. In plants, different polysaccharides perform specialized roles depending on their chemical structure and Bonding patterns. Structural carbohydrates are typically those that provide rigidity and support to plant cell walls.
These structural molecules are composed of long chains of glucose units linked by specific glycosidic bonds that are resistant to Digestion. This structural arrangement allows them to form strong fibrous networks that reinforce plant tissues and maintain cell shape.
In contrast, storage carbohydrates are more easily broken down to release energy. The difference in Bonding and structure determines whether a carbohydrate functions as structural support or energy reserve.
Thus, the role of a carbohydrate depends on its Molecular linkage and structural configuration within plant cells.
Option b – Cellulose
Which of the following responds positively to the phthalein test?
a) Leucine
b) Lysine
c) Serine
d) Tyrosine
Explanation:Organic compounds containing specific functional groups such as phenolic hydroxyl groups can undergo characteristic color reactions with reagents like phthalein indicators. These tests are often used to identify compounds based on their chemical reactivity and structural features.
A positive phthalein test generally indicates the presence of aromatic structures with hydroxyl groups capable of forming colored complexes under alkaline conditions. The intensity and nature of the color change depend on the Molecular structure and position of substituents on the aromatic ring.
Such reactions are widely used in qualitative Organic analysis to distinguish between different classes of Biomolecules, especially amino Acids and phenolic compounds.
Thus, the test is based on structural reactivity involving aromatic hydroxyl-containing molecules.
Option d – Tyrosine
Deficiency of which vitamin causes tongue inflammation and cheilosis?
a) Vitamin A
b) Thiamine
c) Riboflavin
d) Ascorbic acid
Explanation: Vitamins play a critical role in maintaining normal metabolic and physiological functions in the human body. Deficiency of certain vitamins can lead to specific clinical symptoms affecting skin, mucous membranes, and energy metabolism.
Some vitamins are essential for maintaining healthy epithelial tissues, and their deficiency may result in inflammation of the tongue, cracks at the corners of the mouth, and other mucocutaneous disorders. These symptoms arise due to impaired cellular metabolism and reduced enzymatic activity.
Water-soluble vitamins, particularly those involved in coenzyme formation, are often linked with such deficiency symptoms because they are required for continuous metabolic reactions.
Thus, vitamin deficiency disorders can be diagnosed based on characteristic clinical manifestations in the body.
Option c – Riboflavin
What is the process by which RNA directs the production of proteins in Living Organisms?
a) Transcription
b) Mutation
c) Replication
d) Translation
Explanation: Protein synthesis is a fundamental biological process in which genetic information stored in nucleic Acids is converted into functional proteins. This process involves multiple steps, including the transfer of genetic code from nucleic Acids to amino acid sequences.
RNA plays a central role in carrying genetic instructions from DNA and facilitating their interpretation at the ribosomal level. During this process, messenger RNA provides a template, transfer RNA brings amino Acids, and ribosomal RNA forms the structural and catalytic core of the ribosome.
This coordinated mechanism ensures that amino acids are assembled in a specific order dictated by the genetic code, resulting in the formation of functional proteins required for cellular activities.
Thus, protein synthesis depends on accurate decoding and assembly of genetic information through RNA-mediated processes.
Option d – Translation
What does the primary structure of a protein represent?
a) Denatured protein and its prosthetic group structure
b) Three-dimensional arrangement involving distant amino acid interactions
c) The sequence of amino acids in a polypeptide chain
d) Repetitive folding segments of the polypeptide chain
Explanation: Proteins are complex Biomolecules composed of amino acid chains that fold into specific three-dimensional shapes. Their structure is organized into different levels, each contributing to their final shape and function. The primary structure is the most fundamental level of protein organization.
It refers to the specific sequence in which amino acids are linked together in a polypeptide chain through peptide bonds. This linear arrangement determines how the protein will fold into secondary, tertiary, and quaternary structures.
Even a small change in this sequence can significantly alter the protein’s properties and biological function. The primary structure is therefore crucial for determining protein identity and activity.
Thus, protein structure begins with the precise ordering of amino acids in a chain.
Option c – The sequence of amino acids in a polypeptide chain
How many peptide bonds are present in a pentapeptide?
a) 3
b) 4
c) 5
d) 6
Explanation: Peptides are short chains of amino acids linked together by peptide bonds, which form through a condensation reaction between the amino group of one amino acid and the carboxyl group of another. The number of peptide bonds depends on the number of amino acids present in the chain.
In a linear peptide chain, each bond connects two adjacent amino acids. Therefore, the total number of peptide bonds is always one less than the number of amino acid residues in the chain.
This relationship is important in understanding protein structure and the formation of polypeptide chains during protein synthesis.
Thus, peptide bond count is directly determined by amino acid chain length.
Option b – 4
What is the prosthetic group found in glycoproteins?
a) Lipid
b) Carbohydrate
c) Protein
d) Nucleic acid
Explanation: Conjugated proteins consist of a protein component combined with a non-protein component known as a prosthetic group. These groups are essential for the biological function of the protein and may include carbohydrates, lipids, or metal ions depending on the type of conjugated protein.
Glycoproteins specifically contain carbohydrate moieties attached to the polypeptide chain. These carbohydrate groups play important roles in cell recognition, signaling, and stability of protein structures.
The presence of carbohydrate units influences how glycoproteins interact with other molecules and participate in biological processes such as immune response and cell Communication.
Thus, glycoprotein structure is defined by the attachment of carbohydrate-based prosthetic groups to proteins.
Option b – Carbohydrate
Which of the following amino acids is neutral?
a) Glutamic acid
b) Valine
c) Histidine
d) Lysine
Explanation: Amino acids can be classified based on the nature of their side chains, which determine their charge and chemical behavior in physiological conditions. Some amino acids carry acidic side chains, others carry basic side chains, while some remain neutral.
Neutral amino acids have side chains that do not significantly ionize at physiological pH. As a result, they do not carry a strong positive or negative charge and generally exhibit balanced chemical properties.
This neutrality affects their role in protein structure and function, particularly in regions where charge interactions are not required.
Thus, classification depends on the ionization behavior of the amino acid side chain.
Option b – Valine
Identify the carbohydrate that yields only glucose upon hydrolysis.
a) Stachyose
b) Lactose
c) Cellulose
d) Raffinose
Explanation: Polysaccharides and disaccharides are carbohydrates composed of monosaccharide units linked by glycosidic bonds. Upon hydrolysis, these bonds are broken to release their constituent monosaccharides. The type of monosaccharide produced depends on the original structure of the carbohydrate.
Some carbohydrates are homopolysaccharides, meaning they are composed of only one type of monosaccharide unit. When hydrolyzed, they yield a single type of sugar, such as glucose.
This structural uniformity is important in determining their biological function, particularly in energy storage and structural roles in Organisms.
Thus, hydrolysis products reflect the monosaccharide composition of the parent carbohydrate.
Option c – Cellulose
Which vitamin is categorized under the aromatic series based on structure?
a) Vitamin A
b) Vitamin K
c) Vitamin C
d) Vitamin B₁
Explanation: Vitamins are Organic compounds classified based on their solubility and structural characteristics. Some vitamins contain ring systems that resemble aromatic compounds, which are stable cyclic structures with delocalized electrons. These structural features influence their chemical stability and biological activity.
Aromatic-like vitamins often contain conjugated ring systems that allow them to participate in electron-related biochemical reactions. Their structure affects how they interact with enzymes and participate in metabolic pathways. Such vitamins are also important in redox reactions and cellular protection mechanisms.
The classification based on structural similarity helps in understanding how these vitamins behave chemically in biological systems. Their aromatic nature contributes to stability and functional specificity in physiological processes.
Thus, structural arrangement plays a key role in vitamin classification and biological function.
Option b – Vitamin K
From the following, which compounds can exist as zwitterions? I. Glycine II. Sulphanilic acid III. Benzoic acid
a) I, II and III
b) I and II
c) II and III
d) I and III
Explanation: Zwitterions are molecules that contain both positive and negative charges within the same structure but are overall electrically neutral. This property is commonly observed in amino acids, which contain both acidic (carboxyl) and basic (amino) functional groups.
At certain pH levels, amino acids undergo internal proton transfer, resulting in a dipolar ion form. This structure plays a crucial role in their behavior in solution, including solubility, melting point, and electrophoretic movement.
Other Organic acids may or may not form zwitterions depending on the presence of both proton-donating and proton-accepting groups within the same Molecule. The ability to form this internal ionic structure is important in biochemical systems.
Thus, zwitterion formation depends on the presence of both acidic and basic functional groups within a Molecule.
Option b – I and II
Which amino acid forms a yellow oily N-nitrosoamine when treated with cold HNO₂?
a) Alanine
b) Proline
c) Isoleucine
d) Valine
Explanation: Amino acids react differently with nitrous acid depending on their side chain structure and the nature of their amino group. Primary amino acids typically undergo deamination, releasing nitrogen gas, while secondary amino acids behave differently due to their cyclic or substituted nitrogen structures.
Certain amino acids with secondary amino groups can form nitroso derivatives rather than undergoing simple deamination. These reactions produce characteristic oily compounds with distinct coloration, which are used for identification purposes in OrganicChemistry.
The formation of such derivatives depends on the presence of specific structural features in the amino acid Molecule that allow nitrosation reactions to occur.
Thus, reaction behavior with nitrous acid is determined by amino group structure and Molecular configuration.
Option b – Proline
Which amino acid(s) has a very low isoelectric point (below 5)? I. Histidine II. Aspartic acid III. Glutamic acid IV. Arginine
a) I and II
b) II and III
c) III and IV
d) I and IV
Explanation: The isoelectric point of an amino acid is the pH at which it carries no NET electrical charge. This value depends on the presence of acidic or basic side chains within the amino acid structure.
Amino acids with acidic side chains tend to have lower isoelectric points because they release protons more easily, resulting in a NET negative charge at lower pH values. These structural properties influence their behavior in electrophoresis and biochemical reactions.
The balance between acidic and basic groups determines how the amino acid behaves in different pH environments. Understanding these properties is important in protein Chemistry and separation techniques.
Thus, isoelectric point variation depends on side chain acidity and ionization behavior.
Option b – II and III
When glucose is heated with HI, it forms compound X. When reacted with hydroxylamine, it gives compound Y. What are X and Y?
a) X = n-Hexane; Y = Glucoxime
b) X = n-Hexane; Y = Gluconic acid
c) X = Gluconic acid; Y = n-Hexane
d) X = Glucoxime; Y = Gluconic acid
Explanation: Glucose is a hexose sugar that can undergo different chemical reactions depending on the reagents used. Strong reducing agents like hydrogen iodide can completely reduce all functional groups in glucose, leading to a straight-chain hydrocarbon structure.
On the other hand, reaction with hydroxylamine typically targets carbonyl groups, forming oxime derivatives. However, glucose in cyclic or open-chain forms may react differently depending on availability of the reactive carbonyl group.
These reactions are used to study structural features of carbohydrates and confirm the presence or absence of reactive functional groups.
Thus, different reagents help identify structural transformations in carbohydrate Chemistry.
Option a – X = n-Hexane; Y = Glucoxime
Which compound resembles amylopectin in structure but is more highly branched?
a) Cellulose
b) Lactose
c) Cellobiose
d) Glycogen
Explanation: Polysaccharides are large carbohydrate molecules composed of many glucose units linked together. Their structure may be linear or branched depending on the type of glycosidic bonds present.
Amylopectin is a branched polysaccharide that serves as a storage form of energy in plants. Some polysaccharides have a similar glucose-based structure but contain a higher degree of branching, which affects their compactness and digestibility.
Increased branching allows for faster enzymatic breakdown and more efficient energy release. Structural differences in branching patterns play a key role in biological energy storage systems.
Thus, polysaccharide function is strongly influenced by the degree of branching in its molecular structure.
Option d – Glycogen
How many carbon atoms are present in a raffinose Molecule?
a) 6
b) 12
c) 18
d) 24
Explanation: Raffinose is a trisaccharide composed of different monosaccharide units linked through glycosidic bonds. Each monosaccharide contributes a specific number of carbon atoms to the overall structure.
Carbohydrate composition analysis involves summing the carbon atoms from each constituent sugar unit. The glycosidic linkage forms through condensation reactions, but the total carbon count remains unchanged in the final Molecule.
Understanding molecular composition helps in determining the structural formula and biochemical behavior of complex carbohydrates.
Thus, the total carbon content is derived from the combined monosaccharide units forming the oligosaccharide.
Option c – 18
Which of the following is an essential amino acid?
a) Alanine
b) Methionine
c) Aspartic acid
d) Proline
Explanation: Amino acids are classified based on whether the human body can synthesize them or not. Essential amino acids are those that must be obtained through diet because they cannot be synthesized in sufficient quantities by the body.
These amino acids are crucial for protein synthesis, tissue repair, and enzyme production. Their absence in the diet can lead to metabolic disorders and impaired physiological functions.
The classification of amino acids into essential and non-essential is important in nutritional science and diet planning.
Thus, essential amino acids are dietary requirements necessary for maintaining normal body functions.
Option b – Methionine
How much water is used during acid hydrolysis of 1.368 kg of maltose? (Molar Mass: maltose = 342, water = 18, density of water = 1 g/cm³)
a) 0.072 dm³
b) 0.720 dm³
c) 0.18 dm³
d) 0.018 dm³
Explanation: Hydrolysis reactions involve breaking chemical bonds using water molecules. In carbohydrates like disaccharides, glycosidic bonds are cleaved by the addition of water under acidic conditions, resulting in monosaccharide formation.
The amount of water required depends on the number of glycosidic bonds present in the given Mass of carbohydrate. Each bond consumes one Molecule of water during hydrolysis.
Stoichiometric calculations are used to relate Mass, molar Mass, and number of molecules involved in the reaction. This allows determination of reagent consumption in biochemical reactions.
Thus, hydrolysis efficiency is determined by bond count and molecular proportions.
Option a – 0.072 dm³
Identify the substance that is NOT a hormone.
a) Threonine
b) Thyroxine
c) Adrenaline
d) Androsterone
Explanation: Hormones are chemical messengers produced by endocrine glands that regulate physiological processes such as metabolism, growth, and reproduction. They are typically secreted into the bloodstream and act on specific target organs.
Not all biological molecules function as hormones; some serve structural or metabolic roles instead. Hormones are characterized by their signaling function rather than structural or enzymatic activity.
Understanding the classification of Biomolecules helps distinguish between signaling compounds and other organic substances in the body.
Thus, hormonal activity is defined by regulatory and signaling roles in physiological systems.
Option a – Threonine
How many chiral centers are found in the open-chain forms of D-glucose and D-fructose?
a) 4 in each
b) 3 in each
c) 4 in glucose and 3 in fructose
d) 3 in glucose and 4 in fructose
Explanation: Chirality in organic molecules refers to the presence of carbon atoms bonded to four different groups, making them asymmetric. These chiral centers are responsible for optical activity in sugars and other Biomolecules.
In monosaccharides, the number of chiral centers depends on the arrangement of hydroxyl groups and the position of the carbonyl group. Aldoses and ketoses differ in the location of this functional group, which affects the total number of asymmetric carbons.
Chirality plays a major role in biochemical recognition, as enzymes are often specific to particular stereoisomers. This structural feature is crucial in metabolism and molecular interactions.
Thus, stereochemistry determines the optical properties and biological behavior of sugars.
Option c – 4 in glucose and 3 in fructose
All of the following are fibrous proteins except:
a) Fibroin
b) Keratin
c) Collagen
d) Insulin
Explanation: Proteins are classified based on their shape and solubility into fibrous and globular types. Fibrous proteins are elongated, insoluble molecules that provide structural support in tissues such as skin, hair, and connective tissue.
Globular proteins, in contrast, are more compact and generally soluble in water, performing functional roles such as catalysis and regulation. Enzymes and hormones typically fall into this category.
The classification depends on molecular folding patterns and biological function, which determine whether a protein provides structural support or metabolic activity.
Thus, protein shape and solubility are key factors in distinguishing fibrous from non-fibrous types.
Option d – Insulin
Which of the following amino acids lacks an aromatic ring?
a) Tyrosine
b) Phenylalanine
c) Tryptophan
d) Asparagine
Explanation: Amino acids are classified based on the structure of their side chains. Some contain aromatic rings such as benzene-like structures, which contribute to stability and specific interactions in proteins.
Aromatic amino acids participate in stacking interactions and absorb ultraviolet Light due to their ring systems. Others, however, lack such ring structures and instead have aliphatic or simple side chains.
The presence or absence of an aromatic ring significantly influences protein structure, folding, and chemical behavior.
Thus, side chain structure determines aromatic or non-aromatic classification in amino acids.
Option d – Asparagine
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