New Millennium Physics Class 9 for Students

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New Millennium Physics Class 9. We covered all the New Millennium Physics Class 9 in this post for free so that you can practice well for the exam.

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Millennium Physics Class 9 MCQs for Students

The biprism experiment is firstly arranged by :

In the biprism experiment, in order to determine the distance between two virtual sources, the convex lens should be placed between

The distance between the two coherent sources in the biprism experiment cannot be directly measured because they are :

In Young’s double slit experiment, one of the slits was covered by a glass plate with a refractive index of 1.5 and the other by an equally thick glass plate with a refractive index of 1.6. On the removal of the plates, the interference pattern shifted such that ten bright fringes moved across the cross-wires. If the wavelength of light used was 6000 A, the thickness of each plate will be :

In a biprism experiment, the distance between the slit and the biprism was kept at 20 cm and the distance between the biprism and the eyepiece was kept at 80 cm. The slit was illuminated by the light of wavelength 6000 Å. If each refracting angle of the biprism is 1° 30′ and the refractive index of its material is 1.52, the width of the fringes formed in the focal plane of the eyepiece is :

A beam of light of λ = 600 nm from a distant source falls on a single slit 1 mm wide and the resulting diffraction pattern is observed on a screen 2 m away. The distance between the first dark fringes on either side of the central bright fringe is

Biprism is formed by using :

The distance between two points A and B in the air is 10 cm. If a glass plate of thickness 0.1 mm is introduced between A and B, the optical length of the path between A and B becomes 10.005cm, and the refractive index of glass is :

In Young’s double slit experiment, when one of the slits was covered by a glass plate of refractive index 1.58, the cross-wires in the eyepiece moved from the central bright band to the fifth bright band. If the wavelength of light used was 5800 Å. thickness of the glass plate is :

When an interference pattern is obtained, the distance between the midpoint of the 5th dark band on one side and the 5th dark band on the other side of the central bright band is :

The central fringe of the interference pattern produced by the light of wavelength 6000 Aº is found to shift to the position of the 4th bright fringe after a glass plate of refractive index 1.5 is introduced. The thickness of the glass plate would be :

Millennium Physics Class 9 MCQs for Students

The biprism experiment is firstly arranged by :

(A) Fresnel

(B) Young

(D) Maxwell

Option a – Fresnel

In the biprism experiment, in order to determine the distance between two virtual sources, the convex lens should be placed between

(A) slit and eyepiece

(B) slit and biprism

(D) at any position

Option c – biprism and eyepiece

The distance between the two coherent sources in the biprism experiment cannot be directly measured because they are :

(A) virtual coherent sources

(B) virtual incoherent sources

(D) one real and the other acts as virtual

Option a – virtual coherent sources

In Young’s double slit experiment, one of the slits was covered by a glass plate with a refractive index of 1.5 and the other by an equally thick glass plate with a refractive index of 1.6. On the removal of the plates, the interference pattern shifted such that ten bright fringes moved across the cross-wires. If the wavelength of light used was 6000 A, the thickness of each plate will be :

(A) 60 microns

(B) 70 microns

(D) 90 microns

Option a – 60 microns

In a biprism experiment, the distance between the slit and the biprism was kept at 20 cm and the distance between the biprism and the eyepiece was kept at 80 cm. The slit was illuminated by the light of wavelength 6000 Å. If each refracting angle of the biprism is 1° 30′ and the refractive index of its material is 1.52, the width of the fringes formed in the focal plane of the eyepiece is :

(A) 0.01 mm

(B) 0.11 mm

(D) 0.33 mm

Option b – 0.11 mm

A beam of light of λ = 600 nm from a distant source falls on a single slit 1 mm wide and the resulting diffraction pattern is observed on a screen 2 m away. The distance between the first dark fringes on either side of the central bright fringe is

(A) 1.2 cm

(B) 2.4 cm

(D) 2.4 mm

Option d – 2.4 mm

Biprism is formed by using :

(A) two thick prisms

(B) two thin prisms

(D) neither thin nor thick prism

Option b – two thin prisms

The distance between two points A and B in the air is 10 cm. If a glass plate of thickness 0.1 mm is introduced between A and B, the optical length of the path between A and B becomes 10.005cm, and the refractive index of glass is :

(A) 1.3

(B) 1.4

(D) 1.6

Option c – 1.5

In Young’s double slit experiment, when one of the slits was covered by a glass plate of refractive index 1.58, the cross-wires in the eyepiece moved from the central bright band to the fifth bright band. If the wavelength of light used was 5800 Å. thickness of the glass plate is :

(A) 2 μm

(B) 3 um

(D) 5 μm

Option d – 5 μm

When an interference pattern is obtained, the distance between the midpoint of the 5th dark band on one side and the 5th dark band on the other side of the central bright band is :

(A) 4.5 times the bandwidth

(B) 9.5 times the bandwidth

(D) 10 times the bandwidth

Option c – 9 times the bandwidth

The central fringe of the interference pattern produced by the light of wavelength 6000 Aº is found to shift to the position of the 4th bright fringe after a glass plate of refractive index 1.5 is introduced. The thickness of the glass plate would be :

(A) 7.8 μm

(B) 4.8 μm

(D) 1.5 μm

Option b – 4.8 μm

We covered all the new millennium physics class 9 above in this post for free so that you can practice well for the exam.

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Millennium Physics Class 9 MCQs for Students

The biprism experiment is firstly arranged by :

In the biprism experiment, in order to determine the distance between two virtual sources, the convex lens should be placed between

The distance between the two coherent sources in the biprism experiment cannot be directly measured because they are :

A beam of light of λ = 600 nm from a distant source falls on a single slit 1 mm wide and the resulting diffraction pattern is observed on a screen 2 m away. The distance between the first dark fringes on either side of the central bright fringe is

Biprism is formed by using :

The distance between two points A and B in the air is 10 cm. If a glass plate of thickness 0.1 mm is introduced between A and B, the optical length of the path between A and B becomes 10.005cm, and the refractive index of glass is :

In Young’s double slit experiment, when one of the slits was covered by a glass plate of refractive index 1.58, the cross-wires in the eyepiece moved from the central bright band to the fifth bright band. If the wavelength of light used was 5800 Å. thickness of the glass plate is :

When an interference pattern is obtained, the distance between the midpoint of the 5th dark band on one side and the 5th dark band on the other side of the central bright band is :

The central fringe of the interference pattern produced by the light of wavelength 6000 Aº is found to shift to the position of the 4th bright fringe after a glass plate of refractive index 1.5 is introduced. The thickness of the glass plate would be :

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