Nootan Chemistry Class 12 Solutions. We covered all the Nootan Chemistry Class 12 Solutions MCQs in this post for free so that you can practice well for the exam.
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Nootan Chemistry Class 12 Objective with Solutions
Total number of benzene rings and nitrogen atoms present in p-rosaniline hydrochloride are:
(A) 3 benzene rings, 3 nitrogen atoms
(B) 3 benzene rings, 2 nitrogen atoms
(C) 4 benzene rings, 4 nitrogen atoms
(D) 4 benzene rings, 3 nitrogen atoms
Option a – 3 benzene rings, 3 nitrogen atoms
Which of the following cannot reduce Fehling solution?
(A) Methanal
(B) Ethanal
(C) Ethanoic acid
(D) Methanoic acid
Option c – Ethanoic acid
Which of the following is oxidized by ammonical silver nitrate?
(A) Alkoxy alkanes
(B) Alkanes
(C) Alkanols
(D) Alkanals
Option d – Alkanals
Schiff’s reagent on reacting with aldehyde forms a magenta color because of:
(A) Oxidation of alkanal
(B) Reduction of alkanal
(C) Reduction of Schiff’s reagent
(D) Oxidation of Schiff’s reagent
Option c – Reduction of Schiff’s reagent
The pink or red color of p-rosaniline hydrochloride is decolorized by passing:
(A) Carbon monoxide
(B) Sulfur trioxide
(C) Sulfur dioxide
(D) Carbon dioxide
Option c – Sulfur dioxide
Schiff’s reagent gives a magenta color with:
(A) Methyl ethanoate
(B) Ethanoic acid
(C) Propanone
(D) Ethanal
Option d – Ethanal
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