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    Over five years, the sales (in thousands) of Solvato Consultancy Pvt. Ltd., a gold dealership firm in Delhi, were 81,371, 59,287, 76,345, 92,854, and 74,143. What is the ratio of the highest sales to the lowest sales?

    a) 52

    b) 75

    c) 65

    d) 85

    e) None of these

    Explanation:
    The question is based on identifying the extreme values in a dataset and comparing them through a ratio. It requires observing a SET of five numerical sales figures and determining which represents the maximum and which represents the minimum. Such problems are commonly used in data interpretation to test how quickly and accurately one can extract key information from a group of numbers.

    To approach this, we first scan all the given sales values carefully and identify the largest value as the highest sales and the smallest value as the lowest sales. Once these two values are located, the next step is to compare them in proportional form. A ratio is used here because it expresses relative magnitude rather than absolute difference, making it easier to understand how much larger one value is compared to another.

    This type of question does not require complex calculations but demands careful observation and accuracy. A common mistake is misreading or misidentifying the highest or lowest values due to the closeness of numbers. Ensuring correct ordering is the most important step before forming any comparison.

    In summary, the problem focuses on extracting extreme values from a dataset and expressing their relationship in ratio form, which is a fundamental skill in quantitative data interpretation.

    Option b – 75

    Given the same sales data for Solvato Consultancy Pvt. Ltd., by how many lakhs did the second-highest sales exceed the second-lowest sales?

    a) 7.02

    b) 6.98

    c) 7.18

    d) 7.22

    e) None of these

    Explanation:
    The question deals with ranking a dataset and comparing two specific positional values: the second-highest and the second-lowest. It is a typical data interpretation problem that requires careful arrangement of numbers in order before performing any comparison. The focus is not just on extremes but on intermediate ranked values.

    To solve this conceptually, we first organize all the given sales figures in ascending or descending order. Once sorted, the second-highest value is identified just below the maximum, and the second-lowest value is identified just above the minimum. After identifying these two values, we compare them by finding their difference. Since the data is initially given in thousands, proper unit conversion into lakhs is necessary for correct interpretation.

    This kind of question is frequently asked in aptitude exams because it checks both sorting ability and attention to numerical detail. Even a small mistake in ordering can lead to selecting the wrong values, which changes the entire outcome. Therefore, careful step-by-step arrangement is crucial before any arithmetic operation.

    In summary, the problem focuses on ordered data analysis and comparison of middle-ranked extreme values, emphasizing accuracy in sorting and unit handling.

    Option b – 6.98

    When the price of a product decreased by 25%, a person increased their annual usage by 10%. What is the overall change in their yearly spending?

    a) -17.5

    b) 12.5

    c) -18.2

    d) -19.3

    e) None of these

    Explanation:
    This question deals with the combined effect of a change in price and a change in quantity consumed. It focuses on understanding how percentage changes in two related variables influence overall expenditure. Such problems are commonly solved using multiplicative factors rather than simple addition or subtraction of percentages.

    To approach this, we consider that total spending depends on both price and quantity. When price decreases, it reduces expenditure, but when usage increases, it raises expenditure. These two effects must be combined carefully. Instead of treating percentages independently, each change is converted into a multiplier. A decrease of 25% becomes 0.75, and an increase of 10% becomes 1.10. Multiplying these factors gives the NET effect on spending.

    This type of reasoning is important in quantitative aptitude because it tests conceptual understanding of proportional changes. Many students mistakenly add or subtract percentages directly, which leads to incorrect results. The correct method always involves sequential application of percentage change factors.

    In summary, the problem evaluates how two opposing percentage changes interact multiplicatively to determine the final effect on total expenditure, highlighting the importance of factor-based reasoning in percentage problems.

    Option b – 12.5

    A car moves at 56 km/h for 1.5 hours, then accelerates by 15%. How much time is needed to cover a total of 406 km?

    a) 6.4

    b) 6.8

    c) 7.2

    d) 6.5

    e) None of these

    Explanation:
    This question is based on distance-speed-time relationships combined with a change in speed after a certain duration. It requires understanding how total distance is split into two parts and how speed variation affects travel time. Such problems test logical breakdown of motion into segments.

    To approach this, we first compute the distance covered in the initial phase using constant speed and time. After this, the speed increases by a certain percentage, meaning the new speed is higher than the original. The remaining distance must be covered at this increased speed. The key idea is to divide the total journey into two parts and treat each segment separately.

    This type of question emphasizes careful organization of information. One must first determine how much distance is already covered before speed changes, then calculate what remains. After finding the remaining distance, time is calculated using the new speed. Mistakes often occur when students try to apply a single formula without segmenting the journey.

    In summary, the problem focuses on multi-stage motion analysis where distance is split into phases due to a change in speed, requiring structured application of speed-time-distance concepts.

    Option d – 6.5

    A earns 40% more than B, and B receives 30% less than C. If C earns 35% of D’s Income, then the combined Income of A and D is what percentage of the combined Income of B and D?

    a) 125

    b) 235

    c) 225

    d) 175

    e) 45

    Explanation:
    This question involves comparative Income relationships expressed through percentages. It requires converting relative statements into algebraic expressions and then comparing combined values. Such problems are common in ratio and proportion-based reasoning.

    To approach this, we assign a variable to one person’s Income and express all others in terms of it. Each percentage relation is converted into a multiplier form. For example, “40% more” becomes 1.40 times, and “30% less” becomes 0.70 times. Similarly, “35% of D” translates into a fractional relationship. Once all incomes are expressed in a common Base, comparisons become straightforward.

    After establishing relationships, we form combined expressions for A + D and B + D. The comparison between these two combined expressions is then made using proportional reasoning. This helps determine how one group compares to another in percentage terms.

    Such Questions test logical structuring and algebraic translation of verbal statements. The main challenge is maintaining consistency in conversion and avoiding confusion between increases and decreases.

    In summary, the problem focuses on converting chained percentage relationships into comparable expressions and analyzing combined Income ratios systematically.

    Option c – 225

    In a School, 135 students receive scholarships, representing 9% of total enrollment. What percentage is twice this number compared to one-fifth of the non-scholarship students?

    a) 102

    b) 99

    c) 103

    d) 97

    e) None of these

    Explanation:
    This question is based on percentage interpretation and part-whole relationships within a Population. It requires understanding how a given subset relates to the total and how transformed quantities compare with remaining groups.

    To approach this, we first interpret that 135 students represent a certain percentage of the total strength. This allows us to determine the full student Population conceptually. From there, we identify the number of non-scholarship students by subtracting the scholarship group from the total. Once these values are established, we form two new quantities: twice the scholarship group and one-fifth of the non-scholarship group.

    The next step involves comparing these two derived quantities using percentage comparison. This requires expressing one quantity as a percentage of the other. Such problems test the ability to move between absolute numbers and percentage representations smoothly.

    This type of reasoning is important because it combines multiple steps: finding totals, identifying complements, and comparing derived values. Errors often occur when students confuse parts with wholes or fail to correctly interpret percentage statements.

    In summary, the problem focuses on Population partitioning and comparative percentage analysis between derived subsets of a total group.

    Option d – 97

    What is 88.88% of 18.09?

    a) 16

    b) 16.08

    c) 16.16

    d) 16.24

    Explanation:
    This question is based on calculating a percentage of a given number. It tests understanding of converting percentages into fractional or decimal form and applying multiplication. Such problems are straightforward but require accuracy in decimal handling and place value management.

    To approach this, the percentage is first converted into a decimal form by dividing by 100. This converts 88.88% into its multiplier equivalent. The next step is to multiply this decimal factor with the given number 18.09. The operation involves careful decimal multiplication, ensuring proper alignment of digits and correct handling of decimal places.

    This type of question often appears in aptitude tests to check computational accuracy rather than conceptual depth. Small errors in decimal shifting or rounding can significantly affect the result. Therefore, careful step-by-step multiplication is essential.

    In summary, the problem focuses on converting a percentage into a decimal multiplier and applying it to a given value using precise arithmetic operations.

    Option b – 16.08

    Calculate 83.33% of 276

    a) 210

    b) 220

    c) 225

    d) 230

    Explanation:
    This question involves finding a percentage of a whole number using conversion into decimal or fractional form. It checks the ability to simplify percentage values before performing multiplication.

    To approach this, the percentage is first interpreted as a decimal multiplier by dividing it by 100. The value 83.33% is close to a recurring fraction form, which helps in simplifying calculations mentally. Once converted, it is multiplied with 276 to determine the required value. The key step is recognizing patterns in repeating decimals that make calculations easier.

    Such problems are designed to test quick calculation skills and familiarity with common percentage-to-fraction conversions. Instead of performing long multiplication blindly, recognizing approximations can simplify the process. Careful attention is still required to maintain accuracy in intermediate steps.

    In summary, the question focuses on converting percentage values into manageable forms and applying multiplication efficiently to obtain the result.

    Option d – 230

    Find the value of 75% of 7.5

    a) 56.5

    b) 56.25

    c) 5.625

    d) 0.5625

    Explanation:
    This question is based on basic percentage computation where a fraction of a decimal number must be found. It tests understanding of converting percentages into decimal multipliers and applying them to small numbers.

    To solve this conceptually, 75% is first converted into its decimal equivalent. This conversion makes it easier to perform multiplication with 7.5. The process involves multiplying the decimal form of the percentage with the given number. Since both numbers are simple decimals, the calculation is straightforward but requires attention to decimal placement.

    Such Questions are often used to test foundational arithmetic skills, especially in handling percentages and decimals together. Errors usually occur due to incorrect shifting of decimal points or misinterpretation of percentage conversion.

    In summary, the problem focuses on converting a percentage into decimal form and applying it correctly to a given decimal number using simple multiplication.

    Option c – 5.625

    What is 58.333% of 16.8?

    a) 0.96

    b) 96

    c) 8.6

    d) 9.6

    Explanation:
    This question involves computing a percentage of a decimal number where the percentage has a recurring decimal form. It tests both conceptual understanding of percentage conversion and computational accuracy.

    To approach this, the percentage is first converted into a decimal multiplier. The value 58.333% can be understood as a fractional representation, which simplifies multiplication. Once converted, it is multiplied with 16.8. The key is recognizing that recurring decimals often represent simple fractions, making mental calculation easier.

    This type of question is designed to test familiarity with common percentage patterns and efficiency in arithmetic operations. Instead of treating it as a long decimal multiplication problem, recognizing its fractional equivalent helps reduce complexity.

    In summary, the problem focuses on converting recurring percentage values into simpler forms and applying them to decimal multiplication efficiently and accurately.

    Option d – 9.6

    Find 25% of 55

    a) 13

    b) 12.75

    c) 14.75

    d) 13.75

    Explanation:
    This question is based on basic percentage calculation where a quarter of a number must be determined. It tests understanding of simple fractional equivalents of common percentages.

    To approach this, 25% is recognized as one-fourth of a whole. This makes the calculation simpler, as instead of multiplying by a decimal, the number can be divided by 4. The given number 55 is then split accordingly to obtain the required value.

    Such problems are designed to test quick mental calculation skills and familiarity with standard percentage conversions. Recognizing that 25% corresponds to a simple fraction helps avoid unnecessary multiplication steps and reduces computational effort.

    In summary, the problem focuses on converting a standard percentage into a fraction and applying it directly for fast calculation.

    Option d – 13.75

    What is 1/5% of 2500?

    a) 50

    b) 5

    c) 500

    d) 0.5

    Explanation:
    This question involves interpreting a fractional percentage and applying it to a given number. It tests understanding of how percentages expressed as fractions are converted into decimal form before calculation.

    To approach this, the fractional percentage is first converted into a standard percentage value. This is then converted into a decimal multiplier by dividing by 100. Once the correct multiplier is obtained, it is applied to 2500 through multiplication. The key challenge lies in correctly interpreting the fractional percentage format before proceeding with calculations.

    Such problems often test attention to detail because fractional percentages can be confusing if not carefully interpreted. The correct conversion ensures that the multiplication step is accurate and meaningful.

    In summary, the question focuses on interpreting fractional percentages correctly and applying them through systematic conversion into decimal form for calculation.

    Option b – 5

    What is 11-1/9% of 67.5?

    a) 7.5

    b) 9.5

    c) 8.5

    d) 1.5

    Explanation:
    This question involves calculating a percentage expressed in mixed fractional form applied to a decimal number. It requires careful conversion of the percentage into a usable decimal multiplier before computation.

    To approach this, the mixed percentage is first converted into an improper fraction and then into a decimal form. This conversion is essential to ensure correct multiplication with the given value 67.5. Once the percentage is converted into a multiplier, it is applied directly to the number. The process requires careful handling of fractions and decimals together.

    Such Questions test both conceptual clarity and arithmetic precision. Errors often occur when the fractional percentage is misinterpreted or incorrectly converted, leading to inaccurate results.

    In summary, the problem focuses on converting mixed fractional percentages into decimal multipliers and applying them correctly to a given value using systematic calculation steps.

    Option a – 7.5

    Soni weighs 68.4 kg and is 28-4/7% heavier than Rekha. By what percent is Rekha lighter than Soni?

    a) 53.3

    b) 53.2

    c) 56.6

    d) 54.4

    e) None of these

    Explanation:
    This question is based on comparative percentage change between two quantities. It involves understanding how one value relates to another through percentage increase and then reversing the relationship.

    To approach this, we first interpret that Soni’s weight is higher than Rekha’s by a certain percentage. This allows us to express Soni’s weight as a multiple of Rekha’s weight. Once that relationship is established, we can determine Rekha’s weight in terms of Soni. The next step is to compare how much lighter Rekha is relative to Soni using percentage difference.

    Such problems require careful handling of reverse percentage relationships. A common mistake is treating the percentage symmetrically, but increases and decreases are not interchangeable without proper recalculation. The key is to consistently define one variable and express all other values in relation to it.

    In summary, the problem focuses on establishing a percentage-based relationship between two quantities and then reversing it to determine comparative decrease accurately.

    Option b – 53.2

    A college’s student strength grew from 450 in 2014 to 477 in 2015. If the growth continued steadily, what was the increase in strength by 2018?

    a) 81

    b) 59

    c) 48

    d) 42

    e) None of these

    Explanation:
    This question is based on steady growth over time, where an increase observed in one year is assumed to continue uniformly. It tests understanding of consistent incremental change across multiple periods.

    To approach this, we first determine the annual increase by comparing the two given years. This difference represents the constant yearly growth. Once the yearly increment is identified, it is extended across the remaining years up to 2018. The total increase is then calculated by multiplying the yearly growth by the number of years considered.

    Such problems test logical extrapolation skills and consistency in applying growth rates. A common mistake is treating the growth as percentage-based when it is actually a fixed numerical increase. Careful interpretation of the statement is essential.

    In summary, the question focuses on identifying a constant yearly increase and extending it over multiple years to determine total growth.

    Option c – 48

    A property valued at ₹3.20 crores in 2015 appreciated by 1/6% each year. What was its approximate value in 2018, in millions?

    a) 32.16

    b) 33.16

    c) 33.1602

    d) 31.1602

    e) None of these

    Explanation:
    This question involves compound growth over multiple years using a small annual appreciation rate. It tests understanding of repeated percentage increase and unit conversion between crores and millions.

    To approach this, we first interpret the annual appreciation rate and apply it successively over the given number of years. Each year’s value increases slightly based on the previous year’s value, making it a compound process. After applying the growth for the required duration, the final value is obtained. The last step involves converting the result from crores into millions for proper representation.

    Such problems require careful step-by-step application of growth rather than simple multiplication. Since the rate is small, the increase is gradual but accumulates over time. Attention to unit conversion is also important to avoid errors in the final representation.

    In summary, the problem focuses on compound percentage growth over time and accurate conversion of large financial units into smaller standardized forms.

    Option d – 31.1602

    Out of 48,400 candidates who appeared for CAT 2018, 47.5% scored above the 95th percentile, 79.2% above the 90th, and 93.6% above the 85th. How many students scored between the 90th and 95th percentiles (in hundreds)?

    a) 150

    b) 15,300

    c) 15,400

    d) 15,600

    e) None of these

    Explanation:
    This question is based on interpreting cumulative percentage data and finding the difference between two percentile groups. It involves understanding how overlapping percentage ranges can be separated to isolate a specific band of students. Such problems are common in data interpretation sections.

    To approach this, we first interpret that percentages above different percentile thresholds represent cumulative groups. The group above the 95th percentile is a smaller, more selective subset compared to those above the 90th percentile. Therefore, students scoring between the 90th and 95th percentiles can be found by subtracting the higher group from the lower cumulative group.

    The key idea is recognizing that “above 90th” includes everyone above both 90th and 95th percentiles. So, to isolate only those between 90 and 95, we remove the 95+ group from the 90+ group. After finding the difference, the result is expressed in hundreds as required.

    This type of reasoning is important because it tests logical decomposition of overlapping sets rather than direct calculation. Misinterpreting cumulative percentages is a common error, so careful SET-based thinking is essential.

    In summary, the problem focuses on interpreting percentile-based cumulative data and extracting a specific interval using subtraction of overlapping groups.

    Option c – 15,400

    An agent receives a 15% commission on each sewing machine sold, plus a fixed salary of ₹15,000 per month. If he sells five machines at ₹26,000 each, what is his total monthly Income?

    a) 33,560

    b) 34,500

    c) 36,460

    d) 18,900

    e) None of these

    Explanation:
    This question involves calculating total Income from a combination of fixed salary and variable commission. It tests understanding of percentage-based earnings and basic multiplication applied to real-world Income scenarios.

    To approach this, we first interpret that the agent earns a fixed monthly salary, which remains constant regardless of sales. In addition, he earns a commission based on a percentage of the total sales value of sewing machines. The first step is to calculate the total sales amount by multiplying the number of machines sold by the price per machine. Then, the commission is calculated as a percentage of this total sales value.

    Once the commission is determined, it is added to the fixed salary to obtain the total income. The key idea is separating fixed and variable components and treating them independently before combining them.

    Such problems are important because they test the ability to translate real-life financial situations into mathematical expressions. A common mistake is applying the commission to the number of items instead of total sales value, which leads to incorrect results.

    In summary, the problem focuses on combining fixed income and percentage-based commission derived from total sales to compute overall earnings.

    Option d – 18,900

    A property worth ₹74,640 is insured at a premium rate of 1/8%. What is the premium amount?

    a) 92.06

    b) 93.3

    c) 97.02

    d) 90.05

    e) None of these

    Explanation:
    This question is based on calculating Insurance premium using percentage rates applied to a given property value. It involves converting a fractional percentage into a decimal form and applying it to the insured amount.

    To approach this, we first interpret the premium rate expressed as a fraction of a percent. This must be carefully converted into a standard percentage and then into a decimal multiplier. Once converted, the multiplier is applied to the property value ₹74,640 to determine the premium amount.

    Such problems test attention to detail in percentage interpretation, especially when fractional percentages are involved. The main challenge lies in correctly converting the rate before performing multiplication. Even small conversion errors can significantly affect the final result.

    This type of calculation is commonly used in financial mathematics, particularly in Insurance and banking contexts. It reinforces the concept that percentage rates must always be standardized before application.

    In summary, the problem focuses on interpreting fractional percentage rates and applying them accurately to a monetary value to determine Insurance premium.

    Option b – 93.3

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