Explanation: This question asks about the main purpose of a Wheatstone bridge in electrical measurements. A Wheatstone bridge is a Network of four resistors arranged in a diamond shape, with a galvanometer connected between two opposite junctions. It operates on the principle of null deflection, meaning no current flows through the galvanometer when the bridge is balanced. This condition allows precise comparison between known and unknown resistances.
To understand its working, consider that when the ratio of resistances in one branch equals the ratio in the other branch, the potential difference across the galvanometer becomes zero. Because no current flows through it, the setup becomes highly sensitive and accurate. This method avoids errors due to instrument calibration, making it reliable for detecting small resistance differences.
An analogy is balancing weights on a scale: when both sides are equal, the pointer remains at zero, indicating balance. Similarly, the Wheatstone bridge indicates balance when electrical ratios match perfectly.
In summary, this device is designed for accurate comparison and determination of resistance values using a balance condition rather than direct measurement.
Option a - Meter bridge
In a Wheatstone bridge, the four resistances P, Q, R, and S are 10 Ω, 30 Ω, 30 Ω, and 90 Ω respectively. If the cell has an emf of 7 V and internal resistance 5 Ω, and the galvanometer has 50 Ω resistance, the current drawn from the cell is:
a) 0.2 A
b) 0.1 A
c) 2.0 A
d) 1.0 A
Explanation: This question involves determining the total current drawn from a source in a Wheatstone bridge circuit with given resistances and internal parameters. The bridge consists of four resistors forming two parallel branches, along with a galvanometer connecting the midpoints. The concept of bridge balance plays a key role here.
First, check whether the bridge satisfies the balance condition, where the ratio of one pair of opposite resistances equals the ratio of the other pair. When this condition is met, no current flows through the galvanometer, effectively removing it from the circuit. The system then simplifies into a combination of resistors that can be reduced using series and parallel rules.
Next, include the internal resistance of the cell in the total circuit resistance. Once the equivalent resistance is obtained, apply Ohm’s law using the emf of the cell to determine the current. This step-by-step reduction ensures accurate calculation without unnecessary complexity.
Think of it like water flowing through pipes: if one connecting pipe is blocked (no flow through galvanometer), the system simplifies, making flow calculation easier.
Overall, the problem tests understanding of bridge balance and equivalent resistance simplification to determine circuit current.
Option a - 0.2 A
In a meter bridge, resistances X and 2X are connected in the left and right gaps. The null point occurs at:
a) 33.3 cm from the right end
b) 33.3 cm from the left end
c) 66.6 cm from the left end
d) 40 cm from the left end
Explanation: This question focuses on determining the position of the balance point in a meter bridge when two resistances are given in a known ratio. A meter bridge is based on the Wheatstone bridge principle and uses a uniform wire of 100 cm length. The balance point occurs when the ratio of the resistances equals the ratio of the lengths of the wire segments on either side of the null point.
To solve such problems, the relation X/Y = L/(100 − L) is used, where L is the balance length from one end. Here, one resistance is double the other, so the ratio becomes 1:2. Substituting into the equation helps determine the exact position along the wire. The concept relies on the uniform resistance per unit length of the wire, ensuring proportionality between length and resistance.
An analogy would be balancing a seesaw where weights are in a fixed ratio; the pivot point shifts accordingly to maintain equilibrium. Similarly, the null point shifts along the wire depending on resistance ratios.
In summary, the position of the null point depends directly on the ratio of resistances and the proportional division of the wire length.
Option b - 33.3 cm from the left end
A post office box measures resistance based on the principle of:
a) Potentiometer
b) Meter bridge
c) Ohmmeter
d) Galvanometer
Explanation: This question asks about the working principle behind a post office box, an instrument used for precise resistance measurement. The device is essentially a practical form of a Wheatstone bridge, where known resistances are adjusted until a balance condition is achieved. The absence of current through the galvanometer indicates that the ratios of resistances in the bridge are equal.
The key idea is the null method, which provides high accuracy because it does not rely on direct measurement of current or voltage. Instead, it compares ratios, reducing errors due to fluctuations in supply or instrument calibration. By adjusting known resistances, the unknown resistance is determined when the bridge is balanced.
Think of it like matching two sides of a scale using standard weights until perfect balance is achieved. The unknown value is then inferred from the known standards.
Overall, the instrument uses a balance-based comparison technique to determine resistance with high precision and reliability.
Option b - Meter bridge
If the balance point in a meter bridge is at the 35th cm mark, the ratio of the resistances in the two gaps is:
a) 13 : 7
b) 11 : 9
c) 7 : 13
d) 2 : 3
Explanation: This question involves calculating the ratio of resistances using the position of the balance point in a meter bridge. The bridge operates on the principle that resistance is proportional to the length of a uniform wire. When the galvanometer shows null deflection, the ratio of the two resistances equals the ratio of the lengths of the wire segments.
Using the relation R₁/R₂ = L/(100 − L), where L is the balance length, substitute the given value of 35 cm. This gives a ratio based on how the wire is divided at equilibrium. The calculation reflects how electrical resistance is distributed along the wire.
An easy way to visualize this is by dividing a rope into two parts; the lengths directly represent how resistance is shared between the two sides.
In summary, the ratio of resistances is determined by the proportional division of the wire at the balance point in the meter bridge.
Option c - 7 : 13
When using a potentiometer, the current is supplied by:
a) Both the cell and auxiliary battery
b) Cell only
c) Auxiliary battery only
d) Neither cell nor auxiliary battery
Explanation: This question deals with the source of current in a potentiometer setup. A potentiometer is used to measure potential difference by comparing it with a known voltage drop along a uniform wire. It requires a steady current to flow through the wire to maintain a uniform potential gradient.
The circuit typically involves two parts: the primary circuit that establishes the potential gradient and the secondary circuit used for measurement. The primary circuit includes a stable external power source that drives current through the wire. The cell being tested does not supply current to the main circuit; instead, it is compared against the potential difference along the wire.
This can be compared to a ruler used for measurement—the ruler provides a fixed scale, while the object being measured does not affect the scale itself.
In summary, the current in a potentiometer is maintained by an external source to ensure a stable and uniform potential gradient for accurate measurements.
Option c - Auxiliary battery only
In Kelvin’s method, the bridge is considered balanced when the galvanometer shows:
a) Zero deflection
b) Null deflection
c) Full deflection
d) Fixed deflection
Explanation: This question relates to Kelvin’s method, an advanced bridge technique used for measuring very low resistances. Like other bridge methods, it relies on achieving a balance condition where no current flows through the galvanometer. This is indicated by the absence of deflection.
The principle is similar to the Wheatstone bridge but is modified to eliminate errors due to contact and lead resistances. When the bridge is balanced, the potential difference across the galvanometer becomes zero, ensuring that the measured value is accurate and unaffected by unwanted resistances.
Imagine adjusting two sides of a balance scale until the pointer rests exactly at zero; this indicates perfect equilibrium. Similarly, the galvanometer shows no deflection when balance is achieved.
In summary, the balance condition in Kelvin’s method is identified by a state where no current flows through the galvanometer, indicating precise measurement.
Option c - Full deflection
The sensitivity of a Wheatstone bridge mainly depends on:
a) Current
b) Resistance
c) Voltage
d) Specific resistance
Explanation: This question explores the factor that influences the sensitivity of a Wheatstone bridge. Sensitivity refers to the ability of the bridge to detect small changes in resistance. It depends on how effectively the galvanometer responds to slight imbalances in the circuit.
Several factors affect sensitivity, including the arrangement of resistances and the magnitude of current flowing through the circuit. The closer the bridge is to its balanced condition, the more sensitive it becomes to small variations. Proper selection and arrangement of resistances enhance the detection capability of the galvanometer.
An analogy would be a finely tuned weighing scale that can detect even the smallest difference in weight when properly balanced.
In summary, the sensitivity of the Wheatstone bridge is governed by how the circuit conditions allow small resistance changes to produce noticeable galvanometer responses.
Option b - Resistance
The bridge achieves maximum sensitivity when all four resistances are arranged in:
a) Different order
b) Same order
c) Partially same order
d) Partially different order
Explanation: This question examines the condition required for maximum sensitivity in a Wheatstone bridge. Sensitivity is highest when the bridge is configured such that small changes in resistance produce significant changes in galvanometer deflection.
For maximum sensitivity, the resistances should be arranged so that their values are nearly equal. This ensures that the potential difference across the galvanometer changes significantly even for minor variations in any arm of the bridge. When resistances are unevenly distributed, the bridge becomes less responsive to changes.
Think of it like balancing equal weights on a scale—any small addition or removal becomes immediately noticeable. Unequal weights, on the other hand, reduce responsiveness.
In summary, arranging resistances in a balanced and uniform manner enhances the sensitivity of the Wheatstone bridge.
Option b - Same order
Wheatstone’s bridge is used for measuring:
a) EMF of a cell
b) Unknown resistance
c) Unknown current
d) Potential difference
Explanation: This question asks about the primary application of a Wheatstone bridge. It is a widely used electrical circuit designed to determine an unknown resistance by comparing it with known resistances. The method relies on achieving a balance condition where no current flows through the galvanometer.
The advantage of this method lies in its accuracy, as it uses a null deflection technique rather than direct measurement. This minimizes errors due to fluctuations in current or voltage. By adjusting known resistances, the unknown value is calculated when the bridge is balanced.
An analogy is comparing an unknown weight with standard weights on a balance scale until equilibrium is reached.
In summary, the Wheatstone bridge provides a precise method for determining resistance values through comparison and balance.
Option b - Unknown resistance
The Wheatstone bridge is most sensitive when the ratio of the arms is:
a) 0
b) 1
c) 10
d) Infinity
Explanation: This question focuses on the condition for achieving maximum sensitivity in a Wheatstone bridge based on the ratio of its arms. Sensitivity depends on how effectively the bridge responds to small deviations from the balanced state.
When the ratio of resistances in one pair of arms is close to unity, the bridge becomes highly sensitive. This ensures that even a slight change in resistance leads to a noticeable deflection in the galvanometer. If the ratio is too large or too small, the bridge loses its ability to detect minor variations.
This can be compared to a balanced lever, where equal arm lengths make it highly responsive to small forces.
In summary, maintaining an appropriate ratio of resistances ensures that the Wheatstone bridge operates with maximum sensitivity.
Option b - 1
In a balanced Wheatstone bridge, the current through the galvanometer is zero. The galvanometer will show a non-zero current when:
a) The battery EMF is zero
b) The battery and galvanometer are interchanged
c) All resistances in the circuit are doubled
d) Resistances of adjacent arms are interchanged
Explanation: This question examines the condition under which a galvanometer shows deflection in a Wheatstone bridge. In a balanced state, the potential difference across the galvanometer is zero, so no current flows through it. Any disturbance in this balance leads to a potential difference and hence a current.
Such imbalance can occur when the ratios of resistances in the two arms are altered. This disrupts the equality condition, causing current to pass through the galvanometer. The presence of current indicates that the bridge is no longer in equilibrium.
An analogy is a perfectly balanced scale that tips when even a small weight is added to one side.
In summary, the galvanometer shows deflection whenever the balance condition of the bridge is disturbed due to changes in resistance arrangement.
Option d - Resistances of adjacent arms are interchanged
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