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Balaji Publication Chemistry Class 11. We covered all the Balaji Publication Chemistry Class 11 in this post for free so that you can practice well for the exam.
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Balaji Publication Chemistry Class 11 Objective for Students
At 298 K, the vapour pressure of pure water is 23.75 mmHg. For a 5% aqueous solution of urea at the same temperature, the relative decrease in vapour pressure is
a) 0.016
b) 0.16
c) 23.37
d) 27.23
Option a – 0.016
A solution contains 28% (by Mass) of a liquid A having molar Mass 140. Its vapour pressure at 30°C is 160 mmHg. If the vapour pressure of water at 30°C is 150 mmHg, the vapour pressure of pure liquid A is
a) 360 mmHg
b) 10 mmHg
c) 180 mmHg
d) 400 mmHg
Option a – 360 mmHg
The boiling point of a liquid is defined as the temperature at which its vapour pressure becomes equal to
a) Critical pressure
b) Atmospheric pressure
c) Normal pressure
d) Vapour pressure of the Solid phase
Option b – Atmospheric pressure
When a Solid solute is dissolved in a liquid solvent, the boiling point of the solvent
a) Decreases
b) Remains unchanged
c) Increases
d) Depends on the polarity of the solution
Option c – Increases
At a given temperature, the vapour pressure of benzene is 640 mmHg. When 2.175 g of a non-volatile solute is dissolved in 39.08 g of benzene, the vapour pressure drops to 600 mmHg. The molar Mass of the solute is
a) 49.50 g
b) 69.60 g
c) 59.60 g
d) 79.82 g
Option b – 69.60 g
The vapour pressures of pure liquids A and B are 80 atm and 60 atm respectively. When 3 moles of A are mixed with 2 moles of B, the total vapour pressure of the resulting solution is
a) 72 atm
b) 20 atm
c) 68 atm
d) 140 atm
Option a – 72 atm
The vapour pressure of pure benzene at 30°C is 121.8 mmHg. If 15 g of a non-volatile solute is dissolved in 250 g of benzene and the vapour pressure of the solution becomes 120.2 mmHg, the Molecular Mass of the solute is
a) 35.67 g
b) 356.7 g
c) 432.8 g
d) 502.7 g
Option b – 356.7 g
A decrease in vapour pressure of a solvent is observed when the solute added is
a) Volatile
b) Non-volatile
c) A non-electrolyte
d) Any of the above
Option d – Any of the above
The vapour pressure of pure water at room temperature is 40 mmHg. In an aqueous solution of a non-volatile solute, the mole fraction of water is 0.9. The vapour pressure of the solution will be
a) 44.4 mmHg
b) 40 mmHg
c) 40.4 mmHg
d) 36 mmHg
Option d – 36 mmHg
Two liquids A and B form a solution. The vapour pressure of pure liquid A at 300 K is 70 mmHg. If the mole fraction of B is 0.2 and the total vapour pressure of the solution is 84 mmHg, the vapour pressure of pure liquid B is
a) 140 mmHg
b) 56 mmHg
c) 70 mmHg
d) 14 mmHg
Option a – 140 mmHg
The type of solution that follows Raoult’s law over the entire range of concentration and temperature is
a) Real solution
b) Dilute solution
c) Binary solution
d) Ideal solution
Option d – Ideal solution
We covered all the balaji publication Chemistry Class 11 above in this post for free so that you can practice well for the exam.
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