**Centripetal Force in Hindi**. We covered all the Centripetal Force in Hindi in this post for free so that you can practice well for the exam.

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## Mock Test on Centripetal Force for Students

## A ball of mass 0.25 kg attached to one end of a string of length 1.96 m is moving in a horizontal circle. The string will break if the tension is more than 25 N. What is the maximum speed with which a particle can be moved?

(A) 5 m/s

(B) 3.92 m/s

(C) 3 m/s

(D) 14 m/s

Option d - 14 m/s

## A mass of 100 g is tied to one end of a string 2 m long. The body is revolving in a horizontal circle making a maximum of 200 rpm. The outer end of the string is fixed at the center of the revolution. The maximum tension the string can bear is approximate:

(A) 8.76 N

(B) 8.94 N

(C) 89.42 N

(D) 87.64 N

Option d - 87.64 N

## Assuming the coefficient of friction between the road and tires of a car to be 0.5 the maximum speed with which the car can move around the curve of a 40 m radius without slipping if the road is unbanked should be : (g=9.8m/s²)

(A) 25 m/s

(B) 19 m/s

(C) 14 m/s

(D) 11 m/s

Option c - 14 m/s

## A stone of mass 16 kg is attached to a string 144 m. long and is whirled in a horizontal circle. The maximum tension the string can withstand is 16 N. The maximum velocity of revolution that can be given to the stone without breaking it will be :

(A) 20 m/s

(B) 16 m/s

(C) 14 m/s

(D) 12 m/s

Option d - 12 m/s

## An object of mass 50 kg is moving in a horizontal circle of radius 8 m. If the centripetal force is 40 N. The kinetic energy of an object is :

(A) 320 J

(B) 220 J

(C) 260 J

(D) 160 J

Option d - 160 J

## A stone of mass m is tied to one end of a string, and is rotated in a horizontal circle with a constant speed v. The force of tension in the string is F, if now radius and angular velocity are doubled, what is the new tension?

(A) F

(B) 2F

(C) 4F

(D) 8F

Option d - 8F

## The maximum frictional force between the tires and the road is half the weight of the car. If the car negotiates a curve of radius 20 m. The velocity of the car is (g = 10 m/s²)

(A) 7 m/s

(B) 10 m/s

(C) 4.9 m/s

(D) 14.2 m/s

Option b - 10 m/s

## The breaking tension in the string is 20 N. A particle of 0.1 kg is tied to a string 2 m long. What is the maximum angular speed with which a particle can be rotated?

(A) 10 rad/s

(B) 100 rad/s

(C) 5 rad/s

(D) 1 rad/s

Option a - 10 rad/s

## A cyclist turns around a curve at 40 km/hr. If he rounds the curve at double speed, his tendency to overturn is :

(A) Doubled

(B) Tripled

(C) Halved

(D) Quadrupled

Option d - Quadrupled

## A coin is kept on a horizontal rotating disc and has its center at a distance of 0.1 m from the axis of rotation of the disc. If the coefficient of friction between the coin and disc is 0.25, the speed of the disc at which the coin would be about to slip off :

(A) 0.5 m/s

(B) 0.25 m/s

(C) 1 m/s

(D) 2.5 m/s

Option a - 0.5 m/s

## A certain string breaks under 45 kgwt. A mass of 0.1 kg is attached to this string of length 5 m and whirled in a horizontal circle. The maximum number of revolutions per sec without breaking the string is :

(A) 4.72 rps

(B) 47.2 rps

(C) 472 rpm

(D) 47.2 rpm

Option a - 4.72 rps

## A car of mass 1000 kg moves on a circular path with a constant speed of 16 m/s. It is turned by 90° after traveling 628 m on the road. The centripetal force acting on the car is : (g = 9.8 m/s²)

(A) 160 N

(B) 320 N

(C) 1280 N

(D) 640 N

Option d - 640 N

We covered all the centripetal force in Hindi above in this post for free so that you can practice well for the exam.

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