Pure bromoalkane is prepared from bromination of which alkane?
(A) Ethane
(B) Propane
(C) 2-methyl propane
(D) Isopentane
Explanation: Bromination of alkanes proceeds through a free radical substitution mechanism, where hydrogen atoms are replaced by bromine atoms under suitable conditions like UV Light. The reaction tends to prefer positions where the intermediate radical formed is more stable, since stability strongly influences product formation. In simple alkanes, different carbon atoms may lead to different radical stabilities such as primary, secondary, or tertiary types. The distribution of products depends on how stable the intermediate radicals are during the reaction pathway. Factors like hyperconjugation and inductive effects stabilize certain radical intermediates more than others, influencing selectivity. In cases where a single major product is formed, symmetry or equivalent hydrogen positions play a key role in ensuring uniform substitution. The overall outcome is controlled by the nature of the alkane structure and how evenly or unevenly the hydrogen atoms are distributed across the Molecule.
Option a – Ethane
Which of the following compounds yields only one product on monobromination? ( ChemistryClass 9 Chapter mcq )
(A) n-Butane
(B) Propane
(C) Neopentane
(D) Isopentane
Explanation: Monobromination of alkanes also follows a free radical substitution mechanism, where a hydrogen Atom is replaced by a bromine Atom under UV Light or Heat. The number of possible products depends on the number of distinct types of hydrogen atoms present in the Molecule. If all hydrogen atoms are equivalent due to Molecular symmetry, substitution at any position produces the same compound. However, when different types of hydrogen environments exist, multiple isomeric products can form. Structural symmetry and identical carbon environments reduce product diversity, leading to a single monobrominated compound. The reaction outcome is therefore closely linked to Molecular geometry, equivalence of hydrogen positions, and stability considerations of intermediates formed during the reaction process.
Option c – Neopentane
Direct iodination of alkanes is a reversible reaction because
(A) R-I is reduced by HI
(B) R-I is oxidized by HI
(C) HIO3 oxidizes HI
(D) R-I reduce HCl
Explanation: Halogenation of alkanes generally involves a free radical substitution mechanism, where hydrogen atoms are replaced by halogen atoms under suitable conditions. In the case of iodine, the reaction behaves differently compared to chlorine or bromine due to the weaker reactivity of iodine. The bond formed between carbon and iodine is relatively weak, and the intermediate steps do not strongly favor product formation. Additionally, the reverse process is energetically feasible, meaning the products can revert back to reactants under the same conditions. The equilibrium nature of this reaction depends on the relative bond strengths and the overall energy balance between reactants and products. As a result, the system does not move strongly toward product formation, making the reaction reversible in nature.
Option a – R-I is reduced by HI
The major additional product of HBr with isobutylene is ( ChemistryClass 9 Chapter mcq )
(A) Isobutyl bromide
(B) Sec. butyl bromide
(C) Ter. butyl bromide
(D) n-butyl bromide
Explanation: Addition reactions of hydrogen halides to alkenes proceed through electrophilic addition mechanisms, where the double bond is first attacked to form a carbocation intermediate. The stability of this intermediate strongly influences the orientation of the final product. More substituted carbocations are generally more stable due to electron-releasing effects and hyperconjugation. Once the intermediate is formed, the halide ion quickly attaches to it, forming the final product. The pathway followed depends on how the Molecule rearranges to achieve maximum stability in the intermediate stage. Reaction conditions and absence or presence of peroxides can also influence the direction of addition. The overall product distribution is governed by the stability of intermediate species formed during the reaction process.
Option c – Ter. butyl bromide
3-Chloropropene is obtained by reacting propene and which of the following reagents in the presence of UV Light?
(A) Sulfuryl chloride
(B) Thionyl chloride
(C) Benzyl chloride
(D) Vinyl chloride
Explanation: Reactions involving alkenes under UV Light often proceed through radical mechanisms rather than ionic pathways. In such processes, reagents can split into reactive species that attack the double bond or adjacent hydrogen atoms. The presence of Lightenergy initiates homolytic bond cleavage, generating radicals that participate in substitution or addition reactions. The reaction pathway depends on the stability of radical intermediates and the tendency of the system to form more stable substituted products. The position at which substitution occurs is influenced by the relative reactivity of hydrogen atoms in different environments. UV Light plays a crucial role in triggering radical formation, making the reaction proceed through an alternate mechanism compared to dark conditions.
Option a – Sulfuryl chloride
Synthesis of fluoroalkane is best accomplished by ( ChemistryClass 9 Chapter mcq )
(A) Wurtz reaction
(B) Sandmayer’s reaction
(C) Finkelstein reaction
(D) Swartz reaction
Explanation: Preparation of alkyl fluorides is not straightforward due to the high reactivity and difficulty in controlling fluorination reactions. Unlike other halogens, fluorine tends to react violently and can lead to multiple side reactions if not controlled properly. Therefore, indirect methods are preferred for synthesizing fluoroalkanes. These methods involve halogen exchange reactions where a less reactive halogen in an alkyl halide is replaced by fluoride under controlled conditions. The choice of reagent and reaction pathway ensures selective substitution while minimizing unwanted side products. The reaction conditions are carefully maintained to avoid overreaction and decomposition of the Organic substrate. Overall, the synthesis relies on controlled substitution strategies rather than direct halogenation.
Option d – Swartz reaction
Which of the following is not formed during the chlorination of ethane?
(A) Chloroethene
(B) Ethylene chloride
(C) Ethylidene dichloride
(D) Ethyl chloride
Explanation: Chlorination of ethane proceeds through a free radical substitution mechanism initiated by UV Light or Heat, where chlorine radicals replace hydrogen atoms stepwise. The process can lead to multiple substitution products depending on how many hydrogen atoms are replaced. Initially, monosubstituted products form, followed by further substitution leading to di-substituted compounds under continued reaction conditions. The distribution of products depends on reaction control, availability of chlorine radicals, and stability of intermediate radicals formed during hydrogen abstraction. However, addition products involving carbon–carbon multiple bonds are not expected because ethane contains only single bonds and does not support addition-type transformations under these conditions. Therefore, products requiring unsaturation formation or addition across double bonds are not part of the chlorination pathway of ethane.
Option a – Chloroethene
During the preparation of isopropyl chloride from propane, the intermediate obtained is ( ChemistryClass 9 Chapter mcq )
(A) n-propyl free radical
(B) isopropyl free radical
(C) isopropyl carbonium ion
(D) isopropyl carbanion
Explanation: The formation of alkyl chlorides from alkanes typically occurs through a free radical substitution mechanism, especially under the influence of Light or Heat. In this mechanism, chlorine molecules split into reactive radicals that abstract hydrogen atoms from the alkane, forming intermediate species. These intermediates determine the final product distribution based on their stability. More stable intermediates are favored, often leading to selective formation of specific isomers. The reaction proceeds through a chain process involving initiation, propagation, and termination steps. The nature of the intermediate plays a crucial role in deciding the structure of the final alkyl halide formed, as it reflects the most stable radical configuration possible during the reaction pathway.
Option b – isopropyl free radical
3-Methyl butan-2-ol reacts with Lucas reagent to form
(A) 2-chloro-2-methyl butane
(B) 2-chloro-3-methyl butane
(C) 1-chloro-2-methyl butane
(D) 1-chloro-3-methyl butane
Explanation: Alcohols react with Lucas reagent (conc. HCl + anhydrous ZnCl₂) through a mechanism involving formation of a carbocation intermediate, especially for secondary and tertiary Alcohols. The reactivity depends strongly on how stable the intermediate carbocation is during the substitution process. More substituted carbocations form more easily, leading to faster conversion into corresponding alkyl chlorides. The hydroxyl group is replaced by a chloride ion after protonation and loss of water, which is the slow and crucial step in the mechanism. The structure of the Alcohol determines the position where substitution occurs and the nature of the resulting haloalkane. Steric and electronic factors also influence how quickly the reaction proceeds under these conditions.
Option a – 2-chloro-2-methyl butane
Which of the following contains the number of color waves? ( ChemistryClass 9 Chapter mcq )
Explanation: Light can exist in different forms depending on how its electromagnetic waves are arranged and how many wavelengths are present. When light consists of multiple wavelengths, it shows a combination of colors that form a Spectrum. Such light is not limited to a single wavelength and therefore can display various colors depending on dispersion or separation. The Nature of Light sources determines whether the emitted radiation is single-colored or multi-colored. Natural sources like sunlight contain a wide range of wavelengths, while certain artificial sources may emit more controlled or narrow bands of light. The perception of color depends on the mixture of wavelengths reaching the eye and how they interact with optical media.
Option d – Ordinary light
A research student, when trying to get ethyl chloride from ethanol, noticed that extra heating was required despite the reagent, which he didn’t require while preparing tert-butyl chloride. The reagent must be
(A) Groove’s reagent
(B) Sandmayer’s reagent
(C) Darzen’s reagent
(D) Lucas reagent
Explanation: The conversion of Alcohols into alkyl chlorides depends on the nature of the Alcohol and the mechanism involved. Primary Alcohols react slowly and often require stronger conditions such as heating because they do not easily form stable carbocation intermediates. In contrast, tertiary Alcohols react readily due to the formation of highly stable carbocations, allowing faster substitution. Certain reagents facilitate this transformation by activating the hydroxyl group and promoting its replacement by a halogen. The reaction rate is strongly influenced by structural stability and reaction pathway differences between primary, secondary, and tertiary Alcohols. This explains why different Alcohols require different conditions even when treated with similar reagents.
Option d – Lucas reagent
Vijay is performing a reaction between 2-methyl prop-1-ene and hydrogen bromide in the presence of Na2O2. His major product might be a haloalkane. ( ChemistryClass 9 Chapter mcq )
(A) Primary
(B) Secondary
(C) Tertiary
(D) Vinylic
Explanation: Addition of hydrogen halides to alkenes typically follows different pathways depending on reaction conditions. In the absence of peroxides, the reaction proceeds through a carbocation intermediate leading to a more substituted product. However, in the presence of peroxides, a radical mechanism can dominate, altering the orientation of addition. The mechanism involves formation of radicals that add across the double bond in a stepwise fashion. Stability of intermediates and radical preference determines which product is formed in greater quantity. The nature of substituents on the alkene also influences how the reaction proceeds, especially in branched structures where multiple substitution sites may be possible.
Option a – Primary
Four students found the relation between the boiling point for halides of ethane. Who is most likely to be correct? [R is the ethyl group]
(A) Sundarm: RCl > RBr > RI
(B) Vajid: RI > RBr > RCl
(C) Tom: RBr > RI > RCl
(D) Surinder: RCl > RI > RBr
Explanation: Boiling points of alkyl halides depend on intermolecular forces, particularly van der Waals forces and polarizability of the halogen Atom. Heavier halogens generally increase boiling point due to stronger dispersion forces. Molecular structure and size also affect how molecules interact with each other in the liquid state. Trends in halides are influenced by increasing atomic size and electron cloud distortion, which enhances intermolecular attraction. The arrangement of atoms and Molecular symmetry can further modify these physical properties. Comparative analysis of halides involves understanding how halogen identity impacts physical behavior across similar alkyl groups.
Option b – Vajid: RI > RBr > RCl
Nicol’s prism is constructed by cementing two crystals of CaCO3 using adhesive ( ChemistryClass 9 Chapter mcq )
(A) Glycine
(B) Canada balsam
(C) Cement
(D) Synthetic gum
Explanation: Nicol’s prism is an optical device used to produce plane-polarized light through double refraction in calcite crystals. The working principle depends on the difference in refractive indices for ordinary and extraordinary rays within the crystal. A suitable adhesive is used between two specially cut calcite halves to eliminate the undesired ray through total internal reflection and transmission control. This ensures only one plane of vibration emerges from the prism. The choice of material is important because it must have a refractive index between those of the two rays to facilitate separation. Optical polarization depends on controlled interaction of light with anisotropic crystalline structures.
Option b – Canada balsam
Dextro rotatory isomers rotate the plane of plane-polarized light in
(A) Left side
(B) Anticlockwise direction
(C) Right side
(D) Left or right side
Explanation: Optical isomerism arises due to chirality in molecules, where asymmetric carbon atoms cause compounds to interact differently with plane-polarized light. When such light passes through an optically active substance, the plane of vibration is rotated either to the left or right depending on Molecular structure. The direction of rotation is a measurable physical property used to distinguish enantiomers. This behavior is linked to how Molecular asymmetry interacts with electromagnetic waves. The extent and direction of rotation depend on concentration, path length, and intrinsic Molecular properties. Optical rotation is a key concept in stereochemistry and helps identify different spatial arrangements of atoms in chiral compounds.
Option c – Right side
Tetrahedral carbon linked to four different atoms or groups is called ( Chemistry Class 9 Chapter mcq )
(A) Optically inactive carbon
(B) Optically active carbon
(C) Achiral carbon
(D) Stereocenter
Explanation: In Organic Chemistry, carbon atoms can exhibit different spatial arrangements depending on the nature of their Bonding. When a carbon Atom is bonded to four different substituents, it creates a non-superimposable mirror image relationship. This structural feature leads to chirality, which is responsible for optical activity in molecules. The geometry of such carbon centers is typically tetrahedral due to sp³ hybridization. This arrangement prevents symmetry, making the Molecule capable of interacting differently with polarized light. The presence of such centers is crucial in stereochemistry because it defines how molecules behave in biological and chemical systems. Spatial arrangement of atoms around this carbon determines the overall stereochemical identity of the compound.
Option d – Stereocenter
An Organic substance is asymmetric and optically active when
(A) It has an asymmetric carbon and lacks symmetry.
(B) It has an asymmetric carbon and one of the symmetry.
(C) It has no asymmetric carbon but has symmetry.
(D) It has no asymmetric carbon and symmetry.
Explanation: Optical activity in Organic compounds arises due to Molecular asymmetry, where structures lack internal symmetry elements such as planes or centers of symmetry. Such molecules interact with plane-polarized light in a specific manner, causing rotation of the light’s plane. The presence of asymmetric carbon atoms often contributes to this property, although overall Molecular symmetry is the deciding factor. The arrangement of atoms in three-dimensional space determines whether a compound can exist as non-superimposable mirror images. This structural characteristic plays a key role in stereochemical behavior and is widely observed in biologically important molecules. Molecular geometry and symmetry considerations are essential in predicting optical activity.
Option a – It has an asymmetric carbon and lacks symmetry
The equimolar mixture of d and l forms of optically active compounds is called ( Chemistry Class 9 Chapter mcq )
(A) Optical antipodes
(B) Enantiomers
(C) Racemic mixture
(D) Optical isomers
Explanation: Optical isomerism arises when molecules exist in forms that are non-superimposable mirror images of each other. These mirror-image forms rotate plane-polarized light in opposite directions but by equal magnitude. When equal amounts of both forms are present together, their optical effects cancel out, leading to no NET rotation. This cancellation occurs because the contributions of each form are equal and opposite. Such mixtures are commonly formed during reactions that do not favor one stereochemical configuration over the other. The resulting system appears optically inactive despite containing chiral molecules. This phenomenon is an important concept in stereochemistry and helps explain why some mixtures do not exhibit optical rotation even when they contain optically active components.
Option c – Racemic mixture
Light containing single-color waves vibrating in all possible planes is called
(A) Ordinary light
(B) Monochromatic light
(C) Plane-polarized light
(D) Red-colored light
Explanation: Light can be classified based on wavelength composition and direction of vibration. When light consists of only one wavelength but its vibrations occur randomly in all planes perpendicular to the direction of propagation, it exhibits a specific optical nature. Such light is emitted from certain sources where a single frequency dominates but the vibration orientation is not restricted. This differs from light that has been filtered or processed through optical devices, which restrict vibration to a single plane. The behavior of light in different optical states is important in understanding polarization phenomena. The interaction of light with materials can further modify its vibration characteristics, leading to specialized optical effects.
Option b – Monochromatic light
A beam of light vibrating in a single plane is called ( Chemistry Class 9 Chapter mcq )
(A) Nicol’s prism
(B) Plane-polarized light
(C) Monochromatic light
(D) Ordinary light
Explanation: When light waves are restricted so that their Electric Field vibrates only in one direction perpendicular to the direction of travel, it exhibits a highly ordered form of vibration. This restriction is usually achieved using optical devices that filter out all other vibration directions. Such light behaves differently from ordinary light, especially when interacting with anisotropic materials. The controlled orientation of vibration makes it useful in studying molecular structure and optical activity. This property is widely used in optical instruments and analytical techniques to analyze substances based on their interaction with polarized light. The concept is central to understanding how light can be manipulated for scientific and technological applications.
Option b – Plane-polarized light
Nicol’s prism is constructed from
(A) Calcite
(B) CaCO3
(C) Iceland spar
(D) Any of these
Explanation: Nicol’s prism is an optical device designed to produce plane-polarized light by exploiting the phenomenon of double refraction in certain crystalline materials. It uses a naturally birefringent crystal that splits incident light into two rays with different refractive indices. One of these rays is eliminated through internal reflection, while the other is transmitted in a single plane of vibration. The crystal is cut and joined using a suitable medium that allows selective passage of light. This setup ensures that only one type of polarized light emerges from the device. The structural and optical properties of the crystal are essential for its functioning in polarization experiments.
Option d – Any of these
Molecularity of a reaction is decided on the basis of
(A) Transition state
(B) Fast step
(C) Kinetic expression
(D) Rate-determining step
Explanation: chemical reactions occur through stepwise molecular interactions where reactant species collide and transform into products. The concept of molecularity refers to the number of reacting species involved in a single elementary step of a reaction mechanism. It is determined by examining the simplest reaction step rather than the overall reaction equation. This helps in understanding how molecules interact at the microscopic level during a reaction event. Molecularity is always a whole number because it involves discrete particles coming together simultaneously. It is a theoretical concept used in reaction mechanism studies and differs from reaction order, which is determined experimentally from rate laws.
Option d – Rate-determining step
Chiral molecules are those which are ( Chemistry Class 9 Chapter MCQ )
(A) Show chain isomerism
(B) Show metamers
(C) Superimposable on their mirror image
(D) Non-superimposable on their mirror image
Explanation: Molecular chirality arises when a structure lacks internal symmetry and cannot be superimposed on its mirror image. Such molecules exist as pairs of forms that are mirror images but not identical in spatial arrangement. This property results in distinct interactions with plane-polarized light and other chiral environments. The absence of symmetry elements like planes or centers of symmetry is the key reason for this behavior. Chirality is often associated with tetrahedral carbon atoms bonded to four different substituents. This spatial arrangement leads to unique chemical and biological properties, especially in stereochemical reactions and molecular recognition processes.
Option d – Non-superimposable on their mirror image
The total number of optical isomers of fructose is
(A) 2
(B) 4
(C) 8
(D) 16
Explanation: Optical isomerism in carbohydrates arises due to the presence of multiple asymmetric carbon atoms in their structure. Each chiral center can give rise to different spatial arrangements, increasing the number of possible stereoisomers. The total number of optical isomers depends on the number of such stereocenters and follows a mathematical relationship based on combinatorial arrangements. These isomers may differ in how they interact with plane-polarized light while maintaining the same molecular formula. Structural complexity in sugars leads to a variety of stereochemical forms, which play important roles in biological systems. The arrangement of hydroxyl groups around asymmetric carbons determines the final stereochemical diversity observed.
Option c – 8
The process of separation of a racemic mixture into d and l enantiomers is called ( Chemistry Class 9 Chapter MCQ )
(A) Resolution
(B) Dehydration
(C) Revolution
(D) Dehydrohalogenation
Explanation: Racemic mixtures contain equal amounts of two enantiomers that rotate plane-polarized light in opposite directions, resulting in no NET optical activity. Separating these two components requires a method that can distinguish between their spatial configurations. This process often involves converting enantiomers into diastereomers using another chiral substance, making them separable based on physical properties. Once separated, the original enantiomers can be recovered. This technique is important in stereochemistry and Pharmaceutical chemistry because different enantiomers can have different biological effects. The process relies on differences in interactions with chiral environments rather than simple physical separation methods.
Option a – Resolution
A detailed study of the path followed by reactants during their conversion into products is called:
(A) Order of reaction
(B) Mechanism of reaction
(C) Rate of reaction
(D) Molecularity of reaction
Explanation: chemical reactions occur through specific pathways involving multiple intermediate steps before forming final products. These steps include bond breaking, bond formation, and transient intermediate species. Studying this pathway helps in understanding how reactants transform at the molecular level. The sequence of elementary steps provides insight into reaction speed, intermediates, and energy changes. This conceptual framework is essential in physical chemistry for predicting and explaining how reactions proceed. It focuses on the mechanism rather than just the initial and final states of the reaction. Understanding this pathway helps in designing better reaction conditions and catalysts.
Option b – Mechanism of reaction
Objects that are superimposable in their mirror images are called
(A) Chiral
(B) Achiral
(C) Asymmetric molecules
(D) Configuration
Explanation: Molecular and geometric symmetry plays an important role in determining whether an object can be distinguished from its mirror image. When an object can be placed over its mirror image in such a way that all parts match exactly, it indicates the presence of internal symmetry elements. These may include planes of symmetry or centers of symmetry that make the structure identical in three-dimensional space. Such objects do not exhibit chirality and therefore do not interact differently with plane-polarized light. The ability to overlap perfectly with its mirror image is a key concept used in stereochemistry to distinguish between different types of spatial arrangements. This property is closely linked with molecular behavior in optical phenomena.
Option b – Achiral
Find out the wrong statement about optical activity:
(A) Sphere, cube, and cone are superimposable with their mirror images.
(B) Pair of human hands are superimposable with each other.
(C) The objects which are superimposable with mirror images are called chiral molecules.
(D) The objects that are non-superimposable with mirror images are called achiral molecules.
Explanation: Optical activity depends on the presence of chiral structures that can rotate plane-polarized light due to asymmetry in their spatial arrangement. Objects with perfect symmetry, such as certain geometric shapes, do not exhibit this property. In stereochemistry, chirality and achirality are distinguished based on whether an object can be superimposed on its mirror image. Human hands are a common example of non-superimposable mirror images, while symmetric shapes are not. Misinterpretations often arise when symmetry and chirality concepts are interchanged. Understanding these differences is essential for correctly identifying whether a substance or object will show optical rotation under polarized light conditions.
Option b – Pair of human hands are superimposable with each other
The process of conversion of enantiomers into a racemic mixture is called
(A) Retention of configuration
(B) Racemisation
(C) Racemic modification
(D) Inversion of configuration
Explanation: Enantiomers are pairs of stereoisomers that are non-superimposable mirror images and rotate plane-polarized light in opposite directions. When a system allows interconversion or loss of stereochemical purity between these forms, the resulting mixture contains equal proportions of both optical forms. This happens when the chiral center becomes planar or undergoes a reaction pathway that removes stereochemical distinction, often through intermediate formation. Such a process eliminates optical activity because the opposite rotations cancel each other out. The transformation is important in stereochemistry as it explains how optically active substances can become inactive under certain conditions, especially in chemical reactions involving unstable intermediates or high-energy conditions.
Option b – Racemisation
Which of the following haloalkanes is gaseous?
(A) Pentyl chloride
(B) Propyl chloride
(C) Ethyl chloride
(D) Butyl chloride
Explanation: The physical state of haloalkanes depends on molecular Mass and the strength of intermolecular forces acting between molecules. Smaller haloalkanes with lower molecular weight tend to exist as gases at room temperature because weaker dispersion forces are not sufficient to keep them in liquid form. As the size of the alkyl group increases, intermolecular attractions become stronger, leading to higher boiling points and a shift toward liquid or Solid states. The nature of the halogen also influences these properties due to differences in atomic size and polarizability. Thus, lighter haloalkanes with shorter carbon chains are more likely to remain in the gaseous state under normal conditions.
Option c – Ethyl chloride
Select the correct order of boiling point of alkyl halide.
Explanation: Boiling points of alkyl halides are influenced by intermolecular forces, particularly van der Waals forces and dipole–dipole interactions. The strength of these forces increases with molecular size and polarizability of the halogen Atom. Heavier halogens generally lead to stronger dispersion forces, resulting in higher boiling points. Structural factors such as branching also affect boiling point, as more compact molecules have reduced surface area for intermolecular contact. Linear structures tend to have higher boiling points compared to branched ones due to better molecular packing. Comparing different alkyl halides involves analyzing how halogen type and carbon skeleton together influence overall intermolecular attraction and physical behavior.
Option a – 1-chlorobutane > 2-chlorobutane > 2-chloro-2-methyl propane
The property of a substance to rotate the plane of plane-polarized light toward clockwise or anticlockwise direction is called
(A) Optical inactivity
(B) Optical activity
(C) Asymmetric compound
(D) Racemates
Explanation: Certain Organic molecules possess the ability to interact with plane-polarized light due to their three-dimensional asymmetry. When such light passes through these substances, the orientation of its vibration changes depending on the internal structure of the molecules. This behavior arises because chiral molecules interact differently with left- and right-handed components of light. The direction of rotation can be observed using an optical instrument designed to measure angular displacement. This phenomenon is widely used in stereochemical analysis to distinguish between different spatial arrangements of atoms in molecules. The extent and direction of rotation depend on molecular structure, concentration, and path length of the light through the sample.
Option b – Optical activity
The angle through which the plane of plane-polarized light is rotated is measured by
(A) Chirality meter
(B) Stereometer
(C) Optical meter
(D) Polarimeter
Explanation: When plane-polarized light passes through an optically active substance, its plane of vibration rotates by a measurable angle. This rotation is a key property used in studying chiral compounds and their behavior in solution. To accurately determine this change, a specialized optical instrument is used that allows precise alignment of polarizers and detection of angular displacement. The measurement helps in analyzing purity, concentration, and stereochemical composition of substances. The accuracy of this method depends on proper calibration and control of experimental conditions such as temperature and wavelength of light. It is a fundamental technique in optical chemistry for studying molecular asymmetry and its effects on light.
Option d – Polarimeter
The number of reactants whose concentration decides the rate of reaction is called as
(A) Molecularity of reaction
(B) Kinetic expression
(C) Mechanism
(D) Order of reaction
Explanation: Chemical reaction rates depend on the concentration of reactant species involved in the rate-determining step. The relationship between concentration and rate is expressed through a mathematical expression known as the rate law. This law helps describe how changes in concentration influence reaction speed. The number of species whose concentrations appear in this expression determines how sensitive the reaction rate is to changes in reactant amounts. This concept is derived experimentally and provides insight into reaction mechanisms. It helps in understanding how molecular collisions and intermediate formation affect the overall speed of chemical transformations in a system.
Option d – Order of reaction
If the hydroxyl group in 2-hydroxypropanoic Acid is replaced by a hydrogen Atom, what will happen?
(A) Optical activity is lost
(B) Optical activity is retained
(C) Form a racemic mixture
(D) Produce a non-superimposable mirror image
Explanation: The optical behavior of Organic molecules is closely related to the presence of asymmetric carbon atoms and specific functional groups attached to them. In compounds like hydroxy Acids, chirality arises due to a carbon Atom bonded to four different substituents. When a functional group such as hydroxyl is replaced by hydrogen, the arrangement around that carbon may lose its asymmetry depending on the overall structure. This change can significantly alter how the Molecule interacts with plane-polarized light. Optical activity is highly sensitive to even small structural modifications because it depends on spatial arrangement rather than just molecular formula. Removing or replacing a group can disrupt the balance needed for chirality, leading to a change in stereochemical behavior and optical properties.
Option a – Optical activity is lost
n-propyl bromide on boiling with aqueous caustic soda undergoes
(A) Hydrolysis
(B) Electrophilic substitution
(C) Free radical substitution
(D) Elimination
Explanation: Alkyl halides react with aqueous strong Bases through nucleophilic substitution reactions, where the halogen Atom is replaced by a nucleophile such as hydroxide ion. This process involves the breaking of the carbon–halogen bond and formation of a new carbon–oxygen bond. The reaction pathway depends on the structure of the alkyl halide, with primary halides generally favoring direct substitution mechanisms. The nucleophile attacks the carbon Atom bonded to the halogen, leading to displacement of the leaving group. Reaction conditions such as solvent and temperature influence whether substitution or elimination dominates. In aqueous medium, substitution is typically favored, leading to formation of Alcohol-type products through hydrolysis pathways.
Option a – Hydrolysis
Ter. pentyl chloride on heating with moist silver oxide produces
Explanation: Hydrolysis of alkyl halides in the presence of moist silver oxide involves replacement of the halogen Atom by a hydroxyl group. The reaction proceeds more readily for tertiary halides due to the formation of stable intermediate species during the transformation. The leaving halogen is assisted by the formation of insoluble silver halide, which drives the reaction forward. The mechanism is influenced by the stability of carbocation-like intermediates formed during bond cleavage. Tertiary structures favor faster conversion due to greater stabilization through electronic effects. The overall process results in substitution of the halogen with a hydroxyl group, producing corresponding Alcohols under suitable conditions.
Option d – 2-Methyl butan-2-ol
Methyl iodide on heating with alcoholic potassium cyanide produces
(A) Nitromethane
(B) Acetonitrile
(C) Methyl isocyanide
(D) Formonitrite
Explanation: Alkyl halides undergo nucleophilic substitution reactions with cyanide ions, where the halogen is replaced by the cyanide group. The reaction can proceed through either carbon or nitrogen attack depending on conditions and reagents used. In alcoholic medium, nucleophilic substitution is favored, leading to formation of nitrile compounds. The cyanide ion acts as a strong nucleophile, attacking the carbon attached to the halogen and displacing it. This reaction is important in Organic synthesis because it increases carbon chain length and introduces functional groups that can be further transformed. The mechanism depends on the structure of the alkyl halide and reaction Environment, influencing the product distribution.
Option b – Acetonitrile
What are the constituents of alloy solder?
(a) Pb and Zn
(b) Pb and Sn
(c) Pb and Si
(d) Pb and Co
Explanation: Alloys are mixtures of Metals designed to improve certain physical properties such as melting point, strength, and conductivity. Solder is a commonly used alloy in joining metal surfaces, especially in electrical and mechanical applications. It is formed by combining Metals that create a low melting mixture, allowing easy fusion and solidification. The choice of constituent Metals ensures good adhesion and conductivity while maintaining structural stability. The composition is selected to achieve a balance between melting behavior and mechanical strength. Such alloys are widely used in industrial processes where joining of components requires controlled melting and solidification properties.
Option b – Pb and Sn
Which one of the following Acids is secreted by the leaves of Nettle that causes painful stings?
Explanation: Some plants produce defensive chemical compounds that protect them from herbivores and environmental threats. These compounds are stored in specialized structures and released upon contact or injury. OrganicAcids are among the substances that can cause irritation or pain when they come into contact with skin. Their chemical nature allows them to interact with biological tissues, leading to a burning sensation. Such Acids are part of plant defense mechanisms and are often simple carboxylic Acids found in nature. Their presence highlights how biochemical compounds play a role in ecological survival strategies.
When copper reacts with moist carbon dioxide (CO2) in the air, it forms a green coating of which one of the following compounds?
(a) Cupric carbonate
(b) Cuprous oxide
(c) Cupric oxide
(d) Copper sulfate
Explanation: Metals exposed to air and moisture undergo slow chemical changes known as corrosion. Copper, when exposed to atmospheric gases including oxygen, carbon dioxide, and water vapor, forms a surface layer of compounds. These compounds are stable under environmental conditions and appear as a green coating. The formation involves oxidation reactions followed by interaction with atmospheric gases. This protective layer can prevent further corrosion of the underlying metal. The process depends on environmental exposure and the chemical reactivity of the metal surface with surrounding gases.
Option a – Cupric carbonate
What is the name of the process that converts sulfide ores into oxides by heating strongly in the presence of excess air?
(a) Calcination
(b) Roasting
(c) Smelting
(d) Incineration
Explanation: Metallurgical processes involve converting ores into usable metal forms through chemical transformations. Sulfide ores are often converted into oxides before further reduction to pure Metals. This conversion is achieved by heating the ore in the presence of excess air, allowing oxygen to react with sulfur-containing compounds. The process removes sulfur as gaseous oxides and leaves behind metal oxides. It is an important step in extraction Metallurgy because oxides are generally easier to reduce to Metals. The efficiency of the process depends on temperature, air supply, and nature of the ore being treated.
Option b – Roasting
Which one of the following gases produces a red light when Electricity flows through it?
(a) Helium
(b) Argon
(c) Nitrogen
(d) Neon
Explanation: When electrical energy is passed through gases at low pressure, the atoms become excited and emit light of characteristic wavelengths upon returning to their ground state. Each gas produces a unique color due to its specific electronic structure. The emitted light depends on the energy difference between electronic levels. These properties are used in discharge tubes and lighting applications. Noble gases are commonly used for such purposes because they are chemically inert and produce distinct colors under electrical excitation. The observed color is a result of photon emission during electronic transitions.
Option d – Neon
Which one of the following methods can be used to remove the permanent hardness of water?
(a) Boiling
(b) Ion-exchange
(c) Lime treatment
(d) Bubbling sulfur dioxide gas
Explanation: Water hardness is caused by dissolved calcium and magnesium Salts, which interfere with soap action. Permanent hardness arises mainly due to sulfates and chlorides of these Metals, which cannot be removed by simple boiling. Specialized chemical or ion-exchange methods are used to eliminate these ions from water. These processes replace hardness-causing ions with more soluble or harmless ions. The effectiveness of each method depends on water composition and treatment conditions. Removing hardness improves water usability for industrial and domestic purposes by preventing scale formation and improving cleaning efficiency.
Option b – Ion-exchange
Which one of the following is NOT a component of photochemical smog?
Explanation: Photochemical smog forms when sunlight-driven reactions occur between nitrogen oxides and volatile Organic compounds present in the Atmosphere. These reactions produce a mixture of secondary pollutants such as ozone and various reactive nitrogen-containing compounds. The formation process depends on strong sunlight and the presence of Hydrocarbons released from vehicles and industrial activities. Some components are directly emitted, while others are formed through complex photochemical reactions involving radicals. The resulting mixture affects air quality and visibility and can irritate the respiratory system. Understanding the composition of such smog involves identifying both primary pollutants and secondary reaction products formed under sunlight exposure.
(c) In graphite, each carbon atom is linked to three other carbon atoms
(d) Atomic weight is the most fundamental characteristic of an element
Explanation: Elements and compounds exhibit properties that depend on their Atomic Structure and Bonding. Carbon exists in multiple allotropic forms with distinct physical and chemical characteristics. Some forms of carbon have high electrical conductivity due to their Bonding arrangement, while others are poor conductors. Atomic properties are fundamental in classifying elements and understanding Periodic trends. Misconceptions often arise when general properties are incorrectly assigned to all allotropes or when exceptions in physical behavior are overlooked. Understanding the relationship between structure and properties is essential for correctly evaluating statements about elements and their forms.
Option b – Diamond is a good conductor of Electricity
Which one of the following statements about alkaline EarthMetals is NOT true?
(b) Barium metal is used in medicine to examine the alimentary canal of a patient by X-ray
(c) Green plants need magnesium to make the chlorophyll that traps energy from sunlight in photosynthesis
(d) The red color of the gemstone Ruby is due to the element beryllium present in it
Explanation: Alkaline EarthMetals belong to a group of reactive elements with similar outer electronic configurations, leading to comparable chemical behavior. They form characteristic compounds and exhibit predictable trends in properties such as reactivity, flame coloration, and biological importance. Some of their compounds are widely used in industry and medicine due to their chemical stability and reactivity patterns. However, confusion often arises when attributing properties to specific elements or gemstones without considering their actual chemical composition. Understanding Periodic trends and correct elemental associations is important for identifying inaccurate statements about this group of Metals.
Option d – The red color of the gemstone Ruby is due to the element beryllium present in it
Which one of the following is the most fundamental characteristic of an element?
(a) Melting point
(b) Atomic number
(c) Colour
(d) Atomic weight
Explanation: Elements are defined by the number of protons present in their atomic nucleus, which determines their identity and position in the Periodic Table. This fundamental property distinguishes one element from another, regardless of isotopes or atomic Mass variations. Other properties such as Mass, color, or physical behavior can vary due to isotopic differences or environmental conditions. The Atomic Structure governs chemical behavior and Periodic trends, making it the most reliable identifier of an element. Understanding this concept is essential for interpreting Periodic relationships and distinguishing between different atomic species in chemistry.
Option b – Atomic number
The radioactive isotope of hydrogen is:
(a) Protium
(b) Deuterium
(c) Tritium
(d) Hydronium
Explanation: Hydrogen exists in multiple isotopic forms that differ in the number of neutrons present in the nucleus. These isotopes have identical chemical properties but differ in nuclear stability. Some isotopes are stable and commonly found in nature, while others are unstable and undergo radioactive decay. Radioactivity arises when the nucleus has an imbalance in neutron-to-proton ratio, leading to spontaneous emission of radiation to achieve stability. Such isotopes are useful in scientific research, tracing reactions, and nuclear studies due to their detectable decay patterns and energy emission characteristics.
Option c – Tritium
Which one of the following is used for storing biological tissues?
(a) Liquid nitrogen
(b) Liquid helium
(c) Liquid argon
(d) Liquid bromine
Explanation: Biological materials require extremely low temperatures for preservation to prevent enzymatic activity and microbial growth. Cryogenic liquids are used to rapidly freeze and store tissues by maintaining temperatures far below the freezing point of water. This prevents cellular degradation and preserves structural integrity over long periods. The effectiveness of storage depends on the ability of the cooling medium to maintain stable, ultra-low temperatures without chemical interaction with the biological material. Such methods are widely used in medical, biological, and research applications for long-term preservation of sensitive samples.
Option a – Liquid nitrogen
Which one of the following does not form oxide on reaction with oxygen?
(a) Magnesium
(b) Lead
(c) Tin
(d) Silver
Explanation: Metals react with oxygen to form oxides depending on their reactivity and position in the electrochemical series. Some metals readily form stable oxide layers, while others are less reactive under normal conditions. The formation of oxides depends on thermodynamic stability and reaction kinetics. Certain noble or less reactive metals resist oxidation due to their stable electronic configuration and protective surface behavior. Understanding oxidation tendencies helps in predicting corrosion resistance and chemical reactivity of different elements when exposed to atmospheric oxygen.
Option d – Silver
Which of the following Polymers is NOT a thermoplastic?
(a) Teflon
(b) Neoprene
(c) Polystyrene
(d) Polythene
Explanation: Polymers are broadly classified based on their behavior upon heating. Thermoplastics soften when heated and can be remolded, while thermosetting Polymers form rigid structures that do not melt upon reheating. This difference arises from the nature of Bonding between polymer chains. Thermosetting materials contain strong cross-linked networks that prevent rearrangement of molecular chains. These structural differences determine their Mechanical Properties and applications. Understanding polymer classification is essential for selecting materials based on flexibility, durability, and Heat resistance requirements.
Option b – Neoprene
Symbol of the element was introduced by:
(a) John Dalton
(b) Antoine Lavoisier
(c) Jons Jacob Berzelius
(d) Robert Boyle
Explanation: The modern system of chemical symbols was developed to provide a standardized way of representing elements in chemical equations and scientific Communication. Earlier systems used complex or inconsistent representations, making it difficult to study chemical reactions systematically. The introduction of a uniform symbolic system allowed elements to be represented by letters derived from their names, improving clarity and universality. This development played a key role in advancing modern chemistry by simplifying notation and enabling easier interpretation of chemical formulas and reactions across different languages and scientific communities.
Option c – Jons Jacob Berzelius
Identify the correct pair of elements among the following which are liquid at room temperature and standard pressure.
(a) Bromine and fluorine
(b) Mercury and rubidium
(c) Bromine and thallium
(d) Bromine and mercury
Explanation: The physical state of elements at room temperature depends on intermolecular forces and atomic or molecular structure. Most elements exist as Solids due to strong Bonding, while a few exist as gases or liquids depending on their atomic interactions. Liquids are relatively rare among elements and are determined by weak intermolecular forces that allow fluidity at standard conditions. The state of Matter is influenced by atomic size, Bonding type, and electron distribution. Understanding these properties helps classify elements based on their physical behavior under normal environmental conditions.
Option d – Bromine and mercury
Which one of the following oxides shows both acidic and basic behavior?
(a) Zinc oxide
(b) Copper oxide
(c) Magnesium oxide
(d) Calcium oxide
Explanation: Oxides of elements can be classified based on their chemical behavior in reactions with Acids and Bases. Some oxides react only with Acids, some only with Bases, while a few can react with both depending on conditions. This dual behavior arises from their intermediate nature in the Periodic Table and their ability to exhibit amphoteric characteristics. Such oxides can form Salts and water when reacting with either acidic or basic substances. Their behavior depends on the nature of Bonding and the element’s position in the Periodic classification. Understanding this helps in predicting how different metal and non-metal oxides will behave in chemical reactions and industrial processes.
Option a – Zinc oxide
Silver articles turn black when kept in the open for a longer time due to the formation of:
(a) H₂S
(b) AgS
(c) AgSO4
(d) Ag₂S
Explanation: Metals exposed to atmospheric gases undergo surface reactions that gradually change their appearance and properties. Silver, when exposed to trace gases containing sulfur compounds in the air, reacts to form a thin surface layer. This layer is dark in color and reduces the shine of the metal. The reaction occurs slowly over time and is influenced by environmental conditions such as humidity and Pollution. The formation of this layer is an example of corrosion, where a metal reacts with its surroundings to form a compound on its surface. Such processes are common in metals exposed to air over long periods.
Option d – Ag₂S
Rutherford’s alpha particle scattering experiment on thin gold foil was responsible for the discovery of:
(a) electron
(b) proton
(c) atomic nucleus
(d) neutron
Explanation: The structure of the atom was investigated through experiments involving the scattering of high-energy particles through thin metal foils. When alpha particles were directed at a thin sheet of metal, most passed through with little deflection, while a few were deflected at large angles. This observation indicated that most of the atom is empty space with a small, dense, positively charged center. The experimental results helped establish a new model of the atom, replacing earlier assumptions about uniform distribution of charge. This discovery fundamentally changed the understanding of Atomic Structure and led to further developments in nuclear Physics.
Option c – atomic nucleus
Which of the following fertilizers has more nitrogen content?
(a) Urea
(b) Ammonium Nitrate
(c) Potassium Nitrate
(d) Ammonium Phosphate
Explanation: Fertilizers are chemical compounds used to supply essential nutrients to plants, promoting growth and productivity. Nitrogen-containing fertilizers are particularly important because nitrogen is a key element in proteins and chlorophyll formation. The nitrogen content varies depending on the molecular composition and proportion of nitrogen atoms in the compound. Some fertilizers are designed to release nitrogen efficiently into the soil, improving plant absorption. The effectiveness of a fertilizer depends on both its nutrient concentration and availability to plants. Understanding nutrient composition is essential for selecting appropriate fertilizers for agricultural use.
Option a – Urea
Which one of the following is known as Wood Spirit?
(a) Methanol
(b) Ethanol
(c) Formaldehyde
(d) Acetaldehyde
Explanation: Certain Organic compounds obtained historically through the destructive distillation of wood were given traditional names based on their source and properties. These substances were among the earliest studied organic chemicals and played an important role in the development of Organic Chemistry. They are typically simple Alcohols or related compounds formed during thermal decomposition of biomass. Such compounds have characteristic properties including volatility and flammability. The historical naming reflects early chemical processes used to isolate organic substances before modern synthetic methods were developed.
Option a – Methanol
Which one of the following will NOT show the Tyndall effect?
(a) Chalk powder freshly mixed with water
(b) Lime juice
(c) A few drops of milk mixed with water
(d) Starch solution
Explanation: The Tyndall effect refers to the scattering of light by particles in a colloidal system, making the path of light visible. It is observed when the dispersed particles are large enough to scatter light but small enough to remain suspended. True solutions, however, have particles that are too small to scatter visible light effectively, so they do not show this effect. The phenomenon depends on particle size and the nature of the mixture. Understanding this helps distinguish between colloids and true solutions in physical chemistry. The presence or absence of light scattering is a key diagnostic feature for identifying types of mixtures.
Option b – Lime juice
Which of the following are the most favorable conditions for liquefying a gas?
(a) Low-pressure and high-temperature
(b) Low pressure and low temperature
(c) High pressure and high temperature
(d) High pressure and low temperature
Explanation: The state of a gas depends on the balance between kinetic energy of particles and intermolecular attractive forces. To convert a gas into a liquid, conditions must favor increased attraction and reduced particle motion. Lowering temperature reduces kinetic energy, while increasing pressure brings particles closer together, enhancing attractive forces. These combined conditions promote condensation of gas molecules into the liquid phase. The efficiency of liquefaction depends on how effectively these parameters overcome molecular motion. This principle is widely used in industrial gas liquefaction and storage systems.
Option d – High pressure and low temperature
Aluminium, Iron, Copper, and Zinc are extracted from:
(a) Bauxite, Magnetite, Malachite, and Calamine respectively
(b) Magnetite, Bauxite, Malachite, and Calamine respectively
(c) Calamine, Malachite, Magnetite, and Bauxite respectively
(d) Malachite, Magnetite, Bauxite, and Calamine respectively
Explanation: Metals are obtained from naturally occurring ores through metallurgical processes involving extraction and purification. Each metal is associated with a specific ore from which it is economically and chemically feasible to extract the pure metal. These ores contain metal compounds such as oxides, carbonates, or sulfides that undergo chemical treatment to isolate the metal. The selection of ore depends on availability, metal content, and ease of extraction. Different extraction methods such as roasting, smelting, or reduction are used depending on the nature of the ore. Understanding ore sources is essential in Metallurgy for efficient industrial production of metals.
Option a – Bauxite, Magnetite, Malachite, and Calamine respectively
(a) sulphuric Acid and solution of sodium hydrogen carbonate
(b) nitric Acid and solution of sodium hydrogen carbonate
(c) sulphuric Acid and solution of potassium carbonate
(d) nitric acid and solution of potassium carbonate
Explanation: Fire extinguishers operate on chemical reactions that produce gases capable of displacing oxygen or cooling the fire. The soda-acid type works by generating carbon dioxide gas through the reaction of an acid with a bicarbonate solution. When activated, the components mix and produce effervescence, releasing gas that helps suppress combustion. The design ensures that the reaction occurs only when needed, allowing controlled discharge. The effectiveness depends on rapid gas formation and its ability to smother flames. This type of extinguisher is commonly used for ordinary fires involving flammable materials.
Option a – sulphuric acid and solution of sodium hydrogen carbonate
Quartz is extensively used as a piezoelectric material. It contains:
(a) Hg
(b) Si
(c) Ti
(d) Sn
Explanation: Certain crystalline Solids exhibit the piezoelectric effect, where mechanical stress generates an electric charge and vice versa. This property arises due to the asymmetric arrangement of atoms in the crystal lattice, which allows charge separation under deformation. Quartz is one such mineral widely used in electronic devices because of its stable crystal structure and consistent response to mechanical pressure. Its usefulness depends on the presence of a specific element forming a strong, rigid framework that supports this lattice behavior. The internal Bonding in such materials is responsible for their ability to convert mechanical energy into electrical signals, making them valuable in oscillators, sensors, and timing devices.
Option b – Si
Which one of the following statements is not correct?
(a) Elements are defined by the number of protons they possess.
(b) Isobars are atoms having the same atomic number but different Mass numbers.
(c) The Mass number of an atom is equal to the number of nucleons in its nucleus.
(d) Valency is the combined capacity of an atom.
Explanation: Atomic Structure and Periodic classification depend on fundamental properties such as atomic number, Mass number, and nuclear composition. These properties help define elements and their isotopes, as well as their placement in the Periodic Table. Some statements may incorrectly interchange these concepts, leading to confusion between atomic number and Mass number or their roles in defining identity. Valency is related to combining capacity and depends on electronic configuration. Understanding these distinctions is essential for interpreting chemical behavior correctly and avoiding conceptual errors in atomic theory and Periodic trends.
Option b – Isobars are atoms having the same atomic number but different Mass numbers
In graphite, each carbon atom is bonded to three other carbon atoms:
(a) forming a three-dimensional structure
(b) in the same plane giving a hexagonal array
(c) in the same plane giving a square array
(d) in the same plane giving a pentagonal array
Explanation: Carbon exists in multiple allotropes with different Bonding arrangements that determine its physical properties. In graphite, carbon atoms are arranged in layers where each atom forms bonds with three neighboring carbon atoms. This arrangement leads to a planar structure with hexagonal patterns. The remaining electrons are delocalized, allowing electrical conductivity within layers. The layered structure also allows easy sliding between sheets, giving graphite its lubricating properties. The geometry arises from sp² hybridization, which results in strong covalent Bonding within planes but weak interactions between layers. This structural arrangement is responsible for the unique physical characteristics of graphite compared to other forms of carbon.
Option b – in the same plane giving a hexagonal array
Soap solution used for cleaning purposes appears cloudy. This is due to the fact that soap micelles can:
(a) refract light
(b) scatter light
(c) diffract light
(d) polarize light
Explanation: Soap molecules in water form aggregates known as micelles, where the hydrophobic tails cluster inward and the hydrophilic heads face outward. These structures interact with light passing through the solution, causing scattering. The scattering of light by dispersed particles in a colloidal system leads to a cloudy or opaque appearance. This phenomenon is characteristic of colloidal solutions and depends on particle size and distribution. The micelles remain dispersed in water and do not settle, which distinguishes them from true solutions. Their interaction with light is an important indicator of colloidal behavior in cleaning processes.
Explanation: Chromatography is a separation technique based on differences in distribution of components between stationary and mobile phases. It is highly effective for separating mixtures with components that differ in solubility, adsorption, or partition behavior. However, it is not suitable for separating species that are identical in chemical and physical properties or that do not interact differently with the phases involved. Separation depends on differential migration rates of components through the system. If substances behave identically under the conditions used, they cannot be separated by this method. The efficiency of chromatography relies on selective interactions between components and the stationary medium.
Option a – radio-isotopes
Consider the following statement: “The atomic number of an element is a more fundamental property than its atomic Mass.” Who among the following scientists has made the above statement?
(a) Dmitri Mendeleev
(b) Henry Moseley
(c) J. J. Thomson
(d) Ernest Rutherford
Explanation: The understanding of Atomic Structure evolved through experimental discoveries that revealed the importance of nuclear charge in defining elements. The atomic number, which represents the number of protons in the nucleus, determines the identity of an element. This concept replaced earlier ideas that relied primarily on atomic Mass for classification. The refinement of periodic classification led to a more accurate arrangement of elements based on atomic number rather than mass. This advancement provided clarity in resolving anomalies in earlier periodic tables and established a more consistent framework for understanding chemical properties and periodic trends.
Option b – Henry Moseley
Very small insoluble particles in a liquid may be separated from it by using:
(a) crystallization
(b) fractional distillation
(c) centrifugation
(d) decantation
Explanation: Mixtures containing very fine suspended particles require special methods for separation because gravity alone is often insufficient to settle them quickly. These particles remain dispersed due to their small size and interaction with the surrounding liquid. By applying an external force or specialized technique, the particles can be made to settle or separate from the liquid phase. This method increases the effective settling rate by enhancing the influence of density differences. It is commonly used in laboratory and industrial processes where rapid separation of fine suspensions is required. The effectiveness depends on particle size, density difference, and applied force.
Option d – decantation
Which one of the following statements about glass is not correct?
(a) Glass is often said to be a supercooled liquid.
(b) Glass has no definite melting point.
(c) Soda glass is harder than Pyrex glass.
(d) Boron is present in pyrex glass.
Explanation: Glass is an amorphous Solid with a disordered internal structure, lacking a sharp melting point. Its properties differ from crystalline Solids due to the irregular arrangement of its constituent atoms. Different types of glass are produced by modifying composition, such as adding boron or other elements to improve thermal resistance. The structural nature of glass allows it to behave differently under heating and cooling conditions compared to crystalline materials. Understanding its composition and structure helps explain its physical properties and industrial applications.
Option c – Soda glass is harder than Pyrex glass
We covered all the chemistry class 9 mcq above in this post for free so that you can practice well for the exam.
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