First Law of Thermodynamics in Hindi

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First Law of Thermodynamics in Hindi. We covered all the First Law of Thermodynamics in Hindi in this post for free so that you can practice well for the exam.

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Mock Test on First Law of Thermodynamics for Students
A system is given 300 cal of heat and it does 600J of work. How much does the internal energy of the system change in this process? (J = 4.18 J/cal)
The first law of thermodynamics is based on :
The pressure of a given mass of a gas in a thermodynamic system is changed in such a way that 20 J of heat is released from the gas and 8J of work is done on the gas. If the initial internal energy of the gas was 30 J then the final internal energy will be :
If the heat of 110 J is added to a gaseous system, whose internal energy is 40 J, then the amount of external work done is :
110 J of heat is added to a gaseous system, whose internal energy change is 40 J, then the amount of external work done is :
When the amount of work done is 300 cal and the change in internal energy is 167 cal, then the heat supplied is :
The first law of thermodynamics is given by :
The first law of thermodynamics is concerned with the conservation of
We consider a thermodynamic system. If du represents the increase in its internal energy and dW the work done by the system. Which of the following statement is true? :
A gas expands from a volume of 2 m³ to 6 m³ at a constant pressure of 10 N/m² and then at the constant volume of 6 m³, the pressure is changed from 10 N/m² to 20 N/m². The work done by the gas is :
In an isothermal change of an ideal gas, dU = 0. The change in heat energy dQ is equal to :

Mock Test on First Law of Thermodynamics for Students

A system is given 300 cal of heat and it does 600J of work. How much does the internal energy of the system change in this process? (J = 4.18 J/cal)

(A) -528.2 J

(B) -300 J

(C) 156.5 J

(D) 654 J

Option d - 654 J

The first law of thermodynamics is based on :

(A) Mass conservation

(B) Momentum conservation

(C) Energy conservation

(D) Heat exchange

Option c - Energy conservation

The pressure of a given mass of a gas in a thermodynamic system is changed in such a way that 20 J of heat is released from the gas and 8J of work is done on the gas. If the initial internal energy of the gas was 30 J then the final internal energy will be :

(A) 2 J

(B) 18 J

(C) 42 J

(D) 50 J

Option b - 18 J

If the heat of 110 J is added to a gaseous system, whose internal energy is 40 J, then the amount of external work done is :

(A) 150 J

(B) 110 J

(C) 70 J

(D) 40 J

Option c - 70 J

110 J of heat is added to a gaseous system, whose internal energy change is 40 J, then the amount of external work done is :

(A) 40 J

(B) 70 J

(C) 110 J

(D) 150 J

Option b - 70 J

When the amount of work done is 300 cal and the change in internal energy is 167 cal, then the heat supplied is :

(A) 166 cal

(B) 333 cal

(C) 500 cal

(D) 400 cal

Option c - 500 cal

The first law of thermodynamics is given by :

(A) dQ = dU + PdV

(B) dQ = (dU + dV) P

(C) dQ = dU x PdV

(D) dQ = PdU + dv

Option a - dQ = dU + PdV

The first law of thermodynamics is concerned with the conservation of

(A) Mass

(B) Energy

(C) Momentum.

(D) Temperature

Option b - Energy

We consider a thermodynamic system. If du represents the increase in its internal energy and dW the work done by the system. Which of the following statement is true? :

(A) dU = -dW in an isothermal process

(B) dU = dW in an isothermal process

(C) dU = -dW in an adiabatic process

(D) dU = dW in an adiabatic process

Option c - dU = -dW in an adiabatic process

A gas expands from a volume of 2 m³ to 6 m³ at a constant pressure of 10 N/m² and then at the constant volume of 6 m³, the pressure is changed from 10 N/m² to 20 N/m². The work done by the gas is :

(A) 40 erg

(B) 40 J

(C) 60 J

(D) 100 J

Option b - 40 J

In an isothermal change of an ideal gas, dU = 0. The change in heat energy dQ is equal to :

(A) 0.5 dW

(B) dW

(C) 1.5 dW

(D) 2dW

Option b - dW

We covered all the first law of thermodynamics in Hindi above in this post for free so that you can practice well for the exam.

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