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01 There are three bells which ring after 30 min, 80 min, and 90 min, respectively. If last time they rang simultaneously at 8:30 am. At what time they will again ring simultaneously?
- 8:35 am
- 8:35 pm
- 8:30 pm
- 8:40 am
Option 3 – 8:30 pm
02 LCM and HCF of two numbers are 96 and 4, respectively. If one of the numbers is 32, then find the another number
- 12
- 16
- 14
- 18
Option 1 – 12
03 The least number which when divided by 5,6,7 and 8 leaves a remainder 3, but when divided by 9 leaves no remainder
- 1677
- 1683
- 2523
- 3363
Option 2 – 1683
04 Which is the smallest number which leaves remainder 8 and 12 when divided by 28 and 32 respectively?
- 204
- 203
- 201
- 200
Option 1 – 204
05 The product of LCM and HCF of 3.02 and 1.8 is
- 5.436
- 5.346
- 5.643
- 5.364
Option 1 – 5.436
06 (Biggest common factor of 5, 10, and 50) + (Smallest common multiple of 10, 20, 30) is equal to
- 60
- 65
- 70
- 75
Option 2 – 65
07 If (the product of common positive factors of 39 and 52) = 5 x ‘….’ – 117, then the number which will come in blank is
- 26
- 30
- 13
- 15
Option 1 – 26
08 If (the sum of common positive factors of 15 and 90) = 15 x ‘…..’ – 36, then the number which will come in blank is
- 15
- 10
- 5
- 4
Option 4 – 4
09 Sum of all the factors of 96, which are the multiple of 8, is
- 224
- 226
- 228
- 230
Option 1 – 224
10 Find the product of HCF and LCM of 1.08, 0.36, and 0.9
- 0.999
- 1.009
- 0.900
- 0.972
Option 4 – 0.972
11 The LCM of two numbers is 864 and their HCF is 144. If one of the number is 288, the other number is
- 576
- 1296
- 432
- 144
Option 3 – 432
12 If the product of LCM and HCF is 124416. If one of the number is 864, the other number is
- 132
- 135
- 140
- 144
Option 4 – 144
13 The LCM and HCF of the numbers 28 and 42 are in the ratio
- 6:1
- 2:3
- 3:2
- 7:2
Option 1 – 6:1
14 The LCM of two numbers is 693 and their HCF is 11.26. One of the number is 77, the other number is
- 66
- 35
- 99
- 68
Option 3 – 99
15 If the ratio of two numbers is 3:4 and their LCM is 84 then find the larger number ( LCM AND HCF CTET MCQ )
- 21
- 28
- 24
- 84
Option 2 – 28
16 (Smallest common multiple of 8,12 and 15) – (Highest common factor of 64 and 80) is equal to
- 120
- 130
- 125
- 104
Option 4 – 104
17 (Smallest common multiple of 12 and 16) x (Smallest common multiple of 10 and 15) is equal to
- 960
- 720
- 1440
- 480
Option 3 – 1440
18 The sum of all the factors of 100 is ( LCM AND HCF CTET MCQ )
- 217
- 223
- 115
- 216
Option 1 – 217
19 The number of factors of 105 is
- 8
- 3
- 4
- 6
Option 1 – 8
20 The difference between the smallest common multiple and biggest common factor of 5,10 and 35 is
- 75
- 30
- 35
- 65
Option 4 – 65
21 The number of factors of 42 is
- 7
- 8
- 9
- 6
Option 2 – 8
22 The sum of positive factors of 210 is
- 576
- 575
- 573
- 366
Option 1 – 576
23 Difference of (Smallest common multiple of 4,5 and 6) and (smallest common multiple of 5,6 and 9) is
- 30
- 45
- 48
- 60
Option 1 – 30
24 The sum of all the positive factors of 96 is
- 251
- 252
- 155
- 156
Option 2 – 252
25 Sum of all the factors of 84, which are the multiple of 7 is
- 113
- 189
- 196
- 112
Option 3 – 196
26 The product of smallest common multiple and highest common factor of 30, 36 and 42 is
- 7460
- 7660
- 7650
- 7560
Option 4 – 7560
27 If (the product of common positive factors of 36 and 48) = 999 + 9 x ‘……’, then the number which will come in blank is
- 81
- 20
- 9
- 27
Option 1 – 81
28 A gardener wants to plant trees in a garden. If the number of trees in each row is the same and there are 20 or 40 or 60 rows, then no tree is left. Find the least number of trees the gardener have
- 120
- 360
- 240
- 200
Option 1 – 120
29 Find the least number which, when divided by 12, 16, 24 and 36, leaves a remainder 7 in each case
- 151
- 153
- 156
- 161
Option 1 – 151
30 There are three street lights which get on for one second after 30 s, 40 s, and 50 s, respectively. If last time they were on simultaneously at 4:00 pm. At what time after 4:00 pm all of them get on again simultaneously?
- 4:10 pm
- 4:11 pm
- 4:12 pm
- 4:14 pm
Option 1 – 4:10 pm
31 (Smallest common multiple of 25, 40 and 60) x (Smallest common multiple 12, 36, 48) is equal to
- 46800
- 68400
- 86400
- 6848
Option 3 – 86400
32 (Smallest common multiple of 18, 24, 48) x (Highest common factor of 18, 24 and 48) is
- 846
- 864
- 380
- 684
Option 2 – 864
33 Difference of (smallest common multiple of 18, 20 , 30) and (smallest common multiple of 36, 15, 21) is
- 1500
- 1080
- 900
- 1000
Option 2 – 1080
34 The number of factors of 84 is
- 10
- 18
- 14
- 12
Option 4 – 12
35 The sum of all the factors of 50 is
- 87
- 93
- 97
- 84
Option 2 – 93
36 The number of factors of 100 are
- 11
- 13
- 9
- 5
Option 3 – 9
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