These types of competitive mcqs appear in the exams like CSIR, NET, SET, FRO, JL, DL, APPSC, TSPSC, and other Competitive Examinations, etc. We created all the competitive exammcqs into several small posts on our website for your convenience.
You will get their respective links in the related posts section provided below.
According to the Edison effect, if a metal plate around the cathode is held at a positive potential relative to the cathode
a) Electrons emitted from the cathode will move to the plate, producing an electric current
b) Electrons will not be emitted
c) Electrons will reach the plate but no current will flow
d) None of the above
Explanation: This question explores the behavior of electrons emitted from a heated cathode when influenced by an external Electric Field created by a nearby positively charged plate. The phenomenon is based on thermionic emission, where electrons gain enough thermal energy to escape the metal surface.
In such a setup, the cathode emits electrons due to heating, and if a surrounding plate is maintained at a higher (positive) potential, it creates an Electric Field that attracts these free electrons. The movement of electrons under this Electric Field forms the basis of current flow in vacuum tubes. The direction and presence of current depend on whether emitted electrons are able to reach the positively charged plate.
Think of this like steam escaping from boiling water: once particles leave the surface, they can be guided by external forces. Here, instead of gravity or wind, the Electric Field guides the electrons. If conditions allow, a steady flow of electrons establishes an electric current between the cathode and the plate.
In summary, the interaction between thermionic emission and an applied positive potential determines whether electrons move toward the plate and contribute to current formation in the circuit.
Option a – Electrons emitted from the cathode will move to the plate, producing an electric current
The rectifier efficiencies for half-wave and full-wave rectifiers are
a) 40.6% and 81.2%
b) 35.6% and 71.4%
c) 39.8% and 76.9%
d) 30.6% and 61.2%
Explanation: This question focuses on how effectively rectifier circuits convert Alternating Current (AC) into direct current (DC). Efficiency in this context refers to the ratio of DC output power to the AC input power supplied to the circuit.
A half-wave rectifier allows only one half of the AC cycle to pass through, blocking the other half. As a result, a significant portion of the input energy is unused, leading to lower efficiency. In contrast, a full-wave rectifier utilizes both halves of the AC waveform by inverting one half, thereby making better use of the input signal and improving overall efficiency.
The difference arises because full-wave rectification produces a more continuous output with fewer gaps, reducing power loss. This is similar to collecting rainwater: using only one side of a sloped roof wastes potential collection, while using both sides increases efficiency significantly.
Thus, the design and operation of the rectifier directly influence how much of the input AC signal is effectively converted into useful DC output.
Option a – 40.6% and 81.2%
In an NPN transistor circuit, the collector current is 10 mA. If 95% of electrons reach the collector, the Base current is
a) 10.53 mA
b) 0.53 mA
c) 11.06 mA
d) None of the above
Explanation: This question examines current distribution in a transistor, particularly the relationship between emitter, Base, and collector currents. In an NPN transistor, most charge carriers injected from the emitter reach the collector, while a small fraction recombines in the Base region.
The collector current represents the majority of carriers, and the given percentage indicates how efficiently carriers are transferred from emitter to collector. The remaining percentage corresponds to carriers that do not reach the collector and instead contribute to Base current. The Base current is therefore a small portion of the total current flowing through the device.
Imagine a pipeline where most water flows straight through to the exit, while a small amount leaks through side openings. The leakage represents the Base current, and the main flow corresponds to the collector current. By comparing proportions, one can determine the relative magnitude of Base current.
In summary, understanding the fraction of carriers reaching the collector helps estimate how much current is diverted into the Base region in transistor operation.
Option b – 0.53 mA
How does the barrier potential of a P-N junction diode change with biasing?
a) Decreases with both reverse and forward bias
b) Increases with both reverse and forward bias
c) Increases with reverse bias and decreases with forward bias
d) Increases with forward bias and decreases with reverse bias
Explanation: This question deals with how external voltage affects the internal Electric Field at the junction of a P-N diode. The barrier potential is the built-in voltage that opposes the movement of charge carriers across the junction.
When a forward bias is applied, the external voltage reduces the barrier, making it easier for charge carriers to cross the junction. Conversely, when reverse bias is applied, the external voltage increases the barrier, strengthening the opposition to carrier movement. These changes directly influence current flow through the diode.
This can be compared to a hill between two valleys. Lowering the hill allows easier passage, while raising it makes crossing more difficult. Similarly, biasing modifies the effective height of the potential barrier.
In summary, the applied voltage either assists or opposes carrier movement by altering the barrier potential at the junction.
Option c – Increases with reverse bias and decreases with forward bias
Which filter circuit is suitable for high load current?
Explanation: This question focuses on filter circuits used in power supplies to smooth out fluctuations in rectified output. The suitability of a filter depends on how well it maintains voltage stability under varying load conditions, especially when large currents are drawn.
Different filter designs use inductors and Capacitors in various configurations. For high load currents, the filter must effectively reduce ripple while allowing sufficient current flow without significant voltage drop. Inductors are particularly useful in handling large currents because they oppose changes in current and help maintain continuity.
Consider a water system where a steady flow is required despite fluctuations at the source. A component that resists sudden changes in flow helps maintain consistency, similar to how certain filters stabilize electrical output.
In summary, the choice of filter depends on its ability to handle large currents while maintaining smooth and stable output voltage.
Option c – Series inductance filter
For intrinsic semiconductors, the number of electrons in the conduction band
a) Equals the number of holes in the valence band
b) Equals the number of filled positions in the valence band
c) Is less than the number of holes in the valence band
d) None of the above
Explanation: This question addresses the fundamental property of intrinsic semiconductors, which are pure materials without any added impurities. In such materials, charge carriers are generated purely due to thermal energy.
When energy is supplied, electrons jump from the valence band to the conduction band, leaving behind holes. Each electron that moves creates one hole, establishing a direct relationship between the number of free electrons and holes. This balance is a defining characteristic of intrinsic semiconductors.
This situation can be compared to pairs of objects: removing one item from a filled position creates both a free object and an empty spot. The number of free items always equals the number of empty spots created.
In summary, intrinsic semiconductors maintain an equal number of electrons and holes due to the nature of thermal generation of charge carriers.
Option a – Equals the number of holes in the valence band
An Atom that donates one electron to the conduction band of pure Germanium is called
Explanation: This question relates to doping in semiconductors, where impurity atoms are added to modify electrical properties. When an impurity Atom donates an extra electron, it increases the number of free charge carriers available for conduction.
Such atoms typically have more valence electrons than the host semiconductor atoms. When introduced into the lattice, one of their electrons becomes loosely bound and easily contributes to conduction. This process significantly enhances conductivity.
It is similar to adding extra workers to a system where each worker can move freely and contribute to productivity. The additional worker increases overall efficiency without disrupting the structure.
In summary, impurity atoms that contribute extra electrons play a crucial role in increasing conductivity by providing free charge carriers.
Which element produces an n-type extrinsic semiconductor when added to pure Ge?
a) Antimony
b) Cadmium
c) Gallium
d) Indium
Explanation: This question focuses on the formation of n-type semiconductors through doping. When specific impurity elements are added to a pure semiconductor like germanium, they introduce additional free electrons into the system.
These impurity atoms have more valence electrons than the semiconductor atoms. The extra electrons become available for conduction, making electrons the majority charge carriers. This significantly enhances electrical conductivity in the material.
Think of this like adding extra fuel to a system that runs on energy carriers. The more carriers available, the more efficiently the system operates. The key factor is the number of valence electrons in the impurity Atom.
In summary, selecting appropriate impurity elements determines whether the semiconductor becomes electron-rich and more conductive.
Option a – Antimony
At what temperature are the conduction band empty and the valence band fully occupied in semiconductors?
a) 300 K
b) 273 K
c) 0 K
d) 0°C
Explanation: This question examines the behavior of electrons in semiconductors at extremely low temperatures. The distribution of electrons between the valence and conduction bands depends on the thermal energy available.
At very low temperatures, electrons do not have sufficient energy to jump from the valence band to the conduction band. As a result, all electrons remain bound in the valence band, and the conduction band remains empty. This leads to zero electrical conductivity.
This can be compared to a frozen system where particles lack the energy to move. Without motion, no transfer or flow occurs, similar to the absence of current in this condition.
In summary, the absence of thermal energy prevents electron excitation, keeping the conduction band empty and the valence band fully occupied.
Option c – 0 K
Statements regarding semiconductors: 1. Semiconductors have a negative temperature coefficient of resistance 2. Phosphorus, sulfur, and chlorine are semiconductors 3. Their electrical conductivity is strongly affected by small amounts of impurities 4. None of the above. Codes:
a) Only (1) and (2)
b) Only (3)
c) Only (2) and (3)
d) None of the above
Explanation: This question evaluates multiple statements related to semiconductor properties. Semiconductors exhibit unique electrical behavior that differs from conductors and insulators, especially in response to temperature and impurities.
One important characteristic is that their resistance decreases with increasing temperature, meaning conductivity improves as more charge carriers are generated. Additionally, doping with impurities significantly alters conductivity by introducing extra electrons or holes. However, not all elements mentioned are semiconductors themselves; some act as dopants instead.
This is similar to adjusting a system’s performance by adding small but impactful components, rather than changing the entire structure. Small modifications can lead to large changes in output behavior.
In summary, understanding temperature dependence and impurity effects is essential for analyzing semiconductor properties and evaluating such statements.
Option a – Only (1) and (2)
Adding a P-type impurity to an intrinsic semiconductor results in
a) Decrease in free electron concentration below intrinsic value
b) Increase in the number of holes above intrinsic value
c) Decrease in the number of holes below intrinsic value
d) None of the above
Explanation: This question explores the effect of introducing acceptor impurities into a pure semiconductor. P-type doping involves adding elements with fewer valence electrons, which creates vacancies or “holes” in the crystal structure.
These holes act as positive charge carriers and play a major role in conduction. The introduction of such impurities changes the balance of charge carriers, making holes the dominant contributors to current flow. This alters the electrical properties significantly compared to the intrinsic state.
This can be visualized as creating empty seats in a system where movement occurs by shifting positions. The more empty spots available, the easier it is for movement to propagate through the system.
In summary, P-type doping modifies carrier concentration by increasing the role of holes, thereby changing the conduction mechanism of the semiconductor.
Option a – Decrease in free electron concentration below intrinsic value
We covered all the electronic mechanic mock test above in this post for free so that you can practice well for the exam.
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