S Chand Class 10 Chemistry Solutions. We covered all the S Chand Class 10 Chemistry Solutions in this post for free so that you can practice well for the exam.
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S Chand Class 10 Chemistry Objective with Solutions for Students
The major monochlorination product of isobutane is:
(A) 2-chloro-2-methylpropane
(B) 1-chloro-2-methylpropane
(C) 2-chlorobutane
(D) 2-chloropentane
Option a – 2-chloro-2-methylpropane
The yield of iodoalkane obtained from alcohols and HI is very low due to:
(A) R-I is reduced by HI in alkanes
(B) HI is less reactive
(C) The reactivity of alcohols with HI is low
(D) Alcohols are oxidized by HI
Option a – R-I is reduced by HI in alkanes
The order of reactivity of alcohols with a given HX is:
(A) 1° > 2° > 3°
(B) 3° > 2° > 1°
(C) 3° > 1° > 2°
(D) 1° > 3° > 2°
Option b – 3° > 2° > 1°
Which of the following haloalkanes are not obtained by halogenation of alkanes?
(A) Iodoalkane
(B) Bromoalkane
(C) Fluoroalkane
(D) Chloroalkane
Option c – Fluoroalkane
The number of monochlorination products obtained from 2-methyl butane is:
(A) Six
(B) Four
(C) Three
(D) Two
Option b – Four
We covered all the s chand class 10 chemistry solutions above in this post for free so that you can practice well for the exam.
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