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Solid State Previous Year Questions

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Solid State Previous Year Questions. We covered all the Solid State Previous Year Questions in this post for free so that you can practice well for the exam.

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Solid State Previous Year Objective Questions for Students

In the formation of a p-type semiconductor, impurity atoms are added to have a number of valence electrons

(A) 3

(B) 5

(C) 1

(D) 2

Option a – 3

In the formation of an n-type semiconductor, impurity atoms are added to have a number of valence electrons

(A) 3

(B) 5

(C) 1

(D) 2

Option b – 5

NaCl shows

(A) Frankel defect

(B) Schottky defect

(C) Interstitial defects

(D) Line defect

Option b – Schottky defect

An example of a substitual impurity defect is

(A) KCI

(B) ZnS

(C) Brass

(D) CgC

Option c – Brass

The size of tetrahedral voids formed by spheres as compared to octahedral voids formed is

(A) Equal

(B) Smaller

(C) Greater

(D) Indefinite

Option b – Smaller

In the BCC lattice structure, the radius of the sphere is 75 Pm. The edge length of the unit cell is

(A) 32.475 Pm

(B) 212.1 Pm

(C) 37.5 Pm

(D) 173.2 Pm

Option d – 173.2 Pm

Due to the Frenkel defect, the density of the ionic solid

(A) Increases

(B) Decreases

(C) Remains constant

(D) Fluctuates

Option c – Remains constant

When few cations moved from their positions into the interstitial sites in a crystalline solid, it is

(A) Interstitial defect

(B) Frenkel defect

(C) Schottky defect

(D) Line defects

Option a – Interstitial defect

The order of packing efficiency in different types of unit cells is

(A) FCC > BCC > Simple cubic

(B) FCC > BCC > Simple cubic

(C) FCC < BCC > Simple cubic

(D) BCC < FCC < Simple cubic

Option b – FCC > BCC > Simple cubic

In a closest-packed lattice, the number of tetrahedral voids formed will be

(A) Equal to the number of spheres in the lattice.

(B) Half of that of a number of spheres.

(C) Double that of a number of spheres.

(D) One-fourth of that of a number of spheres.

Option c – Double that of a number of spheres

If ‘R’ is the radius of the spheres in the CCP arrangement and ‘Y’ is the radius of the octahedral voids, then

(A) r= 0.414 R

(B) r = 0.224 R

(C) R = 0.414 r

(D) R = 0.224 r

Option b – r = 0.224 R

We covered all the solid state previous year questions above in this post for free so that you can practice well for the exam.

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