New Approach to ICSE Physics Class 10 Solutions. We covered all the New Approach to ICSE Physics Class 10 Solutions in this post for free so that you can practice well for the exam.
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New Approach to ICSE Physics Class 10 MCQs for Students
In Young’s experiment wavelength of light 5000Å is used. One of the slits is covered by a transparent sheet of thickness 18 µm, made of material with a refractive index of 1.5. The number of fringes shifted due to the introduction of the sheet are :
(A) 180
(B) 9
(C) 5
(D) 18
Option d – 18
Two slits separated by a distance of 1 mm are illumined by the light of wavelength 6500 A. The distance of the slit from the source is 1m. The distance between the fifth bright band and 3rd dark band on the same side of the central bright band is :
(A) 0.65 mm
(B) 2.65 mm
(C) 1.625 mm
(D) 3 mm
Option c – 1.625 mm
Monochromatic light from narrow parallel slits produces an interference pattern on a screen. The separation between the two slits is now doubled and the distance between the screen and slits is reduced to half, the fringe width:
(A) is doubled
(B) becomes 4 times
(C) becomes 1/4 times
(D) remains the same
Option c – becomes 1/4 times
What is the percentage change in fringe width if the distance between the slits in Young’s experiment is reduced by 10% and the distance between the slit and the screen is increased by 15% :
(A) 25.4%
(B) 27.7%
(C) 30%
(D) 33.5%
Option b – 27.7%
In Young’s double slit experiment, the fringe width is found to be 0.4 mm. If the whole apparatus is immersed in water of refractive index 4/3, without disturbing the geometrical arrangement, the new fringe width will be :
(A) 0.4 mm
(B) 0.35 mm
(C) 4/3 mm
(D) 0.3 mm
Option d – 0.3 mm
The distance of the 10th dark band from the center of the interference pattern is 11 mm. The bandwidth is :
(A) 19/22 mm
(B) 22/19 mm
(C) 2.2 mm
(D) 1.5 mm
Option d – 1.5 mm
In an interference pattern, the path difference between two waves interfering at the central point on the screen is :
(A) always zero
(B) less than zero
(C) greater than zero
(D) of any value
Option a – always zero
In an interference experiment, the separation between 2nd and 3rd dark fringe on a screen is 5 mm. The screen is at a distance of 1.5 m from the source. If the wavelength of light is 5000 A°, the separation between the two interfering sources is :
(A) 15 m
(B) 1.5 mm
(C) 0.15 mm
(D) 1.5 m
Option c – 0.15 mm
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